Finding Interest Rate & Time with Compounded Interest, Quizzes of Philosophy

A math activity sheet from the Balagtas National Agricultural High School in the Philippines, focusing on the topic of compounding interest when it is compounded more than once a year. objectives, procedures, examples, and activities for students to understand and apply the concepts of compounding interest, frequency of conversion, nominal rate, and maturity value. The students are expected to learn how to find the future value, present value, and interest rate when compounding more than once a year.

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2021/2022

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Republic of the Philippines
Department of Education
Region III
Schools Division Office of Bulacan
Balagtas National Agricultural High School
Pulong Gubat, Balagtas, Bulacan
GENERAL MATHEMATICS
Quarter 2
Week 3-4
COMPOUNDING MORE THAN ONCE A
YEAR and FINDING THE INTEREST RATE
AND TIME
ACTIVITY
SHEET
NAME: __________________________________
GRADE AND SECTION: __________________________________
DATE OF SUBMISSION: __________________________________
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Republic of the Philippines Department of Education Region III Schools Division Office of Bulacan Balagtas National Agricultural High School Pulong Gubat, Balagtas, Bulacan

GENERAL MATHEMATICS

Quarter 2

Week 3-

COMPOUNDING MORE THAN ONCE A

YEAR and FINDING THE INTEREST RATE

AND TIME

ACTIVITY

SHEET

NAME: __________________________________

GRADE AND SECTION: __________________________________

DATE OF SUBMISSION: __________________________________

I. OBJECTIVES

A. Content Standards The learners demonstrate an understanding of key concepts of simple and compound interests. B. Performance Standards: The learner can investigate, analyze, and solve problems involving simple and compound interests. C. MELCs: a. computes interest, maturity value, future value, and present value in simple interest and compound interest environment. (M11GM-IIa-b-1) b. solves problems involving simple and compound interests. (M11GM- IIb-2) D. Specific Objectives:

  1. Finding compound interest (compounding more than once a year)
  2. Finding maturity value, interest, and present value when compounding more than once a year.
  3. Finding the interest rate and time in compound interest.

II. CONTENT

Lesson 3: Compounding More Than Once A Year

III. PROCEDURES:

A. Preliminary Activities

1. Pre-Test Multiple Choice: Read each question carefully, and then choose the letter of the correct answer that best fits the question below. (10 points)

  1. When money is compounded monthly, the frequency of conversion is _____? a. 1 b. 2 c. 4 d. 12
  2. When the annual interest rate is 16% compounded quarterly the interest rate in a conversion period is _____? a. 4% b. .004% c. .04% d. 40%
  3. If the interest rate per conversion period is 1% and money is compounded monthly, the nominal rate is _____? a. 0.012% b. 12% c. 1.2% d. 0.12%
  4. When the term is 3 years and 6 months and money is compounded semi- annually, the total number of conversion period is ____? a. 1 b. 3 c. 5 d. 7
  5. When the total number of conversion periods is 12 and the term is 6 years, then money is compounded _________? a. Annually c. Semi - annually b. Monthly d. Daily

3. ABSTRACTION

LESSON 3

COMPOUNDING MORE THAN ONCE A YEAR

Remember that in solving for the compound interest, the interest of the preceding year is added to the principal to the succeeding year and its is earning more interest compared to simple interest. This lesson will show you another method on how to earn interest better than the usual compound interest and that is compounding more than once a year.

But first, letโ€™s define some new terms.

  • Conversion or interest period โ€“ time between successive conversion of interest.
  • Frequency of conversion ( m ) โ€“ number of conversion periods in one year.
  • Nominal rate ( i(m)^ ) โ€“ annual rate of interest.
  • Rate ( j ) of interest for each conversion period.
  • Total number of conversion periods ( n ) n = tm = ( frequency of conversion ) x ( time in years )

Maturity Value, Compounding m times a year

๐น๐น = ๐‘ƒ๐‘ƒ(1 + ๐‘—๐‘—)๐‘ก๐‘ก^ or ๐น๐น = ๐‘ƒ๐‘ƒ (1 +

๐‘–๐‘– ๐‘š๐‘š ๐‘š๐‘š )

๐‘š๐‘š๐‘ก๐‘ก

Where: F = maturity value P = principal j = ๐‘–๐‘–

๐‘š๐‘š ๐‘š๐‘š ; t = mt

im^ = nominal rate of interest (annual rate) m = frequency of conversion t = term/time in year

EXAMPLE 1. Find the maturity value and interest if Php 10,000 is deposited in a bank at 2 % compounded quarterly for 5 years.

