Physics 218 formula sheet, Cheat Sheet of Physics

Formula sheet in given trigonometry and vectors, quadratics, derivatives, integrals, kinematics, circular motion, relative velocity, forces, energy and momentums.

Typology: Cheat Sheet

2021/2022

Uploaded on 02/07/2022

rothmans
rothmans 🇺🇸

4.7

(20)

249 documents

1 / 2

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Trigonometry and Vectors:
sin 30= cos 60=1
2sin 36.9cos 53.13
5
sin 45= cos 45=1
2sin 53.1cos 36.94
5
sin 60= cos 30=3
2
hadj =hcos θ=hsin φ
hopp =hsin θ=hcos φ
h2=h2
adj +h2
opp
tan θ=hopp
hadj
hhopp
φ
θ
hadj
Law of cosines: C2=A2+B22AB cos γ
Law of sines: sin α
A=sin β
B=sin γ
C
B
γ
α
C
A
β
~
A=Axˆ
i+Ayˆ
j+Azˆ
kˆ
A=~
A
|~
A|
~
A·~
B=AxBx+AyBy+AzBz=AB cos θ=AkB=ABk
~
A×~
B= (AyBzAzBy)ˆ
i+ (AzBxAxBz)ˆ
j+ (AxByAyBx)ˆ
k
|~
A×~
B|=AB sin θ=AB=AB(direction via right-hand rule)
Quadratic:
ax2+bx +c= 0 x1,2=b±b24ac
2a
Derivatives: d
dt (atn) = natn1
d
dt sin at =acos at
d
dt cos at =asin at
Integrals: Rt2
t1f(t)dt =a
n+1 (tn+1
2tn+1
1)
if f(t) = atn, then (Rf(t)dt =a
n+1 tn+1 +C
(n6=1)
Rsin at dt =1
acos at
Rcos at dt =1
asin at
Kinematics:
translational rotational
h~vi=~r2~r1
t2t1~v =d~r
dt
h~ai=~v2~v1
t2t1~a =d~v
dt =d2~r
dt2
~r(t) = ~r0+Rt
0~v(t)dt
~v(t) = ~v0+Rt
0~a(t)dt
hωi=θ2θ1
t2t1ω=
dt
hαi=ω2ω1
t2t1α=
dt =d2θ
dt2
θ(t) = θ0+Rt
0ω(t)dt
ω(t) = ω0+Rt
0α(t)dt
—– constant (linear/angular) acceleration only —–
~r(t) = ~r0+~v0t+1
2~at2
~v(t) = ~v0+~at
v2
x=v2
x,0+ 2ax(xx0)
(and similarly for yand z)
~r(t) = ~r0+1
2(~vi+~vf)t
θ(t) = θ0+ω0t+1
2αt2
ω(t) = ω0+αt
ω2
f=ω2
0+ 2α(θθ0)
θ(t) = θ0+1
2(ωi+ωf)t
Energy and Momenta:
translational rotational
K=1
2Mv2
W=R~
F·d~r const
force
~
F·~r
P=dW
dt =~
F·~v
~pcm =m1~v1+m2~v2+...
=M~vcm
~
J=R~
F dt = ~p
P~
Fext =M~acm =d~pcm
dt
P~
Fint = 0
if PFext,x = 0, pcm,x = const
~τ =~r ×~
Fand |~τ|=Fr=Fl
Krot =1
2Itotω2
W=Rτ const
torque τθ
P=dW
dt =~τ ·~ω
~
L=P~r ×~p
=I1~ω1+I2~ω2+...
=Itot~ω
P~τext =Itot~α =d~
L
dt
P~τint = 0
if Pτext,z = 0, Lz= const
—– Work-energy and potential energy —–
W= K Etot,i +Wother =Etot,f
U=R~
F·d~r ;Ugrav =Mg ycm ;Uelas =1
2kx2
Fx(x) = dU(x)/dx ~
F=~
U=∂U
∂x ˆ
i+∂U
∂y ˆ
j+∂U
∂z ˆ
k
Constants/Conversions:
g= 9.80 m/s2= 32.15 ft/s2(Earth, sea level)
10 m/s233 ft/s2
G= 6.674 ×1011 N·m2/kg21 mi = 1609 m
1 lb = 4.448 N 1 ft = 12 in
0.454 kg (Earth, sea level) 1 in = 2.54 cm
1 rev = 360= 2πradians
Circular motion: arad =v2
Ratan =d|~v|
dt =
T=2πR
vs= vtan =
Relative velocity: ~vA/C =~vA/B +~vB/C
~vA/B =~vB/A
Forces:
Newton’s: P~
F=m~a, ~
FBon A=~
FAon B
Hooke’s: Fx=kx
friction: |~
fs| µs|~n|,|~
fk|=µk|~n|
Centre-of-mass:
~rcm =m1~r1+m2~r2+... +mn~rn
m1+m2+...+mn
(and similarly for ~v and ~a)
Phys 218 Challenge Exam Formulae
pf2

Partial preview of the text

Download Physics 218 formula sheet and more Cheat Sheet Physics in PDF only on Docsity!

