Physics Worksheet: Current Electricity and Radioactivity for Class X ICSE, Study notes of Physics

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Mark on them:Live(L), Neutral (N) and Earth(E).

13. Draw current Vs voltage variation for non-ohmic resistors.
14. Calculate equivalent resistance between a and b.
15. What is current through each resistor for a parallel combination of 3Ω, 3.5Ω and 4Ω resistors. The battery connected is of 8V. Also find the effective resistance and effective current. Multiple Choice Questions Question 1. A wire of length /, made of material resistivity ρ is cut into two equal parts. The resistivity of the two parts are equal to, (a) ρ (b) ρ (c) 2 ρ (d) 4 ρ Answer/Explanation Answer: a

Explanation: (a) Resistivity of the material depends only on the nature of material not dimensions.

2. The temperature of a conductor is increased. The graph best showing the variation of its resistance is Answer/Explanation Answer: a Explanation: (a) Resistance is directly proportional to temperature of the conductor.

5. The resistance whose V-I graph is given below is Answer/Explanation Answer: b Explanation: (b) Resistance = slope line of V-I graph =
6. To get 2 Ω resistance using only 6 Ω resistors, the number of them required is (a) 2 (b) 3 (c) 4 (d) 6 Answer/Explanation Answer: b Explanation: (b) Three resistors of 2 Ω is required to get 6 Ω because resultant is more than individual so they all must be connected in series. Electricity MCQ Question 7. Two wires of same length and area made of two materials of resistivity ρ 1 and ρ 2 are connected in series to a source of potential V. The equivalent

resistivity for the same area is Answer/Explanation Answer: c Explanation: (c) For same length and area of cross-section R ∝ p. For series combination, equivalent resistance is Rs = R 1 + R 2 ⇒ Ps = ρ 1 + ρ 2

8. Two devices are connected between two points say A and B in parallel. The physical quantity that will remain the same between the two points is (a) current (b) voltage (c) resistance (d) None of these Answer/Explanation Answer: b Explanation: (b) In parallel combination, voltage remains same across two points.
9. The least resistance obtained by using 2 Ω, 4 Ω, 1 Ω and 100 Ω is a) < 100 Ω (b) < 4 Ω (c) < 1 Ω (d) > 2 Ω

Question 11. Calculate the current flows through the 10 Ω resistor in the following circuit. (a) 1.2 A (b) 0.6 A (c) 0.2 A (d) 2.0 A Answer/Explanation Answer: b Explanation: (b) In parallel, potential difference across each resistor will remain same. So, current through 10 Ω resistor I = VR=610 = 0.6 A

12. Two resistors are connected in series gives an equivalent resistance of 10 Ω. When connected in parallel, gives 2.4 Ω. Then the individual resistance are (a) each of 5 Ω (b) 6 Ω and 4 Ω (c) 7 Ω and 4 Ω (d) 8 Ω and 2 Ω Answer/Explanation Answer: b Explanation:

(b) In series, Rs = R 1 + R 2 = 10 Ω

13. If R 1 and R 2 be the resistance of the filament of 40 W and 60 W respectively operating 220 V, then (a) R 1 < R 2 (b) R 2 < R 1 (c) R 1 = R 2 (d) R 1 ≥ R 2 Answer/Explanation Answer: b Explanation: (b) Using power, P = V^2 /R or R = V2/P For the same voltage, R ∝ 1/P More the power, lesser the resistance. Accordingly, R 2 < R 1 Question 14. The resistance of hot filament of the bulb is about 10 times the cold resistance. What will be the resistance of 100 W-220 V lamp, when not in use? (a) 48 Ω (b) 400 Ω (c) 484 Ω (d) 48.4 Ω Answer/Explanation Answer: c Explanation:

Scottish High International School

Class: X ICSE (20 22 - 23 )

Subject: Physics

Worksheet – Calorimetry

Q1. Choose the correct answers to the questions from the given options. (i) The_____________ of a body is the amount of heat energy required to raise its temperature by 1 k (a) Heat (b) Temperature (c) Heat capacity (d) Latent heat (ii) Heat capacity per unit mass of a body is called (a) Latent heat (b) Specific heat (c) Heat energy (d)None of these (iii) What is the relation between specific heat capacity(C’) and heat capacity (c) of a body of mass m? (a) C’^ =c/m (b) C’^ = c x m (c) c = C’^ /m (d) c = m x C’ (iv) SI unit of specific heat capacity is: (a) Kg°C (b). J/kg°K (c) J/kg° (d) J/g°C (v) When some salt is added to water , the boiling point of it : (a) Decreases (b) Increases (c) No change (d) cannot find (vi) The specific heat capacity of water is: (a) 4.2 JKg-^1 K-^1 (b) 4200J g-^1 K-^1 (c) 0.24J g-^1 K-^1 (d) 4200 JKg-^1 K-^1 (vii) By imparting heat to a body, its temperature rises by 37°C. The corresponding rise in temperature on kelvin scale is : (a) 310 K (b) 236K (c)0K (d) 37 K (viii) The measurement of the quantity of heat is term: (a) Heat energy (b) Calorie (c) Calorimetry (d) Heat capacity

(ix) The specific heat capacity of a substance: (a) Changes with the mass of given substance. (b) Changes with the area or volume of substance. (c) Changes with rise or fall in temperature. (d) Is a constant quantity for a given substance? (x) How much heat energy is required to melt 4 Kg of ice at 0 °C? (The specific latent heat of fusion of ice is 336x10^3 J Kg-^1 ) (a) 1.344 x 10^3 J (b) 13.44 KJ (c) 1344KJ (d) 1344 J Q2. Answer the following questions: (i) Give two reasons as to why copper is preferred over other metals for making calorimeters. (ii) A liquid P has the maximum specific heat capacity and used as a coolant in car radiators. Name the liquid. (iii) How do you reduce heat loss due to conduction and convection in a calorimeter? (iv) State in brief: (a) The heat capacity of a body is 139 J °C-^1. (b) The specific latent heat of fusion of ice is 336 Jg-^1. (c) The specific heat capacity of copper is 390 JKg-^1. (v) What is the principle of method of mixtures? Name the law on which this principle is based.