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A collection of physics problems and their detailed solutions, covering fundamental concepts in mechanics, waves, and sound. The problems are designed to enhance understanding of key principles and provide practical applications. The solutions offer step-by-step explanations, making it an effective resource for students seeking to solidify their knowledge and problem-solving skills.
Typology: Assignments
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Physics โ Problems and solutions
1. A particle starts from the origin ๐๐ and moves in a horizontal plane with a constant acceleration (โ2,1) cm/s, respectively, the unit of distance being 1 cm on each axis. The initial velocity of the particle is (9, โ4). Show that the position vector of the particle after 5 seconds is (20, โ7.5); Find the position vector of the particle after ๐ก๐ก seconds, and hence show that the particle moves along the curve ๐ฅ๐ฅ 2 + 4๐ฅ๐ฅ๐ฅ๐ฅ + 4๐ฅ๐ฅ^2 โ 8 ๐ฅ๐ฅ โ 18 ๐ฅ๐ฅ = 0. 2. A cannon of mass ๐๐ 2 = 16 ร 10^3 kg is fixed on a movable platform of mass ๐๐ 3 = 3 ร 10^3 kg which is at rest on a rough floor. The elevated angle of the barrel is 60 ยฐ and the mass of the bomb is ๐๐ 1 = 50 kg. If the bomb is fired with speed ๐ฃ๐ฃ 1 relative to the barrel, the platform recoils a total distance of 3 m before it comes to rest in 6 seconds. Find ๐ฃ๐ฃ 1. What is the assumption you have made? And why you can make this? 3. A wave on a string is described by the following equation
๐๐ = (15 ๐๐๐๐) cos ๏ฟฝ 5 ๐๐๐๐๐๐ ๐ฅ๐ฅ โ 12 ๐๐ ๐ ๐ ๐ก๐ก๏ฟฝ (a) What is the amplitude of this wave? (b) What is its wavelength? (c) What is its period? (d) What is its speed? (e) In which direction does the wave travel?
4. A motorcycle and a police car are moving toward one another. The police car emits sound with a frequency of 512 Hz and has a speed of 27.0 m/s. The motorcycle has a speed of 13.0 m/s. What frequency does the motorcyclist hear? Suppose the motorcycle and police car are moving in the same direction, with the motorcycle in the lead. What frequency does the motorcyclist hear in this case?
Also, no net force acting on the system, conservation of momentum is obeyed.
๐๐ 1 ๏ฟฝ๐ฃ๐ฃ 1 cos 60ยฐ โ ๏ฟฝ^2 ๐ก๐ก ๐ ๐ โ ๐ฃ๐ฃ๏ฟฝ๏ฟฝ โ (๐๐ 2 + ๐๐ 3 )^ ๏ฟฝ^2 ๐ก๐ก ๐ ๐ โ ๐ฃ๐ฃ๏ฟฝ = 0
50(๐ฃ๐ฃ 1 cos 60ยฐ โ 1) = 19 ร 10^3 ๐ฃ๐ฃ 1 โ 762 ๐๐/๐ ๐
Amplitude = 15 ๐๐๐๐
Wavelength ๐๐ = 2๐๐๐๐ = (^) ๏ฟฝ2๐๐ ๐๐ 5 ๏ฟฝ = 10 ๐๐๐๐
Period ๐๐ = 2๐๐๐๐ = (^) ๏ฟฝ2๐๐ 12 ๐๐ ๏ฟฝ = 24 ๐ ๐
Speed ๐ฃ๐ฃ = ๐๐๐๐ = ((๐๐๐๐//^125 )) = 125 ๐๐๐๐ ๐ ๐ โ
The wave is travelling to the right