Trigonometry and Vectors:

sin 30

◦ = cos 60

1

2

sin 36. 9

◦ ≈ cos 53. 1

◦ ≈

3

5

sin 45

◦ = cos 45

1 √

2

sin 53. 1

◦ ≈ cos 36. 9

◦ ≈

4

5

sin 60

◦ = cos 30

3

2

hadj = h cos θ = h sin φ

hopp = h sin θ = h cos φ

h

2

= h

2

adj

  • h

2

opp

tan θ =

hopp

hadj

h

h

opp

hadj

Law of cosines: C

2 = A

2

  • B

2 − 2 AB cos γ

Law of sines:

sin α

A

sin β

B

sin γ

C

B γ

α

C

A

β

A = Ax

i + Ay

j + Az

k

A =

~ A

|

~ A|

A ·

B = A

x

B

x

+ A

y

B

y

+ A

z

B

z

= AB cos θ = A ‖

B = AB

A ×

B = (A

y

B

z

−A

z

B

y

)ˆi + (A z

B

x

−A

x

B

z

)ˆj + (A x

B

y

−A

y

B

x

k

A ×

B| = AB sin θ = A⊥B = AB⊥ (direction via right-hand rule)

Quadratic:

ax

2

  • bx + c = 0 ⇒ x 1 , 2

−b ±

b

2 − 4 ac

2 a

Derivatives: d

dt

(at

n

) = nat

n− 1

d

dt

sin at = a cos at

d

dt

cos at = −a sin at

Integrals:

t 2

t 1

f (t)dt =

a

n+

(t

n+

2

− t

n+

1

if f (t) = at

n , then

f (t)dt =

a

n+

t

n+

  • C

(n 6 = −1)

sin at dt =

− 1

a

cos at

cos at dt =

1

a

sin at

Kinematics:

translational rotational

〈~v〉 =

~r 2 −~r 1

t 2 −t 1

~v =

d~r

dt

〈~a〉 =

~v 2 −~v 1

t 2 −t 1

~a =

d~v

dt

d

2 ~r

dt

2

~r(t) = ~r 0

t

0

~v(t

′ ) dt

~v(t) = ~v 0 +

t

0

~a(t

′ ) dt

〈ω〉 =

θ 2 −θ 1

t 2 −t 1

ω =

dt

〈α〉 =

ω 2 −ω 1

t 2 −t 1

α =

dt

d

2 θ

dt

2

θ(t) = θ 0

t

0

ω(t

′ ) dt

ω(t) = ω 0 +

t

0

α(t

′ ) dt

—– constant (linear/angular) acceleration only —–

~r(t) = ~r 0

  • ~v 0

t +

1

2

~at

2

~v(t) = ~v 0

  • ~at

v

2

x

= v

2

x, 0

  • 2a x

(x − x 0

(and similarly for y and z)

~r(t) = ~r 0

1

2

(~v i

  • ~v f

)t

θ(t) = θ 0

  • ω 0

t +

1

2

αt

2

ω(t) = ω 0

  • αt

ω

2

f

= ω

2

0

  • 2α(θ − θ 0

θ(t) = θ 0

1

2

(ω i

  • ω f

)t

Energy and Momenta:

translational rotational

K =

1

2

M v

2

W =

F · d~r

const

−−−→

force

F · ∆~r

P =

dW

dt

F · ~v

p~cm = m 1 ~v 1 + m 2 ~v 2 +...

= M~vcm

J =

F dt = ∆~p

F

ext

= M~a cm

d~pcm

dt

~ Fint = 0

if

Fext,x = 0, pcm,x = const

~τ = ~r ×

F and |~τ | = F⊥r = F l

Krot =

1

2

Itotω

2

W =

τ dθ

const

−−−−→

torque

τ ∆θ

P =

dW

dt

= ~τ · ~ω

L =

~r × ~p

= I 1 ~ω 1 + I 2 ~ω 2 +...

= Itot~ω

~τext = Itot ~α =

d

L

dt

~τ int

if

τ ext,z

= 0, L

z

= const

—– Work-energy and potential energy —–

W = ∆K E

tot,i

+ W

other

= E

tot,f

U = −

F · d~r ; Ugrav = M gycm ; Uelas =

1

2

k∆x

2

Fx(x) = −dU (x)/dx

F = −

∇U = −

[

∂U

∂x

i +

∂U

∂y

j +

∂U

∂z

k

]

Constants/Conversions:

g = 9.80 m/s

2

= 32.15 ft/s

2

(Earth, sea level)

≈ 10 m/s

2

≈ 33 ft/s

2

G = 6. 674 × 10

− 11 N · m

2 /kg

2

1 mi = 1609 m

1 lb = 4.448 N 1 ft = 12 in

⇔ 0 .454 kg (Earth, sea level) 1 in = 2.54 cm

1 rev = 360

◦ = 2π radians

Circular motion: arad =

v

2

R

atan =

d|~v|

dt

= Rα

T =

2 πR

v

s = Rθ vtan = Rω

Relative velocity: ~vA/C =^ ~vA/B +^ ~vB/C

~vA/B = −~vB/A

Forces:

Newton’s:

F = m~a,

FB on A = −

FA on B

Hooke’s: Fx = −k∆x

friction: |

fs| ≤ μs|~n|, |

fk| = μk|~n|

Centre-of-mass:

~r cm

m 1

~r 1

  • m 2

~r 2

+... + m n

~r n

m 1 + m 2 +... + mn

(and similarly for ~v and ~a)

Phys 218 — Challenge Exam Formulae

Moments of inertia:

rectangular plate,

axis through centre

thin rectangular plate,

axis along edge

hollow sphere

solid sphere

thin-walled hollow

cylinder

solid cylinder

I =

1

12

M L

2 I =

1

3

M L

2 I =

1

12

M (a

2

  • b

2 ) (^) I =

1

3

M a

2

a

L

through centre

slender rod, axis

through one end

slender rod, axis

thin-walled

R^ R

R

2

R 1

hollow cylinder

R R

b

a

b L

I =

1

2

M (R

2

1

+ R

2

2

) I =

1

2

M R

2 I = M R

2

I =

2

5

M R

2 I =

2

3

M R

2

For a point-like particle of mass M a distance R from the axis of rotation: I = M R

2

Parallel axis theorem: I p

= I

cm

  • M d

2