Math 106: Finding Third Degree Taylor Polynomial and Solving Integrals, Exercises of Calculus

Instructions for finding the third degree taylor polynomial approximation of a function and solving integrals. The first task involves calculating the derivatives of the function (x + 5)3/2 and determining the coefficients (ck) to find the polynomial. The second task requires selecting the best method to solve integrals with given functions using various substitutions. An example is provided for the first integral.

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Math 106 A and B circle your section Quiz 05 page 1 02/17/12 Name
1a. The following table has several (zero-th, first, second, third, etc.) derivatives for the function f(x) = (x+ 5)3/2.
Fill out just as much of the last two columns of this table as required to find find the third degree Taylor polynomial
approximation P3(x) of f(x), in powers of x+ 4, that is, with “base point” a=4. NOTE: Keep all the ck’s as fractions
(that is, in the form p/q) in reduced form (Don’t convert them to decimals)
Write your “assembled” polynomial in the blank space to the right of the table.
k f(k)(x)f(k)(a)ck
0 (x+ 5)3/2
13
2x+ 5
23
4
1
x+ 5
33
8(x+ 5)3/2
49
16 (x+ 5)5/2
2. For each of the following integrals, choose the best way to “do” the integral from the list below. Write the letter of
that choice in the box next to the integral. The first one is done as an example. If two choices are equally valid, write them
BOTH in the box!
Zx+ 2
x2+ 2x+ 1 dx Z Z(sin3x)(cos4x)dx Z(tan4x)(sec4x)dx
Z(sin4x)(cos4x)dx Zdx
x2x2+ 4
Choices:
Z) Let u=x2+ 2x+ 1 A) Let u= sin xB) Let u= cos xC) Let u= tan xD) Let u= sec x
E) Use “half angle” formulas F) Let x= 2 sin tG) Let x= 2 cos tH) Let x= 2 tan tI) Let x= 2 sec t
3. Suppose in some trig substitution problem, the substitution used was x= 4 sin tand the antiderivative in terms of tis
t/8 + cot t+C. What is the answer in terms of x?

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Math 106 A and B ←− circle your section Quiz 05 page 1 02/17/12 Name

1a. The following table has several (zero-th, first, second, third, etc.) derivatives for the function f(x) = (x + 5)^3 /^2. Fill out just as much of the last two columns of this table as required to find find the third degree Taylor polynomial approximation P 3 (x) of f(x), in powers of x + 4, that is, with “base point” a = −4. NOTE: Keep all the ck’s as fractions (that is, in the form p/q) in reduced form (Don’t convert them to decimals) Write your “assembled” polynomial in the blank space to the right of the table. k f(k)(x) f(k)(a) ck 0 (x + 5)^3 /^2 1 32 √x + 5

2 34 √x^1 + 5

3 − 83 (x + 5)−^3 /^2

4 16 9 (x + 5)−^5 /^2

  1. For each of the following integrals, choose the best way to “do” the integral from the list below. Write the letter of that choice in the box next to the integral. The first one is done as an example. If two choices are equally valid, write them BOTH in the box! ∫ x + 2 x^2 + 2x + 1 dx^ Z

(sin^3 x)(cos^4 x) dx

(tan^4 x)(sec^4 x) dx ∫ (sin^4 x)(cos^4 x) dx

∫ (^) dx x^2 √x^2 + 4 Choices: Z) Let u = x^2 + 2x + 1 A) Let u = sin x B) Let u = cos x C) Let u = tan x D) Let u = sec x E) Use “half angle” formulas F) Let x = 2 sin t G) Let x = 2 cos t H) Let x = 2 tan t I) Let x = 2 sec t

  1. Suppose in some trig substitution problem, the substitution used was x = 4 sin t and the antiderivative in terms of t is t/8 + cot t + C. What is the answer in terms of x?