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Eigenvalues and Eigenvectors
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Oxford University Mathematical Institute
Linear Algebra II for Mathematical Moderations Lecture 5 (Tuesday 1 February 2011): Eigenvalues and eigenvectors
The theory of eigenvalues and eigenvectors (to be defined shortly) applies equally to square matrices and to endomorphisms of a finite-dimensional vector space V. But we will, in fact, concentrate on matrices in the first instance.
Recall that the following three properties of an n × n matrix A are equivalent:
(1) A is singular (in the sense that detA = 0); (2) A is not invertible; (3) there exists a non-zero column vector v = (x 1 , x 2 ,... , xn)tr^ such that Av = 0.
Now we come to the main subject of the next few lectures.
Definition. Let A ∈ Mn×n(R). The scalar λ ∈ R is said to be an eigenvalue of A if there exists a non-zero column vector v = (x 1 , x 2 ,... , xn)tr^ ∈ Rn^ such that
Av = λ v. The non-zero column vector v = (x 1 , x 2 ,... , xn)tr^ ∈ Rn^ is said to be an eigenvector of A if there exists a scalar λ ∈ R such that Av = λ v.
Similarly, for an endomorphism T : V → V of a finite-dimensional real vector space, the scalar λ ∈ R is said to be an eigenvalue of T if there exists v ∈ V \ { 0 } such that T v = λ v ; and the non-zero vector v ∈ V is said to be an eigenvector of T if there exists a scalar λ ∈ R such that T v = λ v.
Examples.
Theorem. If A ∈ Mn×n(R) and λ ∈ R then λ is an eigenvalue of A if and only if det(λIn − A) = 0.
Proof.
Definition. For an n×n matrix A the characteristic polynomial is defined by
χA(x) := det(xIn − A).
Thus λ is an eigenvalue of A if and only if χA(λ) = 0.
Recall: n × n matrices A, B are said to be similar if there exists an invertible n × n matrix P such that B = P −^1 AP.
Theorem. If A, B ∈ Mn×n(R) are similar then χA(x) = χB (x) and so A and B have the same eigenvalues.
Proof.
Probable end of Lecture 5