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This physics question paper is designed for high school students, covering mechanics, thermodynamics, waves, optics, and nuclear physics. It features multiple-choice and descriptive problems, comprehensively assessing students' understanding of physics concepts. Useful for exam preparation and self-assessment, it offers problems to test knowledge and problem-solving skills. Questions are in both English and Hindi, increasing accessibility. General instructions and diagrams aid comprehension. This resource helps students reinforce physics principles and improve exam performance, covering a wide range of topics relevant to the high school physics curriculum.
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This Question Paper consists of 30 questions including 2 figures and 8 printed pages.
ß‚ ¬˝‡Ÿ-¬òÊ ◊¥ 30 ¬˝‡Ÿ ∑§ 8 ◊ÈÁŒ˝Ã ¬Îc∆U U •ÊÒ⁄U 2 •Ê∑ΧÁÃÿʰ „Ò–
Roll No.
•ŸÈ∑˝§◊Ê¥∑§
Code No.
Day and Date of Examination
¬⁄UˡÊÊ ∑§Ê ÁŒŸ fl ÁŒŸÊ¥∑§
Signature of Invigilators 1. ÁŸ⁄UˡÊ∑§Ê¥ ∑§ „SÃÊˇÊ⁄U
General Instructions :
‚Ê◊Êãÿ •ŸÈŒ‡Ê —
∑§Ë ¡ÊÚ°ø ÷Ë ∑§⁄U ‹¥ Á∑§ ¬˝‡Ÿ ∑˝ Á◊∑§ UM§¬ ◊¥ „Ò¥–
¡ÊÿªÊ–
•¥ª˝¡Ë, Á„¥ŒË, ©ŒÍ¸, ¬¥¡Ê’Ë, ’°ª‹Ê, ÃÁ◊‹, ◊‹ÿÊ‹◊, ∑§ãŸ«∏, ËȪÈ, ◊⁄UÊ∆UË, ©Á«∏ÿÊ, ªÈ¡⁄UÊÃË, ∑§Ê¥∑§áÊË, ◊ÁáʬÈ⁄UË, •‚Á◊ÿÊ, Ÿ¬Ê‹Ë, ∑§‡◊Ë⁄UË, ‚¥S∑Χç•ÊÒ⁄U Á‚¥œË– ∑Χ¬ÿÊ ©ûÊ⁄U-¬ÈÁSÃ∑§Ê ◊¥ ÁŒ∞ ª∞ ’ÊÚÄ‚ ◊¥ Á‹π¥ Á∑§ •ʬ Á∑§‚ ÷Ê·Ê ◊¥ ©ûÊ⁄U Á‹π ⁄U„ „Ò¥– § (π) ÿÁŒ •ʬ Á„¥ŒË ∞fl¥ •¥ª˝¡Ë ∑§ •ÁÃÁ⁄UÄà Á∑§‚Ë •ãÿ ÷Ê·Ê ◊¥ ©ûÊ⁄U Á‹πà „Ò¥ ÃÊ ¬˝‡Ÿ ∑§Ê ‚◊¤ÊŸ ◊¥ „ÊŸ flÊ‹Ë òÊÈÁ≈UÿÊ¥/ª‹ÁÃÿÊ¥ ∑§Ë Á¡ê◊UŒÊ⁄Ë ∑ fl‹ •ʬ∑§Ë „ʪ˖
PHYSICS
(÷ÊÒÁÃ∑§ ÁflôÊÊŸ)
(312)
Time : 3 Hours ] [ Maximum Marks : 80
‚◊ÿ — 3 ÉÊá≈U ] [ ¬ÍáÊÊZ∑§ — 80
Note : (i) All questions are compulsory. There is no overall choice, however, alternative choices are given in some questions. In such questions, you have to attempt only one choice. (ii) Marks allotted are indicated against each question. (iii) Each question from Question Nos. 1 to 10 has four alternative - (A), (B), (C) and (D), out of which one is most appropriate. Choose the correct answer among the four alternatives and write it in your answer-book against the number of the question. No extra time is allotted for attempting multiple choice questions.
