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The solutions to test 1 of math 554/703i - analysis i. It covers topics such as real number axioms, upper and least upper bounds, multiplicative inverses, and the archimedean principle. Students are guided through the proofs of various mathematical statements.
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[See course lecture notes.]
[Suppose that α, β are both least upper bounds for A. Since α is an upper bound for A, and β is a least upper bound of A, then β ≤ α. By symmetry, α ≤ β]
[See course lecture notes: But use the fact that additive inverses are unique and observe that a + ((−1)(a)) = a(1 + (−1)) = a · 0 = 0.]
[If α, β are both a multiplicative inverse of an element a, then α = α1 = α(aβ) = (αa)β = β. ]
[Use the previous part, i.e. multiplicative inverses are unique, and observe that (ab)(a−^1 b−^1 ) = (aa−^1 )(bb−^1 ) = 1. ]
[Use 0 < x and multiply x < y to get x^2 < xy. Use 0 < y and multiply x < y to get xy < y^2. Using the transitive property, gives x^2 < y^2 .]
[There exists ǫ > 0 such that for each natural number N there exists a pair x, y ∈ [0, 1] which satisfies |x − y| < 1 /N , but |f (x) − f (y)| ≥ ǫ.]
[See course lecture notes.]
[See course lecture notes.]
[Use the Archimedean Principle to find a natural number N so that
< ǫ. Notice that if n ≥ N , then N ≤ n · 1 ≤ n · n and so (^) n^12 ≤ (^) n^1 ≤ (^) N^1 < ǫ]
[See course lecture notes.]
[|a + b| ≤ |a| + |b|]
[Represent (x − 2) as (x − 3) + 1 and apply the triangle inequality: |x − 2 | ≤ |x − 3 | + 1 ≤ 1 + 1 = 2.]