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Portage Learning MATH 110 All Exams, Exams of Nursing

Chamberlain College of NursingNursing

Portage Learning MATH 110 All Exams Portage Learning MATH 110 All Exams Portage Learning MATH 110 All Exams

Typology: Exams

2024/2025

Available from 08/28/2025

nclexmaster
nclexmaster 🇺🇸

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1
Mod 1 Exam 1
1.
Define each of the following:
a) Observation
b) Element
c) Variable
Observation- all the information collected for each element in a study
Element- in a data set, the individual and unique entry about which data has been collected, analyzed and
presented in the same manner
Variable- a particular, measurable attribute that the researcher believes is needed to describe the element in
their study.
2.
Explain outliers
An outlier is a value which is out of place compared to the other values. It may be too large or too small
compared to the other values
3.
Look at the following data and see if you can identify any outliers:
53 786 789 821 794 805 63 777 814 2333 783 811 795 788 780
Outliers: 53 63 2333
4.
a) How many were burgers?
b) How many were fish?
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe
pff
pf12
pf13
pf14
pf15
pf16
pf17
pf18
pf19
pf1a
pf1b
pf1c
pf1d
pf1e
pf1f
pf20

Partial preview of the text

Download Portage Learning MATH 110 All Exams and more Exams Nursing in PDF only on Docsity!

Mod 1 Exam 1

  1. Define each of the following: a) Observation b) Element c) Variable Observation- all the information collected for each element in a study Element- in a data set, the individual and unique entry about which data has been collected, analyzed and presented in the same manner Variable- a particular, measurable attribute that the researcher believes is needed to describe the element in their study.
  2. Explain outliers An outlier is a value which is out of place compared to the other values. It may be too large or too small compared to the other values
  3. Look at the following data and see if you can identify any outliers: 53 786 789 821 794 805 63 777 814 2333 783 811 795 788 780 Outliers: 53 63 2333
  4. a) How many were burgers? b) How many were fish?
  • a) Burgers, 2900(0.12)=
  • b) Fish, 2900(0.28)=
  1. Consider the following data: 430 389 414 401 466 421 399 387 450 407 392 410 440 417 471 Find the 40th percentile of this data.
  2. Consider the following data: {29, 20, 24, 18, 32, 21} a) Find the sample mean of this data. b) Find the range of this data. c) Find the sample standard deviation of this data. d) Find the coefficient of variation. a.
  1. Suppose that you have a set of data that has a mean of 49 and a standard deviation of 8. a) Is the point 57 above, below, or the same as the mean. How many standard deviations is 57 from the mean. b) Is the point 33 above, below, or the same as the mean. How many standard deviations is 33 from the mean. c) Is the point 31 above, below, or the same as the mean. How many standard deviations is 31 from the mean. d) Is the point 79 above, below, or the same as the mean. How many standard deviations is 79 from the mean. a) The data point 57 is above the mean. Now use the z-score to determine how many standard deviations 57 is above the mean. We are told that the mean is 49 and the standard deviation is 8. So, the z-score is given by: The z-score is 1, so the data point 57 is 1 standard deviation above the mean. b) The data point 33 is below the mean. Now use the z-score to determine how many standard deviations 33 is below the mean. We are told that the mean is 49 and the standard deviation is 8. So, the z-score is given by: The z-score is - 2, so the data point 33 is 2 standard deviations below the mean (the negative sign indicates that the point is below the mean). c) The data point 31 is below the mean. Now use the z-score to determine how many standard deviations 31 is below the mean. We are told that the mean is 49 and the standard deviation is 8. So, the z-score is given by: The z-score is - 2.25, so the data point 31 is 2.25 standard deviations below the mean (the negative sign indicates that the point is below the mean). d) The data point 79 is above the mean. Now use the z-score to determine how many standard deviations 79 is above the mean. We are told that the mean is 49 and the standard deviation is 8. So, the z-score is given by:
  1. Consider the following set of data: {20, 5, 12, 29, 18, 21, 10, 15} a) Find the median. b) Find the mode of this set. a) In order to find the median, we must first put the numbers in ascending order: 5, 10, 12, 15, 18, 20, 21, 29. Notice that there are two “middle” numbers, 15 and 18. The median is the average of these two numbers. Median = (15+18)/2 = 16.5. b) No number occurs more than once, so there is “no mode”.

Exam 3

  1. Find the answer to each of the following by first reducing the fractions as much as possible: a) P(412,3)= b) C(587,585)=
  2. Suppose you are going to make a password that consists of 5 characters chosen from {1,2,4,9,d,i,k,m,n,w,z}. How many different passwords can you make if you cannot use any character more than once in each password?
  1. Suppose A and B are two events with probabilities: P(A)=.35, P(Bc^ )=.45, P(A∩B)=.25. Find the following: a) P(A𝖴B). b) P(Ac^ ). c) P(B). a. For P(A 𝖴 B). Use P(A 𝖴 B)=P(A)+P(B)-P(A∩B). But for this equation, we need P(B) which we can find by using P(B)=1-P(Bc^ ). So, P(B)=1-.45= .55. P(A 𝖴 B)=. 35 +. 55 -. 25 =. 65 b. For P(Ac^ ). Use P(A)=1-P(Ac^ ) which may be rearranged to (Ac^ )=1-P(A). P(Ac^ )=1-.35=.65. c. For P(B). Use (B)=1-P(Bc^ ). P(B)=1-.45=.55.
  2. Suppose A and B are two events with probabilities: P(Ac^ )=.50, P(B)=.65, P(A∩B)=.30. a) What is (A│B)? b) What is (B│A)?