ÁŸŒ¸‡Ê — (i) ‚÷Ë ¬˝‡ŸÊ¥ ∑§ ©ûÊ⁄U Œ¥– ¬Íáʸ ¬˝‡Ÿ-¬òÊ ◊¥ Áfl∑§À¬ Ÿ„Ë¥ „Ò¥, Á»§⁄U ÷Ë ∑ȧ¿U ¬˝‡ŸÊ¥ ◊¥ •Ê¥ÃÁ⁄U∑§ Áfl∑§À¬ „Ò– ∞‚ ‚÷Ë
¬˝‡ŸÊ¥ ◊¥ •ʬ∑§Ê ∞∑§ „Ë Áfl∑§À¬ ∑§Ê ©ûÊ⁄U ŒŸÊ „Ò– –
(ii) ¬˝àÿ∑§ ¬˝‡Ÿ ∑§ ‚Ê◊Ÿ •¥∑§ Œ‡Êʸÿ ªÿ „Ò¥–
(iii) ¬˝‡Ÿ ‚¥ÅÿÊ 1 ‚ 10 Ã∑§ ∑§ ¬˝àÿ∑§ ¬˝‡Ÿ ◊¥ øÊ⁄U Áfl∑§À¬ - (A), (B), (C) •ÊÒ⁄U (D) ÁŒÿ ªÿ „Ò¥, Á¡Ÿ◊¥ ‚ ∞∑§ ‚’ ‚ ©¬ÿÈÄà „Ò– øÊ⁄UÊ¥ Áfl∑§À¬Ê¥ ◊¥ ‚ ‚„Ë ©ûÊ⁄U øÈŸ¥ ÃÕÊ •¬ŸË ©ûÊ⁄U-¬ÈÁSÃ∑§Ê ◊¥ ¬˝‡Ÿ ‚¥ÅÿÊ ∑§ ‚Ê◊Ÿ ©ûÊ⁄U Á‹Áπÿ– ’„ÈflÒ∑§ÁÀ¬∑§ ¬˝‡ŸÊ¥ ∑§ Á‹ÿ •ÁÃÁ⁄UÄà ‚◊ÿ Ÿ„Ë¥ ÁŒÿÊ ¡ÊÿªÊ–
(A) 2 mu (B) mu (C) ‡ÊÍãÿ (D) −2 mu
(A) rotates the plane of polarised light
(B) changes the direction of polarised light
(C) does not allow plane polarised light to pass through it
(D) none of these
∞∑§ ¬˝∑§ÊÁ‡Ê∑§Ëÿ ¬ŒÊÕ¸ —
(A) œ˝ÈÁflà ¬˝∑§Ê‡Ê ∑§ Ë ∑§Ê ÉÊÈ◊ÊÃÊ „Ò
(B) œ˝ÈÁflà ¬˝∑§Ê‡Ê ∑§Ë ÁŒ‡ÊÊ ∑§Ê ’Œ‹ÃÊ „Ò
(C) ‚◊Ë œ˝ÈÁflà ¬˝∑§Ê‡Ê ∑§Ê ß‚◊¥ ‚ ªÈ¡⁄UŸ Ÿ„Ë¥ ŒÃÊ
(D) ߟ◊¥ ‚ ∑§Ê߸ Ÿ„Ë¥
(A) Mass only (B) Energy only
(C) Momentum only (D) Mass, Energy and Momentum
ŸÊÁ÷∑§Ëÿ •Á÷Á∑˝§ÿÊ ◊¥ ‚¥⁄UˇÊáÊ „ÊÃÊ „Ò —
(A) ∑§fl‹ Œ˝√ÿ◊ÊŸ ∑§Ê (B) ∑§fl‹ ™§¡Ê¸ ∑§Ê
(C) ∑§fl‹ ‚¥flª ∑§Ê (D) Œ˝√ÿ◊ÊŸ, ™§¡Ê¸ •ÊÒ⁄U ‚¥flª ∑§Ê
(A) Lyman series (B) Balmer series (C) Paschen series (D) Pfund series
ŸËø ÁŒ∞ „È∞ ◊¥ ‚ ∑§ÊÒŸ ‚Ë S¬Ä≈˛U‹ üÊáÊË ÁfllÈÃ-øÈê’∑§Ëÿ ÁflÁ∑§⁄UáÊÊ¥ ∑§ ŒÎ‡ÿ ÷ʪ ∑§ •ãê¸Ã •ÊÃË „Ò?
(A) ‹Êß◊Ÿ üÊáÊË (B) ’Ê◊⁄U üÊáÊË (C) ¬Ê‡øŸ üÊáÊË (D) »¥§«U üÊáÊË
(A) 9000 Å (B) 4000 Å (C) 6000 Å (D) 3000 Å
ÁŸflʸà ◊¥ λ=6000 Å ¬˝∑§Ê‡Ê ∑§Ë Á∑§⁄UáÊÊ¥ ∑§ Á‹∞ ∑§Ê°ø ∑§Ê •¬fløŸÊ¥∑§ 1.5 „Ò– ∑§Ê°ø ◊¥ ß‚∑§Ë Ã⁄¥UªŒÒäÿ¸ ∑§Ê ◊ÊŸ „Ò —
(A) 9000 Å (B) 4000 Å (C) 6000 Å (D) 3000 Å
(a) SÕÒÁÃ∑§ ÉÊ·¸áÊ ªÈáÊÊ¥∑§ •ÊÒ⁄U (b) ªÁá ÉÊ·¸áÊ ªÈáÊÊ¥∑§ ∑§Ë ¬Á⁄U÷Ê·Ê ŒËÁ¡∞–
‘m’ Œ˝√ÿ◊ÊŸ ∑§Ê ∞∑§ ªÈ≈U∑§Ê θ •ÊŸÁà ∑§ πÈ⁄UŒ⁄U Ë ¬⁄U ⁄UπÊ „È•Ê „Ò– ªÈ≈U∑§ ¬⁄U ¬˝÷ÊflË ÁflÁ÷㟠’‹Ê¥ ∑§Ê ÁøòÊ mÊ⁄UÊ Œ‡Êʸßÿ–
◊Ê≈U⁄U ªÊÁ«∏ÿÊ¥ ∑§Ê ∞∑§ ÁŸÁ‡øÃ ™°§øÊ߸ Ã∑§ ©∆UÊŸ ∑§ Á‹∞ „Êß«˛UÊÁ‹∑§ ¡Ò∑§ ∑§Ê ∞∑§ ‚◊ÈÁøÃ ÁøòÊ ’ŸÊßÿ–
™§c◊ʪÁÃ∑§Ë ∑§ ‡ÊÍãÿ ∑§ÊÁ≈U ÁŸÿ◊ ∑§Ê ∑§ÕŸ Á‹Áπ∞– ™§c◊Ê ∑§Ë ∞∑§ ∑Ò§‹Ê⁄UË ∑§Êÿ¸ ∑§ Á∑§ÃŸ ¡Í‹ ∑§ ’⁄UÊ’⁄U „ÊÃË „Ò?
