Solutions to Math 554/703I - Analysis I Test 1 - Prof. R. Sharpley, Exams of Mathematics

The solutions to test 1 of math 554/703i - analysis i. It covers topics such as real number axioms, upper and least upper bounds, multiplicative inverses, and the archimedean principle. Students are guided through the proofs of various mathematical statements.

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Pre 2010

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Math 554/703I - Analysis I
Test 1 - Solutions
1. List the axioms for the real numbers.
[See course lecture notes.]
2. Let Abe an nonempty subset of IR.
a.) Define ‘upper bound’ for A.
b.) Define ‘least upper bound’ for A.
c.) Prove that least upper bounds are unique.
[Suppose that α, β are both least upper bounds for A. Since αis an upper bound for A, and βis a
least upper bound of A, then βα. By symmetry, αβ]
3. Prove for each aIR, (a) = (1) ·a.
[See course lecture notes: But use the fact that additive inverses are unique and observe that
a+ ((1)(a)) = a(1 + (1)) = a·0 = 0.]
4. Suppose that IR is an ordered field, prove
a) Multiplicative inverses are unique.
[If α, β are both a multiplicative inverse of an element a, then α=α1 = α() = (αa)β=β. ]
b) (ab)1=a1b1
[Use the previous part, i.e. multiplicative inverses are unique, and observe that
(ab)(a1b1) = (aa1)(bb1) = 1. ]
c) If 0 < x < y, then x2< y2.
[Use 0 < x and multiply x < y to get x2< xy. Use 0 < y and multiply x < y to get xy < y2. Using
the transitive property, gives x2< y2.]
5. Negate the statement:
‘For each ǫ > 0 there exists a natural number Nsuch that for every pair x, y [0,1]
which satisfies |xy|<1/N , then |f(x)f(y)|< ǫ.’
[There exists ǫ > 0 such that for each natural number Nthere exists a pair x, y [0,1] which
satisfies |xy|<1/N, but |f(x)f(y)| ǫ.]
6. a) Prove that the natural numbers are not bounded.
[See course lecture notes.]
b) State and prove the Archimedean principle.
[See course lecture notes.]
c) Prove that for each ǫ > 0, there exists a natural number Nsuch that for all Nn
there holds 1
n2< ǫ.
[Use the Archimedean Principle to find a natural number Nso that 1
N< ǫ. Notice that if nN,
then Nn·1n·nand so 1
n21
n1
N< ǫ]
7. Pick one: Sketch the proof that every open interval (a, b), where a < b, contains a rational
(irrational) number.
[See course lecture notes.]
8. a) State the triangle inequality for the real numbers.
[|a+b| |a|+|b|]
pf2

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Math 554/703I - Analysis I

Test 1 - Solutions

1. List the axioms for the real numbers.

[See course lecture notes.]

2. Let A be an nonempty subset of IR.

a.) Define ‘upper bound’ for A.

b.) Define ‘least upper bound’ for A.

c.) Prove that least upper bounds are unique.

[Suppose that α, β are both least upper bounds for A. Since α is an upper bound for A, and β is a least upper bound of A, then β ≤ α. By symmetry, α ≤ β]

3. Prove for each a ∈ IR, (−a) = (−1) · a.

[See course lecture notes: But use the fact that additive inverses are unique and observe that a + ((−1)(a)) = a(1 + (−1)) = a · 0 = 0.]

4. Suppose that IR is an ordered field, prove

a) Multiplicative inverses are unique.

[If α, β are both a multiplicative inverse of an element a, then α = α1 = α(aβ) = (αa)β = β. ]

b) (ab)−^1 = a−^1 b−^1

[Use the previous part, i.e. multiplicative inverses are unique, and observe that (ab)(a−^1 b−^1 ) = (aa−^1 )(bb−^1 ) = 1. ]

c) If 0 < x < y, then x^2 < y^2.

[Use 0 < x and multiply x < y to get x^2 < xy. Use 0 < y and multiply x < y to get xy < y^2. Using the transitive property, gives x^2 < y^2 .]

5. Negate the statement:

‘For each ǫ > 0 there exists a natural number N such that for every pair x, y ∈ [0, 1]

which satisfies |x − y| < 1 /N, then |f (x) − f (y)| < ǫ.’

[There exists ǫ > 0 such that for each natural number N there exists a pair x, y ∈ [0, 1] which satisfies |x − y| < 1 /N , but |f (x) − f (y)| ≥ ǫ.]

6. a) Prove that the natural numbers are not bounded.

[See course lecture notes.]

b) State and prove the Archimedean principle.

[See course lecture notes.]

c) Prove that for each ǫ > 0, there exists a natural number N such that for all N ≤ n

there holds

n^2

[Use the Archimedean Principle to find a natural number N so that

N

< ǫ. Notice that if n ≥ N , then N ≤ n · 1 ≤ n · n and so (^) n^12 ≤ (^) n^1 ≤ (^) N^1 < ǫ]

7. Pick one: Sketch the proof that every open interval (a, b), where a < b, contains a rational

(irrational) number.

[See course lecture notes.]

8. a) State the triangle inequality for the real numbers.

[|a + b| ≤ |a| + |b|]

b) If |x − 3 | < δ ≤ 1, then prove that |x − 2 | < 2.

[Represent (x − 2) as (x − 3) + 1 and apply the triangle inequality: |x − 2 | ≤ |x − 3 | + 1 ≤ 1 + 1 = 2.]

Extra Credit: If |x − 3 | < δ ≤ 1, then prove that |(x^2 − 5 x + 7) − (1)| < 2 δ.

[ |(x^2 − 5 x + 7) − (1)| = |x^2 − 5 x + 6| = |(x − 3)(x − 2)| = |(x − 3)| · |(x − 2)| ≤ δ · 2. ]