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An overview of partial differential equations (pdes), their applications in mathematics and sciences, and an introduction to an introductory university course, math 112, on the subject. Pdes are equations involving derivatives of functions with respect to multiple variables and come up in various fields such as physics, engineering, and mathematics. The importance of calculus and linear algebra as prerequisites for the course, the difficulty level of pdes, and the focus on the laplace equation, diffusion equation, and wave equation in the course.
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Math 112 – Partial Differential Equations
Partial Differential Equations (PDEs for short) come up in most parts of mathematics and in most sciences. For instance, complex analysis is the study of the Cauchy-Riemann equations
ux = vy , uy = −vx. (1)
Another example is the recent resolution of the celebrated Poincar´e conjec- ture in topology, which uses diffusion-type PDEs to analyze the singularities of surfaces. Brownian motion is a random process that is described by a PDE. Other examples of PDEs occur in the flow of fluids, diffusion of chemicals, conduction of neural impulses along an axon, radiation of electromagnetic waves, quantum mechanics, spread of heat, propagation of sound, spread of epidemics, etc. PDE is a vast subject. Math 112 is an introductory course in the subject. All you really have to know is calculus and linear algebra. The key prerequisite is several-variable calculus. However, it is not one of the easier 100-level courses, so it is recom- mended (but not required) that you take at least one other 100-level course before taking Math 112. Very good preparatory courses would be Math 101 (Introduction to Analysis), 126 (Complex Analysis), 113 (Real Analysis) or 111 (Ordinary Differential Equations). Math 111 is not a prerequisite. A few PDEs are really easy to solve, such as
ut + ux = 0, (2)
which has the general solution u(x, t) = f (x − t) for any function f of one variable. But most of them are difficult or notoriously difficult or impos- sible to solve.∫ (It’s something like indefinite integrals, most of which, like exp(x^2 ) dx, do not have explicit solutions.) In Math 112 we will study the most important equations that are in the easy-to-difficult category. The notoriously difficult ones are subjects of current mathematical research or computational experimentation. Most of the ones studied in this course have explicit solutions in the form of fairly complicated formulas involving integrals or infinite series. Just about all PDEs have infinitely many solutions, often an infinite-dimensional space of solutions, as in the very simple example above. After a while, one realizes that one has to rethink what one means by “solving” a PDE. Many PDEs have no solution formula at all. Instead, one has to find properties of the solutions.
A PDE like ut + ux = 0 has order one because it involves only first derivatives. The PDE ut = uxx has order two because there is a second derivative, etc. After a very short introduction to first-order PDEs, the focus of the course rests on the three most fundamental PDEs of order two:
uxx + uyy = 0, ut = uxx and utt = uxx. (3)
These are called the Laplace equation, the diffusion (or heat) equation and the wave equation, respectively. There are also the higher-dimensional ver- sions of them, namely:
∆u = uxx + uyy + uzz = 0, ut = ∆u and utt = ∆u (4)
in three spatial dimensions. Each of these three basic equations has its own “personality”. These equations are linear, and therefore the space of solutions is a vector space! So the concepts of linear algebra come into play, particularly the concepts of eigenvector and orthogonality. There are an infinite number of solutions, so ... how do we pick out any particular one? Here’s the standard way. For the diffusion or wave equations we impose initial conditions, which specify the solution at t = 0. In the space variables, we take a domain D and specify boundary conditions on its boundary. For instance, for the diffusion equation ut = uxx, we could take the in- terval 0 ≤ x ≤ 1 and look for a solution which vanishes at both endpoints x = 0, 1. With the initial condition u(x, 0) = φ(x), this problem (with these extra conditions)
ut = uxx , u(x, 0) = φ(x) , u(0, t) = u(1, t) = 0 (5)
has a unique solution! It turns out to be given by the complicated formula
u(x, t) =
n=
an e−n
(^2) π (^2) t sin(nπx). (6)
How in blazes to we get to this? Well, take the course and you’ll find out. Put t = 0 in the formula and we see that
φ(x) =
n=
an sin(nπx). (7)