™§c◊ʪÁÃ∑§Ë ÁŸ∑§Êÿ ∑§ Á‹∞ ∞∑§ ‚Íø∑§ •Ê⁄Uπ ’ŸÊßÿ, ¡’Á∑§ ŒÊ’ P 1 •ÊÒ⁄U P 2 ¬⁄U ∑˝§◊‡Ê— •Êÿß V 1 fl V 2 ‚◊ÃÊ¬Ë •flSÕÊ ◊¥ ¬˝‚Ê⁄U ∑§ ŒÊÒ⁄UÊŸ „ÊÃÊ „Ò–
©Ÿ ŒÊ ∑§Ê⁄UáÊÊ¥ ∑§Ê Á‹Áπ∞, Á¡ã„¥ äÿÊŸ ◊¥ ⁄Uπ∑§⁄U ‹Êå‹Ê‚ ∑§Ê flÊÿÈ ◊¥ äflÁŸ ∑§ flª ∑§ Á‹∞ ãÿÍ≈UŸ ∑§Ê ‚ÍòÊ ‚¥‡ÊÊÁœÃ ∑§⁄UŸÊ ¬«∏Ê–
ÿ„ Œ‡Êʸßÿ Á∑§ ¬˝Áà 18 C Ãʬ ’…∏Ÿ ¬⁄U flÊÿÈ ◊¥ äflÁŸ ∑§Ê flª 0.61 ms−^1 ’…∏ ¡ÊÃÊ „Ò–
Ãʬ ∑§ ‚ÊÕ •h¸øÊ‹∑§ ∑§Ë ¬˝ÁÃ⁄UÊœ∑§ÃÊ ∑§ ¬Á⁄UfløŸ ∑§Ê Œ‡ÊʸŸ ∑§ Á‹∞ ∞∑§ ª˝Ê»§ ’ŸÊßÿ–
¬˝∑§Ê‡Ê-ÁfllÈà ¬˝÷Êfl ∑§ ¬˝ÊÿÊÁª∑§ •äÿÿŸ ‚ ∑§ÊÒŸ ‚ øÊ⁄U ◊ÈÅÿ ¬˝ˇÊáÊ ¬˝Êåà „Êà „Ò¥?
(b) Draw symbols of n-p-n and p-n-p transistors. (c) Why does the arrow head point ‘outward’ in case of n-p-n transistor; while ‘inward’ in case of p-n-p transistor? (a) ÁøòÊ ∑§Ë ‚„ÊÿÃÊ ‚ ≈˛UÊ¥Á¡S≈U⁄U ∑§ ÃËŸ ◊ÈÅÿ •flÿflÊ¥ ∑§Ê ÁŒπ‹Êßÿ–
(b) n-p-n •ÊÒ⁄U p-n-p ≈˛UÊ¥Á¡S≈U⁄UÊ¥ ∑§ Á‹∞ ‚Ê¥∑§ÁÃ∑§ ÁŸM§¬áÊ ∑§Ê ’ŸÊßÿ– (c) n-p-n ≈˛UÊ¥Á¡S≈U⁄U ◊¥ ’ÊáÊʪ˝ “’Ê„⁄U ∑§Ë •Ê⁄U” ¡’Á∑§ p-n-p ≈˛UÊ¥Á¡S≈U⁄U ◊¥ “•ãŒ⁄U ∑§Ë •Ê⁄U” ÄÿÊ¥ „ÊÃÊ „Ò?
(b) Á∑§‚Ë ¬Ê⁄UŒ‡Ê˸ ¬ŒÊÕ¸ ‚ ¬⁄UÊflÁøà „Ê ¡ÊŸ ¬⁄U •œ˝ÈÁflà ¬˝∑§Ê‡Ê Á∑§‚ ¬˝∑§Ê⁄U ‚◊Ë œÈ˝Áflà „ÊÃÊ „Ò? ß‚∑§ Á‹∞ ∞∑§ Á∑§⁄UáÊ •Ê⁄Uπ ÷Ë ’ŸÊßÿ– (c) ’˝ÍS≈U⁄U ÁŸÿ◊ ∑§ Á‹∞ √ÿ¥¡∑§ ¬˝Êåà ∑§ËÁ¡∞–
‚⁄U ‚Ë.flË. ⁄U◊Ÿ ∑§Ê 1930 ◊¥ ÷ÊÒÁÃ∑§Ë ∑§Ê ŸÊ’‹ ¬È⁄US∑§Ê⁄U “⁄U◊Ÿ ¬˝÷Êfl” ∑§Ë πÊ¡ ∑§ Á‹∞ ¬˝ŒÊŸ Á∑§ÿÊ ªÿÊ ÕÊ–
(a) “⁄U◊Ÿ ¬˝÷Êfl” ∑§ ’Ê⁄U ◊¥ ’ËÊßÿ •ÊÒ⁄U ‚ÊÕ ◊¥ ß‚∑§Ë ‚⁄U‹ ‚ÒhÊÁãÃ∑§ √ÿÊÅÿÊ ∑§ËÁ¡∞–
(b) Á∑§‚Ë ‚◊’Ê„È Á¬˝í◊ ∑§ ¬ŒÊÕ¸ ∑§ •¬fløŸÊ¥∑§ ∑§Ê ¬Á⁄U∑§‹Ÿ ∑§ËÁ¡∞, ¡’ ãÿÍŸÃ◊ Áflø‹Ÿ ∑§ÊáÊ •ÊÒ⁄U Á¬˝í◊ ∑§ÊáÊ ∞∑§ ŒÍ‚⁄U ∑§ ’⁄UÊ’⁄U „Ê–
(a) ™§¡Ê¸ ’Ò¥«UÊ¥ ∑§ •ÊœÊ⁄U ¬⁄U øÊ‹∑§Ê¥, •h¸-øÊ‹∑§Ê¥ ∞fl¥ ÁfllÈÃ-Áfl⁄UÊÁœÿÊ¥ ∑§ flªË¸∑§⁄UáÊ ∑§ ’Ê⁄U ◊¥ Á‹Áπ∞– ¬˝àÿ∑§ ∑§ Á‹∞ ∞∑§-∞∑§ ™§¡Ê¸ ’Ò¥«U ∑§Ê ÁøòÊ ’ŸÊßÿ–
(b) ŸÒ¡ •h¸øÊ‹∑§Ê¥ fl ’Ês •h¸øÊ‹∑§Ê¥ ∑§ ’Ëø ŒÊ ◊ÈÅÿ •ãÃ⁄U Á‹Áπ∞–
OR / •ÕflÊ
(a) Explain the formation of p-n junction. Draw a diagram for it. Hence define ‘Depletion Region’ and ‘Barrier Potential’. (b) Draw I-V characteristics for a zener diode. What is its main application?
