Starting from rest, a cheetahaccelerates at a constant rate of 4.8 m/s2for a
total of 5 seconds.
Since it starts from rest,
v
0=0
.
With constant acceleration, velocity is:
v
=
v
0+
at
=
at
We substitute each requested time value (t=1,2,3,4,5) into the simplified
equation:
For t=1 s: v (1) = 4.8(1) =4.8 m/s
For t=2 s: v (2) = 4.8(2) =9.6 m/s
For t=3 s: v (3) = 4.8(3) =14.4 m/s
For t=4 s: v (4) = 4.8(4) =19.2 m/s
For t=5 s: v (5) = 4.8(5) =24.0 m/s
