Polar Coordinates: Calculating Equations and Identifying Curves, Study notes of Calculus

The concept of polar coordinates, providing examples and equations for parabolas, ellipses, and hyperbolas. It covers the relationship between cartesian and polar coordinates, the rotation of axes, and the use of trigonometric functions.

Typology: Study notes

Pre 2010

Uploaded on 09/02/2009

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Polar Coordinates
Let P = (x,y) be a point of the plane different from the origin. Let (r, θ) be an ordered pair) be an ordered pair
of real numbers such that
θr, yθrx sincos
.
We say that (r, θ) be an ordered pair) is a set of polar coordinates for P.
Example Consider the curve defined in polar coordinates by
,
cos1
0
e
ed
r
where e and d are positive real numbers, and where
0
is a real number. Note that
.sinsincoscoscos
000
In the special case where
2
0
we have that
.sin
2
cos
We have that
.
sinsincoscos1
00
e
ed
r
Then
.sincos
.sincos
.sincos
.sinsincoscos
.sinsincoscos1
00
00
00
00
00
yxder
yxeedr
edyxer
edrrer
eder
Next we get that
1
y
x
P = (x,y)
r
θ) be an ordered pair
0
pf3
pf4

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Polar Coordinates Let P = (x,y) be a point of the plane different from the origin. Let (r, θ) be an ordered pair) be an ordered pair of real numbers such that

x  r cos  θ  , y  r sin θ .

We say that (r, θ) be an ordered pair) is a set of polar coordinates for P. Example Consider the curve defined in polar coordinates by  

1  cos    0

e ed r where e and d are positive real numbers, and where ^0 is a real number. Note that cos     0  cos  cos  0  sin  sin  0 . In the special case where (^02)    we have that sin  . 2 cos  (^)          We have that         

1  cos  cos  0 sin  sin  0

e ed r Then                                   cos   sin  .

cos sin.

cos sin.

cos cos sin sin.

1 cos cos sin sin.

0 0 0 0 0 0 0 0 0 0

r e d x y

r ed e x y

r e x y ed

r e r r ed

r e ed

Next we get that y x P = (x,y) r θ) be an ordered pair 0

                                            2 cos   sin  sin . 2 cos 2 sin cos cos sin sin sin cos sin cos sin cos cos cos sin cos sin cos sin 2 0 2 0 0 2 0 2 0 0 2 2 0 2 0 0 0 0 0 2 0 2 0 0 0 2 0 0 0 0 2 0 0 x y y d d x d y x x y d y x y y d d x d y d x x d x y d x y d x y      

Thus            2 sin   . cos 2 cos sin sin 2 cos 2 0 0 2 0 2 0 0 2 0 2 2 2 d y d r e x x y y d x     

Hence          2 cos   2 sin  . cos 2 cos sin sin 2 0 0 2 0 2 0 0 2 0 2 2 2 2 d x d y d x y e x x y y        

Therefore          sin   1  2 cos  2 sin  0.

cos 1 2 cos sin

2 2 0 2 0 2 2 0 2 2 0 0 2 2 0 2 2

e y e d x e d y e d

e x e x y

Now let       sin   1. cos 1 , 2 cos sin , 0 2 2 0 0 2 0 2 2  

C e A e B e Note that         cos^ ^ ^ sin ^ ^1. cos sin cos sin 1 2 0 2 0 4 2 0 2 2 0 2 2 0 2 0 4 2    

e e AC e e e  

Hence B^2  4 AC  4   e^2  1 . We now consider the possible cases for e. Case 1 e=1. Then B^2  4 AC  0. Now the curve is a parabola or a limiting form.

      ^ ^ ^ ^  ^ ^ ^  ^ ^ ^ 

2  cos   sin   2  cos  sin  sin  cos  0.

sin 1 sin 2 sin cos cos

2 cos sin cos sin cos sin sin cos

cos 1 cos 2 cos sin sin

2 2 0 0 0 0 2 0 2 0 2 2 0 2 2 0 0 0 2 2 2 2 0 0 2 0 2 0 2 0 0 2 0 0 2 0 2 2 0 0 0 2 2 2 2

e du edv e d

e u uv v

e u uv v

e u uv v

Collecting coefficients we get

 1 - e  2.

Thusfinally we get e cos sin 1 0 1 2 0.

cos sin sin 2 cos sin sin cos cos ( 2 sin cos 2 sin cos (( 2 cos sin 2 cos sin( )) 2 cos sin (cos sin ( )) cos cos 2 cos sin sin sin 2 2 2 2 2 2 (^222222) 0 2 0 2 2 2 2 2 2 0 2 0 2 0 2 2 0 2 0 2 2 0 2 0 2 0 2 2 0 0 0 0 2 3 0 2 0 2 0 0 2 0 0 0 0 2 3 2 0 2 0 2 4 0 2 0 2 2 0 2 0 2 4 u v edu e d u uv v edu e d so edu e d e e e v e uv e e e e e u    

                           