(a) p-n ‚¥Áœ ∑§Ë ‚¥⁄UøŸÊ ∑§Ê ‚◊¤ÊÊßÿ– ß‚∑§ Á‹∞ ∞∑§ ÁøòÊ ’ŸÊßÿ– “•flÿfl ˇÊòÊ” •ÊÒ⁄U “Áfl÷fl ¬˝ÊøË⁄U” ∑§Ë ¬Á⁄U÷Ê·Ê ŒËÁ¡∞–
(b) $¡Ÿ⁄U «UÊÿÊ«U ∑§ I-V •Á÷‹ˇÊáÊÊ¥ ∑§ Á‹∞ ∞∑§ fl∑˝§ÁøòÊ ’ŸÊßÿ– ß‚∑§Ê ∞∑§ ◊ÈÅÿ •ŸÈ¬˝ÿʪ ÄÿÊ „Ò?
PHYSICS
(÷ÊÒÁÃ∑§ ÁflôÊÊŸ)
(312)
Time : 3 Hours ] [ Maximum Marks : 80
‚◊ÿ — 3 ÉÊá≈U ] [ ¬ÍáÊÊZ∑§ — 80
Note : (i) All questions are compulsory. There is no overall choice, however, alternative choices are given in some questions. In such questions, you have to attempt only one choice. (ii) Marks allotted are indicated against each question. (iii) Each question from Question Nos. 1 to 10 has four alternative - (A), (B), (C) and (D), out of which one is most appropriate. Choose the correct answer among the four alternatives and write it in your answer-book against the number of the question. No extra time is allotted for attempting multiple choice questions.
ÁŸŒ¸‡Ê — (i) ‚÷Ë ¬˝‡ŸÊ¥ ∑§ ©ûÊ⁄U Œ¥– ¬Íáʸ ¬˝‡Ÿ-¬òÊ ◊¥ Áfl∑§À¬ Ÿ„Ë¥ „Ò¥, Á»§⁄U ÷Ë ∑ȧ¿U ¬˝‡ŸÊ¥ ◊¥ •Ê¥ÃÁ⁄U∑§ Áfl∑§À¬ „Ò– ∞‚ ‚÷Ë
¬˝‡ŸÊ¥ ◊¥ •ʬ∑§Ê ∞∑§ „Ë Áfl∑§À¬ ∑§Ê ©ûÊ⁄U ŒŸÊ „Ò– –
(ii) ¬˝àÿ∑§ ¬˝‡Ÿ ∑§ ‚Ê◊Ÿ •¥∑§ Œ‡Êʸÿ ªÿ „Ò¥–
(iii) ¬˝‡Ÿ ‚¥ÅÿÊ 1 ‚ 10 Ã∑§ ∑§ ¬˝àÿ∑§ ¬˝‡Ÿ ◊¥ øÊ⁄U Áfl∑§À¬ - (A), (B), (C) •ÊÒ⁄U (D) ÁŒÿ ªÿ „Ò¥, Á¡Ÿ◊¥ ‚ ∞∑§ ‚’ ‚ ©¬ÿÈÄà „Ò– øÊ⁄UÊ¥ Áfl∑§À¬Ê¥ ◊¥ ‚ ‚„Ë ©ûÊ⁄U øÈŸ¥ ÃÕÊ •¬ŸË ©ûÊ⁄U-¬ÈÁSÃ∑§Ê ◊¥ ¬˝‡Ÿ ‚¥ÅÿÊ ∑§ ‚Ê◊Ÿ ©ûÊ⁄U Á‹Áπÿ– ’„ÈflÒ∑§ÁÀ¬∑§ ¬˝‡ŸÊ¥ ∑§ Á‹ÿ •ÁÃÁ⁄UÄà ‚◊ÿ Ÿ„Ë¥ ÁŒÿÊ ¡ÊÿªÊ–
(A) rotates the plane of polarised light
(B) changes the direction of polarised light
(C) does not allow plane polarised light to pass through it
(D) none of these
∞∑§ ¬˝∑§ÊÁ‡Ê∑§Ëÿ ¬ŒÊÕ¸ —
(A) œ˝ÈÁflà ¬˝∑§Ê‡Ê ∑§ Ë ∑§Ê ÉÊÈ◊ÊÃÊ „Ò
(B) œ˝ÈÁflà ¬˝∑§Ê‡Ê ∑§Ë ÁŒ‡ÊÊ ∑§Ê ’Œ‹ÃÊ „Ò
(C) ‚◊Ë œ˝ÈÁflà ¬˝∑§Ê‡Ê ∑§Ê ß‚◊¥ ‚ ªÈ¡⁄UŸ Ÿ„Ë¥ ŒÃÊ
(D) ߟ◊¥ ‚ ∑§Ê߸ Ÿ„Ë¥
(A) Mass only (B) Energy only (C) Momentum only (D) Mass, Energy and Momentum
ŸÊÁ÷∑§Ëÿ •Á÷Á∑˝§ÿÊ ◊¥ ‚¥⁄UˇÊáÊ „ÊÃÊ „Ò —
(A) ∑§fl‹ Œ˝√ÿ◊ÊŸ ∑§Ê (B) ∑§fl‹ ™§¡Ê¸ ∑§Ê
(C) ∑§fl‹ ‚¥flª ∑§Ê (D) Œ˝√ÿ◊ÊŸ, ™§¡Ê¸ •ÊÒ⁄U ‚¥flª ∑§Ê
ŸËø ÁŒ∞ „È∞ ◊¥ ‚ ∑§ÊÒŸ ‚Ë S¬Ä≈˛U‹ üÊáÊË ÁfllÈÃ-øÈê’∑§Ëÿ ÁflÁ∑§⁄UáÊÊ¥ ∑§ ŒÎ‡ÿ ÷ʪ ∑§ •ãê¸Ã •ÊÃË „Ò?
