physical math and form, Study notes of Physiotherapy

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Typology: Study notes

2021/2022

Uploaded on 05/06/2023

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Bài tập phương trình vi phân
Giải các phương trình sau;
1/
tan2xsin2ydx +cos2xcot2ydy=0
2/
y¿+sin
(
x+y
)
=sin
(
xy
)
3/
y¿sinx=ylny , y¿x=π
2
=1¿
4/
y¿=1
xy+1
5/
y¿=(8x+y+1)2
6/
(
2x+3y1
)
dx+
(
4x+6y5
)
dy=0
7/
y¿ysinx=sinxcosx
8/
9/
x
(
1+x2
)
y¿
(
x21
)
y+2x=0
10/
y¿y
xlnx =xlnx , y¿x=e=e2
2¿
11/
x y¿y=x2lnx
12/
ydx +
(
xy +x
)
dy=0
13/
y¿y=exsinx
14/
x y¿y=3x2cos 3 x
15/
x y¿y=2x2sin 5 x

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Bài tập phương trình vi phân

Giải các phương trình sau;

1/ tan

2 x sin 2 ydx +cos 2 x cot 2 ydy = 0

2/ y

¿ +sin( x + y )=sin ( xy )

y ¿ sinx = ylny , y ∨¿ x = π 2

4/ y

¿

xy

5/ y

¿ =( 8 x + y + 1 ) 2

6/ (^2 x +^3 y^ −^1 )^ dx +(^4 x +^6 y −^5 )^ dy =^0

7/ y

¿ − ysinx = sinxcosx

8/ 2 x^ (^ x −^1 )^ y

¿ +( 2 x − 1 ) y + 1 = 0

9/ x (^1 + x

y ¿

−(^ x

2

− 1 )^ y + 2 x = 0

10/ y

¿ − y xlnx = xlnx , y ∨¿ x = e = e 2 2

11/ x y ¿− y = x^2 lnx

12/ ydx^ +(^ xy^ +^ x^ )^ dy =^0

13/ y

¿ − y = e x sinx

14/ x y ¿− y = 3 x^2 cos 3 x

15/ x y

¿ − y = 2 x 2 sin 5 x