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These are the notes of Exercise of Calculus. Key important points are: Parabolas, Vertex, Focus, Directrix, Focal Width, Standard Form, Equation of the Parabola, Testname
Typology: Exercises
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Find the vertex, focus, directrix, and focal width of the parabola.
x2^ = y
A) Vertex: (0, 0); Focus: (0, - 10); Directrix: y = 10; Focal width: 40 B) Vertex: (0, 0); Focus: (-20, 0); Directrix: x = 10; Focal width: 160 C) Vertex: (0, 0); Focus: (0, 10); Directrix: y = -10; Focal width: 10 D) Vertex: (0, 0); Focus: (0, - 10); Directrix: y = 10; Focal width: 160
; Directrix: y = - 1 32
; Focal width: 32
B) Vertex: (0, 0); Focus: 1 32
, 0 ; Directrix: x = 1 32
; Focal width: 32
C) Vertex: (0, 0); Focus: 1 8
, 0 ; Directrix: x = - 1 8
; Focal width: 0.
D) Vertex: (0, 0); Focus: 1 32
, 0 ; Directrix: x = - 1 32
; Focal width: 0.
y2^ = 8x A) Vertex: (0, 0); Focus: (0, 2); Directrix: y = -2; Focal width: 2 B) Vertex: (0, 0); Focus: (2, 0); Directrix: x = -2; Focal width: 8 C) Vertex: (0, 0); Focus: (2, 0); Directrix: x = -2; Focal width: 32 D) Vertex: (0, 0); Focus: (2, 2); Directrix: x = 2; Focal width: 32
(y - 8)2^ = 16(x - 2) A) Vertex: (2, 8); Focus: (6, 8); Directrix: x = -2; Focal width: 16 B) Vertex: (8, 2); Focus: (8, 18; Directrix: y = -14; Focal width: 16 C) Vertex: (2, 8); Focus: (18, 8); Directrix: x = -14; Focal width: 16 D) Vertex: (8, 2); Focus: (8, 6); Directrix: y = -2; Focal width: 4
(x - 8)2^ = 16(y - 6) A) Vertex: (6, 8); Focus: (10, 8); Directrix: x = 4; Focal width: 4 B) Vertex: (6, 8); Focus: (22, 8); Directrix: x = -8; Focal width: 16 C) Vertex: (8, 6); Focus: (8, 10); Directrix: y = 2; Focal width: 16 D) Vertex: (-8, - 6); Focus: (-8, 10); Directrix: y = -22; Focal width: 16
Find the standard form of the equation of the parabola.
x2^ B) y2^ = 36x C) y2^ = 9x D) y = 1 36
x
x2^ C) y = 1 16
x2^ D) y2^ = 16x
y2^ C) y = 1 8
x2^ D) x2^ = 8y
y2^ B) - 8y = x2^ C) y2^ = - 8x D) y = - 1 8
x
Focus at (-3, 2), directrix x = - 11 A) (y - 2)2^ = 16(x + 3) B) (x + 3)2^ = 16(y - 2) C) (x - 2)2^ = 16(y + 7) D) (y - 2)2^ = 16(x + 7)
Focus at (6, - 2), directrix y = - 8 A) (y + 2)2^ = 12(x - 6) B) (x - 6)2^ = 12(y + 2) C) (x - 6)2^ = 12(y + 5) D) (x + 2)2^ = 12(y + 5)
Vertex at the origin, opens to the right, focal width = 14 A) y2^ = 14x B) y2^ = - 14x C) x2^ = 14y D) y2^ = 3.5x
Graph the parabola.
-10 -5 5 10 x
y 10
5
-10 -5 5 10 x
y 10
5
(x + 4)2^ - 3
-10 -5 5 10 x
y 10
5
-10 -5 5 10 x
y 10
5
-10 -5 5 10 x
y 10
5
-10 -5 5 10 x
y 10
5
Find the vertex, the focus, and the directrix of the parabola.
; Focus: (-1, 3); Directrix: y = - 41 8
; Focus: 5, 23 12
; Directrix: x = 25 12
B) Vertex: 5, 2 ; Focus: 5, 25 12
; Directrix: y = 23 12
C) Vertex: 5, 5 ; Focus: (5, 5); Directrix: x = - 1 D) Vertex: 5, 19 2
; Focus: (5, 14); Directrix: x = 10
C) Vertex: - 4, 3 ; Focus: 98 , 3 ; Directrix: y = 78 D) Vertex: 1, 3 ; Focus: (3, 3); Directrix: x = - 1
-10 -5 5 10 x
y 10
5
-10 -5 5 10 x
y 10
5
-10 -5 5 10 x
y 10
5
-10 -5 5 10 x
y 10
5
-10 -5 5 10 x
y 10
5
-10 -5 5 10 x
y 10
5