(A) ‹Êß◊Ÿ üÊáÊË (B) ’Ê◊⁄U üÊáÊË (C) ¬Ê‡øŸ üÊáÊË (D) »¥§«U üÊáÊË
ÁŸflʸà ◊¥ λ=6000 Å ¬˝∑§Ê‡Ê ∑§Ë Á∑§⁄UáÊÊ¥ ∑§ Á‹∞ ∑§Ê°ø ∑§Ê •¬fløŸÊ¥∑§ 1.5 „Ò– ∑§Ê°ø ◊¥ ß‚∑§Ë Ã⁄¥UªŒÒäÿ¸ ∑§Ê ◊ÊŸ „Ò —
(A) 9000 Å (B) 4000 Å (C) 6000 Å (D) 3000 Å
‘m’ Œ˝√ÿ◊ÊŸ ∑§Ë ∞∑§ ª¥Œ ŒÎ…∏ ŒËflÊ⁄U ‚ ‘u’ ªÁà ‚ ≈U∑§⁄UÊÃË „Ò •ÊÒ⁄U ≈U∑§⁄UÊŸ ∑§ ’ÊŒ ©‚Ë ªÁà ‚ flÊÁ¬‚ •ÊÃË „Ò– ŒËflÊ⁄U ∑§ mÊ⁄UÊ ª¥Œ ∑§Ê ÁŒÿÊ ªÿÊ •Êflª „Ò —
(A) 2 mu (B) mu (C) ‡ÊÍãÿ (D) −2 mu
(A) temperature only (B) volume only (C) both volume and temperature (D) not on both volume and temperature together
Á∑§‚Ë •ÊŒ‡Ê¸ ªÒ‚ ∑§Ë •ÊãÃÁ⁄U∑§ ™§¡Ê¸ Á∑§‚ ¬⁄U ÁŸ÷¸⁄U ∑§⁄UÃË „Ò?
(A) ∑§fl‹ Ãʬ ¬⁄U (B) ∑§fl‹ •Êÿß ¬⁄U
(C) ŒÊŸÊ¥ Ãʬ fl •Êÿß ¬⁄U (D) ŒÊŸÊ¥ Ãʬ fl •Êÿß ¬⁄U ∞∑§ ‚ÊÕ Ÿ„Ë¥
ÿ„ Œ‡Êʸßÿ Á∑§ ¬˝Áà 18 C Ãʬ ’…∏Ÿ ¬⁄U flÊÿÈ ◊¥ äflÁŸ ∑§Ê flª 0.61 ms−^1 ’…∏ ¡ÊÃÊ „Ò–
Ãʬ ∑§ ‚ÊÕ •h¸øÊ‹∑§ ∑§Ë ¬˝ÁÃ⁄UÊœ∑§ÃÊ ∑§ ¬Á⁄UfløŸ ∑§Ê Œ‡ÊʸŸ ∑§ Á‹∞ ∞∑§ ª˝Ê»§ ’ŸÊßÿ–
¬˝∑§Ê‡Ê-ÁfllÈà ¬˝÷Êfl ∑§ ¬˝ÊÿÊÁª∑§ •äÿÿŸ ‚ ∑§ÊÒŸ ‚ øÊ⁄U ◊ÈÅÿ ¬˝ˇÊáÊ ¬˝Êåà „Êà „Ò¥?