Exam 4

  1. In a large shipment of clocks, it has been discovered that 21 % of the clocks are defective. Suppose that you choose 7 clocks at random. What is the probability that 2 or less of the clocks are defective.
  2. Find each of the following probabilities: (use standard normal distribution table to get z-score) a. Find P(Z ≤ 1.27). b. Find P(Z ≥ - .73). c. Find P(-.09 ≤ Z ≤ .86). a. P(Z ≤ 1.27) =0. b.P(Z ≥ - 0.73= 1 - P(Z ≤ - 0.73)=1- 0.23270=0. c. P(-0.09 ≤ Z ≤0 .86)= P(Z≤0 .86)- P(Z≤ - 0.09) 0.80511-0.46414=.
  3. A company manufactures a large number of rods. The lengths of the rods are normally distributed with a mean length of 4.0 inches and a standard deviation of .75 inches. If you choose a rod at random, what is the probability that the rod you chose will be: a) Less than 3.0 inches? b) Greater than 3.7 inches?

c) Between 3.5 inches and 4.3 inches?

  1. An archer is shooting arrows at a target. She hits the target 68% of the time. If she takes 15 shots at the target, what is the probability that she will hit the target exactly 12 times?

Exam 5

  1. Suppose that you take a sample of size 20 from a population that is not normally distributed. Can the sampling distribution of x̄ be approximated by a normal probability distribution? No because the sample has to be at least 30 to use sampling distribution of x̄ or be normally distributed.
  2. Suppose that you are attempting to estimate the annual income of 2000 families. In order to use the infinite standard deviation formula, what sample size, n, should you use? Your Answer: n N ≤ 0. n 2000 ≤ 0. n ≤ 0.05(2000)= Sample size must be less than 100
  3. Suppose that in a large hospital system, that the average (mean) time that it takes for a nurse to take the temperature and blood pressure of a patient is 150 seconds with a standard deviation of 35 seconds. What is the probability that 30 nurses selected at random will have a mean time of 155 seconds or less to take the temperature and blood pressure of a patient? We calculate the standard deviation of the sample distribution: Calculate the z-score: So, we want to find P(Z < .782) on the standard normal probability distribution table. Recall that P(Z < .78) = .78230. Therefore, there is a 0.78230 probability that a simple random sample of 30 nurses will have a mean time

of 155 seconds or less.

  1. Suppose that you are a nurse and you are assigned to do checkups of people one day per week in a certain village. You have a total of 300 patients in the village. You have the option of doing the checkups in the mornings or in the afternoons. Therefore, you ask 35 patients and find that 62% prefer afternoon appointments while 38% prefer morning appointments. Find the 95% confidence limit for the proportion of all patients that prefer afternoon appointments. Since 62% prefer afternoon, we set P = .62. As we mentioned previously, we estimate p by P. So, p=.62. The total population is 300, so set N=300. A total of 35 patients were surveyed, so Based on a confidence limit of 95 %, we find in table 6.1 that z=1.96. Now, we can substitute all of these values into our equation: So the proportion of the total who prefer afternoon appointments is between .469 and .771.

Exam 7

  1. a) Define the null and alternative hypothesis for the following. Also, explain what it would mean to make a Type I error and explain what it would mean to make a Type II error. The newspaper in a certain city had a circulation of 15,000 per day in 2010. You believe that the newspaper’s circulation is more than 15,000 today. b) Define the null and alternative hypothesis for the following. Also, explain what it would mean to make a Type I error and explain what it would mean to make a Type II error. A certain website had 3500 hits per month a year ago. You believe that the number of hits per month is less than that today. a. H 0 : μ =15,000 circulation H 1 : μ >15,000 circulation Type I error: Reject the null hypothesis that the mean of circulations is 15,000 even though it is correct. Type II error: Do not reject the null hypothesis when the mean of circulations is greater than 15, circulations. b. H 0 :μ =3500 hits H 1 :μ <3500 hits Type I error: Reject the null hypothesis even though the hits per month in a year are at least 3500.

Type II error: Do not reject the null hypothesis when the mean of hits per month is less than 3500.

Since this is a right-tailed test, and the z-score is greater than 2.05, we reject the null hypothesis.

Exam 8

Suppose we have independent random samples of size n 1 = 420 and n 2 = 510. The proportions of success in the two samples are p 1 = .38 and p 2 = .43. Find the 99% confidence interval for the difference in the two population proportions. Answer the following questions:

  1. Multiple choice: Which equation would you use to solve this problem? A. B. C. D.
  2. List the values you would insert into that equation.
  3. State the final answer to the problem From table 6.1, we see that 99% confidence corresponds to z=2.58. Notice that the sample sizes are each greater than 30, so we may use eqn. 8.2: B.