Combinatorics Exam 2 - MATH 0345, Exams of Mathematics

The solutions manual for exam 2 of the combinatorics course (math 0345) held on november 17, 2006. Six problems covering various topics in combinatorics, such as combinatorial proofs, newton's binomial theorem, opinion poll analysis, rook placements, and fibonacci numbers.

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Combinatorics - MATH 0345
Exam 2
November 17, 2006
Name:
Honor Code Pledge
Signature
Directions: Please complete all but 1 problem. If you complete all six problems, I
will count your best five.
1. Let nand kbe positive integers. Give a combinatorial proof that
Σn
k=1kn
k2
=n2n1
n1.
2. Given that 1/2
k=(1)k1
k22k12k2
k1, use Newton’s Binomial Theorem to approximate
40. (You may leave your answer as a sum.)
3. An opinion poll reports that the percentage of voters who would be satisfied with
each of three candidates A, B, C for President is 65%,57%,58% respectively. Further,
28% would accept Aor B, 30% Aor C, 27% Bor Cand 12% would be content with
any of the three. What do you conclude?
4. What is the number of ways to place six nonattacking rooks on the 6-by-6 boards
with forbidden positions as shown? (See opposite side. You may leave your answer
as a sum.)
5. Prove that the nth Fibonacci number fnis the integer that is closest to the number
1
5(1 + 5
2)n.
6. There are nseating positions arranged in a line. Prove that the number of ways
of choosing a subset of these positions, with no two chosen positions consecutive,
is fn+1 (the (n+ 1)th fibonacci number).
1
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Combinatorics - MATH 0345

Exam 2

November 17, 2006

Name: Honor Code Pledge

Signature Directions: Please complete all but 1 problem. If you complete all six problems, I will count your best five.

  1. Let n and k be positive integers. Give a combinatorial proof that

Σnk=1k

n k

= n

2 n − 1 n − 1

  1. Given that

k

k− 1 k 22 k−^1

( 2 k− 2 k− 1

√ , use Newton’s Binomial Theorem to approximate

  1. (You may leave your answer as a sum.)
  2. An opinion poll reports that the percentage of voters who would be satisfied with each of three candidates A, B, C for President is 65%, 57%, 58% respectively. Further, 28% would accept A or B, 30% A or C, 27% B or C and 12% would be content with any of the three. What do you conclude?
  3. What is the number of ways to place six nonattacking rooks on the 6-by-6 boards with forbidden positions as shown? (See opposite side. You may leave your answer as a sum.)
  4. Prove that the nth Fibonacci number fn is the integer that is closest to the number

)n.

  1. • There are n seating positions arranged in a line. Prove that the number of ways of choosing a subset of these positions, with no two chosen positions consecutive, is fn+1 (the (n + 1)th^ fibonacci number).
  • If the n positions are arranged around a circle, show that the number of choices is fn + fn− 2 for n ≥ 2.