(a) SÕÒÁÃ∑§ ÉÊ·¸áÊ ªÈáÊÊ¥∑§ •ÊÒ⁄U (b) ªÁá ÉÊ·¸áÊ ªÈáÊÊ¥∑§ ∑§Ë ¬Á⁄U÷Ê·Ê ŒËÁ¡∞–
∞∑§ ‚ÁŒ‡Ê ÁøòÊ ’ŸÊßÿ ¡’Á∑§ ÃËŸ ‚¥ªÊ◊Ë ’‹ ∞∑§ Á’ãŒÈ ¬⁄U ß‚ ¬˝∑§Ê⁄U ‹ªÊ∞ ¡Êà „Ò¥ Á∑§ ÿ ÃËŸÊ¥ ’‹ ‚¥ÃÈ‹Ÿ ◊¥ „Ê¥–
◊Ê≈U⁄U ªÊÁ«∏ÿÊ¥ ∑§Ê ∞∑§ ÁŸÁ‡øÃ ™°§øÊ߸ Ã∑§ ©∆UÊŸ ∑§ Á‹∞ „Êß«˛UÊÁ‹∑§ ¡Ò∑§ ∑§Ê ∞∑§ ‚◊ÈÁøÃ ÁøòÊ ’ŸÊßÿ–
™§c◊ʪÁÃ∑§Ë ∑§ ‡ÊÍãÿ ∑§ÊÁ≈U ÁŸÿ◊ ∑§Ê ∑§ÕŸ Á‹Áπ∞– ™§c◊Ê ∑§Ë ∞∑§ ∑Ò§‹Ê⁄UË ∑§Êÿ¸ ∑§ Á∑§ÃŸ ¡Í‹ ∑§ ’⁄UÊ’⁄U „ÊÃË „Ò?
™§c◊ʪÁÃ∑§Ë ∑§ ¬˝Õ◊ ÁŸÿ◊ ∑§Ê ∑§ÕŸ Á‹Áπ∞– ß‚∑§ ªÁáÊÃËÿ M§¬ ∑§Ê ÷Ë Á‹Áπ∞–
©Ÿ ŒÊ ∑§Ê⁄UáÊÊ¥ ∑§Ê Á‹Áπ∞, Á¡ã„¥ äÿÊŸ ◊¥ ⁄Uπ∑§⁄U ‹Êå‹Ê‚ ∑§Ê flÊÿÈ ◊¥ äflÁŸ ∑§ flª ∑§ Á‹∞ ãÿÍ≈UŸ ∑§Ê ‚ÍòÊ ‚¥‡ÊÊÁœÃ ∑§⁄UŸÊ ¬«∏Ê–
Á«U ’˝ÊÇ‹Ë ∑§Ë ¬Á⁄U∑§À¬ŸÊ ∑§Ê Á‹Áπ∞– ∞∑§ ◊Í‹ ∑§áÊ Á¡‚∑§Ê Œ˝√ÿ◊ÊŸ ‘m’, •Êfl‡Ê ‘q’, ‘v’ ªÁà ‚ ø‹Êÿ◊ÊŸ „Ò, ¡’ ©‚ ‘V’ Áfl÷flÊãÃ⁄U ‚ àflÁ⁄Uà Á∑§ÿÊ ¡ÊÃÊ „Ò Á«U ’˝ÊÇ‹Ë Ã⁄¥UªŒÒäÿ¸ ∑§ Á‹∞ √ÿ¥¡∑§ ¬˝Êåà ∑§ËÁ¡∞–
(b) Draw symbols of n-p-n and p-n-p transistors. (c) Why does the arrow head point ‘outward’ in case of n-p-n transistor; while ‘inward’ in case of p-n-p transistor?
(a) ÁøòÊ ∑§Ë ‚„ÊÿÃÊ ‚ ≈˛UÊ¥Á¡S≈U⁄U ∑§ ÃËŸ ◊ÈÅÿ •flÿflÊ¥ ∑§Ê ÁŒπ‹Êßÿ–
(b) n-p-n •ÊÒ⁄U p-n-p ≈˛UÊ¥Á¡S≈U⁄UÊ¥ ∑§ Á‹∞ ‚Ê¥∑§ÁÃ∑§ ÁŸM§¬áÊ ∑§Ê ’ŸÊßÿ–
(c) n-p-n ≈˛UÊ¥Á¡S≈U⁄U ◊¥ ’ÊáÊʪ˝ “’Ê„⁄U ∑§Ë •Ê⁄U” ¡’Á∑§ p-n-p ≈˛UÊ¥Á¡S≈U⁄U ◊¥ “•ãŒ⁄U ∑§Ë •Ê⁄U” ÄÿÊ¥ „ÊÃÊ „Ò?
ãÿÍ≈UŸ ∑§ ÃË‚⁄U ªÁà ÁŸÿ◊ ∑§Ê Á‹Áπ∞– ß‚ ∞∑§ ©‚ ©ŒÊ„⁄UáÊ ∑§ mÊ⁄UÊ ¬˝ŒÁ‡Ê¸Ã ∑§ËÁ¡∞ ¡’ ∞∑§ ¬ÈSÃ∑§ ∑§Ê ◊$¡ ¬⁄U ⁄UπÊ ¡ÊÃÊ „Ò– ß‚∑§Ê ∞∑§ ÁøòÊ ’ŸÊßÿ–
ãÿÍ≈UŸ ∑§ ÃË‚⁄U ªÁà ÁŸÿ◊ ∑§Ê ‚ÁŒ‡Ê •Á÷M§¬ ÄÿÊ „Ò?
