Permutations - Finite Math - Lecture Notes - M118, Study notes of Mathematics

Topics: Permutations of indistinguishable and/or distinguishable objects

Typology: Study notes

2011/2012

Uploaded on 10/01/2012

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Permutations - Finite Math - Lecture Notes - M118
Permutations
Permutations of k objects selected from n: assuming order matters, the number of ways n! to
select, without replacement, k objects from n is:
p(n,k) = (n-k)!
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Examples:
In a class of 25 students, how many ways can one choose 4 students to win different prizes of $1,
$2, $3, and $4, if……
A) A student cannot be a repeat winner?
P = 25!/254!
P = 303,600
B) Repeat winners are allowed?
254 = 390625
The Greek alphabet consists of 24 letters. How many three letter combinations are possible if….
A) Each letter can be used more than once?
243 = 13824
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Permutations of indistinguishable objects
Consider the word: dog. How many distinguishable ways can the letters be arranged to form a
new 3 letter word?
3P3 = 6
Consider the word: bee. How many distinguishable ways can the letters be arranged to form a
new 3 letter word?
3P3 = 6
FORMULA: The number of distinguishable arranged of nobjects is:
n!/(n1! * n2! *…..nk)
Examples:
pf2

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Permutations - Finite Math - Lecture Notes - M

Permutations

Permutations of k objects selected from n : assuming order matters, the number of ways n! to select, without replacement, k objects from n is:

p( n,k ) = ( n-k )!

Examples:

In a class of 25 students, how many ways can one choose 4 students to win different prizes of $1, $2, $3, and $4, if……

A) A student cannot be a repeat winner?

P = 25!/254! P = 303,

B) Repeat winners are allowed?

254 = 390625

The Greek alphabet consists of 24 letters. How many three letter combinations are possible if….

A) Each letter can be used more than once?

243 = 13824

Permutations of indistinguishable objects

Consider the word: dog. How many distinguishable ways can the letters be arranged to form a new 3 letter word?

3 P 3 = 6

Consider the word: bee. How many distinguishable ways can the letters be arranged to form a new 3 letter word?

3 P 3 = 6

FORMULA: The number of distinguishable arranged of n objects is:

n !/(n1! * n2! *…..nk)

Examples:

Beattle:

Noon:

IUPUI:

Infinite:

Mississippi:

How many different ways can thirteen gifts be distributed among three children if the oldest must receive three, the middle must receive four, and the youngest must receive six of the gifts?