Stoichiometry Review: Percent Yield and Theoretical Yield, Lecture notes of Stoichiometry

A review on the concepts of theoretical yield and percent yield in the context of stoichiometry. It includes definitions, formulas, and an example calculation for finding percent yield.

Typology: Lecture notes

2021/2022

Uploaded on 08/05/2022

aichlinn
aichlinn ๐Ÿ‡ฎ๐Ÿ‡ช

4.4

(46)

1.9K documents

1 / 2

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Jocelyn M.
Melissa R.
Stoichiometry Review
Percent Yield and Theoretical Yield๎˜ƒ
Q: What is theoretical yield?
A: Theoretical yield is the maximum amount of product that can be
obtained in a chemical reaction. It is calculated from the limiting reactant.
______________________________________________________________________
Q: What is percent yield?
A: Percent yield is the amount of product that could possibly be produced
in a given reaction. It is a ratio of the actual yield and the theoretical
yield multiplied by 100 to get a percent.
______________________________________________________________________
Q: How do you find percent yield?
A: To find percent yield, you have to use the following formula:
% yield = ๎˜ actual yield ๎˜ x 100
theoretical yield
______________________________________________________________________
Example #1: If 16.0 g of CaCO๎˜
3๎˜
are decomposed and 7.54 g of CaO are
obtained, what is the percent yield of CaO obtained? CaCO๎˜
3๎˜
โ†’ CaO +
CO๎˜
2
1. Balance chemical equation. Because our equation is already
balanced, we move on to the second step.
2. We will need to convert the reactants and products and we can
only do that when we are starting with moles. So we make a
dimensional analysis table starting with what we know and going
straight to moles. We continue to finish the table.
16.0 g CaCO๎˜
3
1 mol CaCO๎˜
3
1 mol CaO
56.1 g CaO
100.1 g CaCO๎˜
3
1 mol
CaCO๎˜
3
1 mol CaO
= 8.97 g CaO
3. Always bring down diagonally your unit.
16.0 g CaCO๎˜
3
1 mol CaCO๎˜
3
1 mol CaO
56.1 g CaO
100.1 g CaCO๎˜
3
1 mol
CaCO๎˜
3
1 mol CaO
1๎˜ƒ
pf2

Partial preview of the text

Download Stoichiometry Review: Percent Yield and Theoretical Yield and more Lecture notes Stoichiometry in PDF only on Docsity!

Jocelyn M. Melissa R. Stoichiometry Review

Percent Yield and Theoretical Yield

Q: What is theoretical yield? A: Theoretical yield is the maximum amount of product that can be obtained in a chemical reaction. It is calculated from the limiting reactant.


Q: What is percent yield? A: Percent yield is the amount of product that could possibly be produced in a given reaction. It is a ratio of the actual yield and the theoretical yield multiplied by 100 to get a percent.


Q: How do you find percent yield? A: To find percent yield, you have to use the following formula: % yield = actual yield x 100 theoretical yield


Example #1: If 16.0 g of CaCO 3 are decomposed and 7.54 g of CaO are obtained, what is the percent yield of CaO obtained? CaCO 3 โ†’ CaO + CO 2

  1. Balance chemical equation. Because our equation is already balanced, we move on to the second step.
  2. We will need to convert the reactants and products and we can only do that when we are starting with moles. So we make a dimensional analysis table starting with what we know and going straight to moles. We continue to finish the table. 16.0 g CaCO 3 1 mol CaCO 3 1 mol CaO 56.1 g CaO

100.1 g CaCO 3 1 mol CaCO 3

1 mol CaO

= 8.97 g CaO

  1. Always bring down diagonally your unit. 16.0 g CaCO 3 1 mol CaCO 3 1 mol CaO 56.1 g CaO

100.1 g CaCO 3 1 mol CaCO 3

1 mol CaO

1

Jocelyn M. Melissa R. Stoichiometry Review

  1. Multiply all the top numbers. Divide your answer by all the bottom numbers. 16.0 x 1 x1 x 56.1 = 897. 897.6 / 100.1 = 8.
  2. Our theoretical yield is 8.97 g CaO
  3. To find our percent yield we use this formula: % yield = actual yield x 100 theoretical yield
  4. The actual yield, we cannot calculate. The actual yield should always be given to us. In this problem, our actual yield is 7. % yield = 7.54 x 100 = 84.4%
  5. Our percent yield is 84.4%

2