2 kg Œ˝√ÿ◊ÊŸ ∑§Ê ∞∑§ Á¬¥«U ¡◊ËŸ ‚ 10 m ∑§Ë ™°§øÊ߸ ¬⁄U ⁄UπÊ „È•Ê „Ò– ∑§Êÿ¸-™§¡Ê¸ Á‚hÊãà ∑§Ê ¬˝ÿʪ ∑§⁄Uà „È∞ —
(a) ¡◊ËŸ ‚ 6 m ∑§Ë ™°§øÊ߸ ¬⁄U Á¬¥«U ∑§Ë øÊ‹ ∑§Ë ªáÊŸÊ ∑§ËÁ¡∞, ¡’ fl„ 10 m ‚ ◊ÈÄàÊ M§¬ ‚ Áª⁄UÃÊ „Ò–
(b) 10 m ∑§Ë ™°§øÊ߸ ‚ ◊ÈÄàÊ M§¬ ‚ Áª⁄U ∑§⁄U $¡◊ËŸ ¬⁄U ¬„ȰøŸ ¬⁄U Á¬¥«U ∑§Ë øÊ‹ ∑§Ë ªáÊŸÊ ∑§ËÁ¡∞–
(c) ªÈL§àflËÿ ’‹ mÊ⁄UÊ ¡◊ËŸ ‚ 10 m ∑§Ë ™°§øÊ߸ ¬⁄U ‹ ¡ÊŸ ◊¥ Á∑§ÃŸÊ ∑§Êÿ¸ Á∑§ÿÊ ¡Ê∞ªÊ?
(d) ÿ„ ’ËÊßÿ Á∑§ (c) ◊¥ Á∑§ÿÊ ªÿÊ ∑§Êÿ¸ œŸÊà◊∑§ „ÊªÊ ÿÊ ´§áÊÊà◊∑§? (g=10 ms−^2 ∑§Ê ◊ÊŸ ‹ËÁ¡∞)
ÁfllÈà ˇÊòÊ ⁄UπÊ∞° ÄÿÊ „ÊÃË „Ò¥? ©Ÿ∑§ ÃËŸ ªÈáÊœ◊ÊZ ∑§Ê Á‹Áπ∞– (a) œŸÊà◊∑§ ∞∑§‹ Á’ãŒÈ •Êfl‡Ê, •ÊÒ⁄U (b) ÁfllÈà Ámœ˝Èfl ∑§ Á‹∞ ÁfllÈà ˇÊòÊ ⁄UπÊ∞° πË¥Áø∞–
(b) State ‘Rayleigh’s law of scattering’. (c) Explain the red colour of the sun at sunrise and sunset. Draw a diagram.
(a) “¬˝∑§Ê‡Ê ∑§ ¬˝∑§ËáʸŸ” ∑§Ë ¬Á⁄UÉÊ≈UŸÊ ∑§Ë √ÿÊÅÿÊ ∑§ËÁ¡∞–
(b) “⁄ÒU‹ ∑§ ¬˝∑§ËáʸŸ ÁŸÿ◊” ∑§Ê ∑§ÕŸ Á‹Áπ∞–
(c) ß‚ Ãâÿ ∑§Ë √ÿÊÅÿÊ ∑§ËÁ¡∞ Á∑§ ‚ÍÿʸŒÿ fl ‚ÍÿʸSà ∑§ ‚◊ÿ ‚Íÿ¸ ‹Ê‹ ⁄¥Uª ∑§Ê ÄÿÊ¥ ÁŒπÊ߸ ŒÃÊ „Ò? ß‚∑§ Á‹∞ ∞∑§ ÁøòÊ ’ŸÊßÿ–
‚⁄U ‚Ë.flË. ⁄U◊Ÿ ∑§Ê 1930 ◊¥ ÷ÊÒÁÃ∑§Ë ∑§Ê ŸÊ’‹ ¬È⁄US∑§Ê⁄U “⁄U◊Ÿ ¬˝÷Êfl” ∑§Ë πÊ¡ ∑§ Á‹∞ ¬˝ŒÊŸ Á∑§ÿÊ ªÿÊ ÕÊ–
(a) “⁄U◊Ÿ ¬˝÷Êfl” ∑§ ’Ê⁄U ◊¥ ’ËÊßÿ •ÊÒ⁄U ‚ÊÕ ◊¥ ß‚∑§Ë ‚⁄U‹ ‚ÒhÊÁãÃ∑§ √ÿÊÅÿÊ ∑§ËÁ¡∞–
(b) Á∑§‚Ë ‚◊’Ê„È Á¬˝í◊ ∑§ ¬ŒÊÕ¸ ∑§ •¬fløŸÊ¥∑§ ∑§Ê ¬Á⁄U∑§‹Ÿ ∑§ËÁ¡∞, ¡’ ãÿÍŸÃ◊ Áflø‹Ÿ ∑§ÊáÊ •ÊÒ⁄U Á¬˝í◊ ∑§ÊáÊ ∞∑§ ŒÍ‚⁄U ∑§ ’⁄UÊ’⁄U „Ê–
This Question Paper consists of 30 questions including 1 figure and 8 printed pages.
ß‚ ¬˝‡Ÿ-¬òÊ ◊¥ 30 ¬˝‡Ÿ ∑§ 8 ◊ÈÁŒ˝Ã ¬Îc∆U U •ÊÒ⁄U 1 •Ê∑ΧÃË „Ò¥–
Roll No.
•ŸÈ∑˝§◊Ê¥∑§
Code No.