Solution. Given: P = 10,000; i (4)^ = 0.02; t = 5 years; m = 4 Find: (a) F; (b) P Compute for the interest rate in a conversion period by

Compute for the total number of conversion periods given by

Compute for the maturity value using

Answer: The compound interest is given by

EXAMPLE 2. Find the maturity value and interest if Php 10,000 is deposited in a bank at 2 % compounded monthly for 5 years.

Solution. Given: P = 10,000; i (12)^ = 0.02; t = 5 years; m = 12 Find: (a) F; (b) P Compute for the interest rate in a conversion period by

Compute for the total number of conversion periods given by

Compute for the maturity value using

Answer: The compound interest is given by

and the total number of conversion periods is

The present value can be computed by substituting these values in the formula.

Thus,

Answer. The present value is P19,529.

FINDING THE INTEREST RATE AND TIME IN COMPOUND INTEREST

EXAMPLE 1. How long will it take P3,000 to accumulate to P3,500 in a bank savings account at 0.25% compounded monthly?

Solution.

Given: P = 3,000; F = 3,500; i(12)^ = 0.0025; m = 12; j = ๐‘–๐‘–

( 12 ) 12 =^

  1. 0025 12 Find: t

Substituting the given values in the maturity value formula F = P(1 + j)n^ results to

To solve for n, take the logarithm of both sides.

Thus, payments should be made for 740 months or ๐‘ก๐‘ก = (^) ๐‘š๐‘š๐‘›๐‘› = 74012 = 61.

years.

EXAMPLE 2. How long will it take P1,000 to earn P300 if the interest is 12% compounded semi-annually?

Solution.

Given: F = 1,300; m = 2; i (2)^ = 0.12; j = ๐‘–๐‘–

( 2 ) 2 =^

  1. 12 2 = 0. Find: n and t

Because interest is earned only at the end of the period, then 5 six-month periods are needed so that the interest can reach P300. Thus, n = 5 and ๐‘ก๐‘ก = ๐‘›๐‘› ๐‘š๐‘š =^

5 2 = 2.5^ years. It will take 2.5 years for P1,000 to earn P300.

EXAMPLE 3. At what nominal rate compounded semi-annually wil P10, accumulate to P15,000 in 10 years?

Solution. Given: F = 15,000; P = 10,000; t = 10; m = 2; n = mt = (2)(10) = 20 Find: i(2)

The interest rate per conversion period is 2.05% The nominal rate (annual rate of interest) can be computed by

ACTIVITY 3: FINDING INTEREST RATE

(Write your answers and solutions on a separate sheet.) A. Complete the table by computing the interest rate per period and the total number of conversion periods.

Nominal Rate i (m)

Interest compounded

Frequency of conversion (m)

Interest rate per conversion peiod 12% Semi-annually (1) (2) 16% Quarterly (3) (4) 9% Monthly (5) (6) 10.95% Daily (7) (8)

ACTIVITY 4: COMPOUNDING MORE THAN ONCE A YEAR

A. Solve the following problem.

  1. Accumulate P15,000 for 2 years at 15% compounded monthly.
  2. How much should Kaye set aside and invest in a fund earning 2% compounded quarterly if she needs P75,000 in 15 months?

B. Find the unknown.

  1. F = 2,000; P = 1,750; m = 2; t = 4 years; j = ?; i(m) =?
  2. F = 30,000; P = 10,000; i(m) = 16% compounded quarterly; j= ?;