Day and Date of Examination
¬⁄UˡÊÊ ∑§Ê ÁŒŸ fl ÁŒŸÊ¥∑§
Signature of Invigilators 1. ÁŸ⁄UˡÊ∑§Ê¥ ∑§ „SÃÊˇÊ⁄U
General Instructions :
‚Ê◊Êãÿ •ŸÈŒ‡Ê —
∑§Ë ¡ÊÚ°ø ÷Ë ∑§⁄U ‹¥ Á∑§ ¬˝‡Ÿ ∑˝ Á◊∑§ UM§¬ ◊¥ „Ò¥–
¡ÊÿªÊ–
•¥ª˝¡Ë, Á„¥ŒË, ©ŒÍ¸, ¬¥¡Ê’Ë, ’°ª‹Ê, ÃÁ◊‹, ◊‹ÿÊ‹◊, ∑§ãŸ«∏, ËȪÈ, ◊⁄UÊ∆UË, ©Á«∏ÿÊ, ªÈ¡⁄UÊÃË, ∑§Ê¥∑§áÊË, ◊ÁáʬÈ⁄UË, •‚Á◊ÿÊ, Ÿ¬Ê‹Ë, ∑§‡◊Ë⁄UË, ‚¥S∑Χç•ÊÒ⁄U Á‚¥œË– ∑Χ¬ÿÊ ©ûÊ⁄U-¬ÈÁSÃ∑§Ê ◊¥ ÁŒ∞ ª∞ ’ÊÚÄ‚ ◊¥ Á‹π¥ Á∑§ •ʬ Á∑§‚ ÷Ê·Ê ◊¥ ©ûÊ⁄U Á‹π ⁄U„ „Ò¥– § (π) ÿÁŒ •ʬ Á„¥ŒË ∞fl¥ •¥ª˝¡Ë ∑§ •ÁÃÁ⁄UÄà Á∑§‚Ë •ãÿ ÷Ê·Ê ◊¥ ©ûÊ⁄U Á‹πà „Ò¥ ÃÊ ¬˝‡Ÿ ∑§Ê ‚◊¤ÊŸ ◊¥ „ÊŸ flÊ‹Ë òÊÈÁ≈UÿÊ¥/ª‹ÁÃÿÊ¥ ∑§Ë Á¡ê◊UŒÊ⁄Ë ∑ fl‹ •ʬ∑§Ë „ʪ˖
Which one of the following statements is true? (A) A is isothermal process, while B is adiabatic process (B) A is adiabatic process, while B is isothermal process (C) Both are isothermal processes (D) Both are adiabatic processes ÁŒÿÊ „È•Ê P-V •Ê⁄Uπ ªÒ‚ ∑§ ¬˝‚Ê⁄U ∑§ Á‹∞ „Ò? ŸËø ÁŒ∞ ª∞ ∑§ÕŸÊ¥ ◊¥ ‚ ∑§ÊÒŸ-‚Ê ‚„Ë „Ò?
(A) A ‚◊ÃÊ¬Ë ¬˝∑˝§◊ „Ò, ¡’Á∑§ B L§hÊc◊ ¬˝∑˝§◊ „Ò
(B) A L§hÊc◊ ¬˝∑˝§◊ „Ò, ¡’Á∑§ B ‚◊ÃÊ¬Ë ¬˝∑˝§◊ „Ò (C) ŒÊŸÊ¥ „Ë ‚◊ÃÊ¬Ë ¬˝∑˝§◊ „¥Ò
(D) ŒÊŸÊ¥ „Ë L§hÊc◊ ¬˝∑˝§◊ „Ò¥
(A) Solids (B) Liquids (C) Gases (D) Vacuum äflÁŸ ∑§Ë Ã⁄¥Uª¥ ∑§ÊÒŸ ‚ ◊Êäÿ◊ ◊¥ ‚’‚ Ã$¡ ªÁà ‚ ‚¥ø⁄UáÊ ∑§⁄UÃË „Ò¥? (A) ∆UÊ‚ (B) Œ˝fl (C) ªÒ‚ (D) ÁŸflʸÃ
(A) 1 : 2 (B) 1 : 3 (C) 2 : 3 (D) 3 : 5
(A) rotates the plane of polarised light (B) changes the direction of polarised light (C) does not allow plane polarised light to pass through it (D) none of these ∞∑§ ¬˝∑§ÊÁ‡Ê∑§Ëÿ ¬ŒÊÕ¸ —
(A) œ˝ÈÁflà ¬˝∑§Ê‡Ê ∑§ Ë ∑§Ê ÉÊÈ◊ÊÃÊ „Ò
(B) œ˝ÈÁflà ¬˝∑§Ê‡Ê ∑§Ë ÁŒ‡ÊÊ ∑§Ê ’Œ‹ÃÊ „Ò (C) ‚◊Ë œ˝ÈÁflà ¬˝∑§Ê‡Ê ∑§Ê ß‚◊¥ ‚ ªÈ¡⁄UŸ Ÿ„Ë¥ ŒÃÊ
(D) ߟ◊¥ ‚ ∑§Ê߸ Ÿ„Ë¥
(A) Mass only (B) Energy only (C) Momentum only (D) Mass, Energy and Momentum ŸÊÁ÷∑§Ëÿ •Á÷Á∑˝§ÿÊ ◊¥ ‚¥⁄UˇÊáÊ „ÊÃÊ „Ò — (A) ∑§fl‹ Œ˝√ÿ◊ÊŸ ∑§Ê (B) ∑§fl‹ ™§¡Ê¸ ∑§Ê
(C) ∑§fl‹ ‚¥flª ∑§Ê (D) Œ˝√ÿ◊ÊŸ, ™§¡Ê¸ •ÊÒ⁄U ‚¥flª ∑§Ê
(A) ‹Êß◊Ÿ üÊáÊË (B) ’Ê◊⁄U üÊáÊË (C) ¬Ê‡øŸ üÊáÊË (D) »¥§«U üÊáÊË
(A) 2 mu (B) mu (C) ‡ÊÍãÿ (D) −2 mu