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In this practical laboratory session, students will learn how to measure the emission spectrum of a heated gas using a digital spectrometer and identify the unknown gas based on its unique emission pattern. The theory behind emission and absorption spectra, as well as the relationship between energy and wavelength of photons, will be explored.
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We see very differently than we hear. With sound, we are able to pick out many different frequencies, i.e. different pitches. For example, if we listen to music, we can pick out the drums and voice separately, even though they are happening at the same time. We don’t have that capability with light. Instead, we end up seeing one individual color, which most likely is made up of many different wavelengths of light. The electromagnetic spectrum, shown in Fig. 2.1, covers a huge range of wavelengths, from gamma rays at 10 −^14 m to AM radio waves at 104 m. In this lab we are going to be concerned with the narrow band of wavelengths, ∼ 400 − 750 nm (a nm = 10 −^9 m), that make up visible light. In order to
161
Figure 2 .1: Theelectromagnetic spectrum with the visible light regionblown up.
know very accurately what wavelengths are being emitted by a source of light, we will use a digital spectrometer.
In last week’s lab you saw evidence of light behaving as a wave. In this lab we will explore light acting as a particle, called a photon. Sunlight and incandescent light (such as from a lightbulb) are sometimes called “white” light as they are made up of many wavelengths of light (all the colors mixed together make white). If you shine white light through a prism it spreads the light out into a rainbow because different wavelengths of light have slightly different indexes of refraction, called dispersion. If you heat up a gaseous element, such as hydrogen, until it glows and send that
Figure 2 .3: Model of an atom showing absorption and emission of photons.
The periodic table of the elements is also explained by the atomic model, where every element is uniquely identified by the number of protons in its nucleus. Quantum mechanics explains the energy states of the electrons in an atom. Every element in the periodic table has a distinct set of electron energy levels, so for a given element only photons of specific energies can be emitted. Therefore, when you are measuring the emission spectrum of an element, only certain wavelengths of light are allowed and the “pattern” that is produced is unique f or that substance. The spectrum of various gases and phosphors are shown in Fig. 2 .4.
The energy of an emitted photon and its wavelength are related. For example, the color of a laser pointer (e.g. red or green) is determined by the energy of the emitted light. The energy of a photon is described by the equation:
E =
hc λ
where λ is the wavelength in meters, h is the Planck constant (h ≈ 6. 63 × 10 −^34 J s), and c is the speed of light (c ≈ 3. 00 × 108 m/s). When dealing with visible light, wavelengths are usually given in nanometers (nm) so it
Figure 9.4: Emission spectra for various elements and phosphors
is convenient to convert the quantity hc into units of electron volts (eV)^2 and nm. Equation 2 .1 can now be written as:
hc λ
1240 eV nm λ
where λ is the wavelength in nm and the energy of the photon is in eV.
(^2) An electron volt (eV) is the amount of energy it takes to move an electron through one volt of potential so 1 eV = U = qV = (1. 6 × 10 −^19 C)(1 V) = 1. 6 × 10 −^19 J.
Figure 2 .8: Thedigital spectrometer with a white USB cable and blueoptical fiber plugged in.
You will investigate the spectrum of ONE unknownlight source, in the gas discharge tube box labeled with a letter from A to E.
Gas discharge tube — The gas may take some time to heat up and emit its complete spectrum; so after turning it on, wait about 3 minutes before making your observations. Do not leave the tube on after making your measurements.
Last updated January 10, 2015 169
1. List the wavelength and uncertainty of the peaks you found in thecolor spectrum.
Color:
λ±δλ (nm): " :
Light Source
hydrogen gas^ Color:
Wavelength (nm):
Violet Blue ^ Green^ Yellow Orange^ Red
helium gas^ Color:
Wavelength (nm):
Violet Blue ^ Green^ Yellow Orange^ Red
neon gas Color: Violet Blue _ Green (^) Yellow Orange Red_
Wavelength (nm): " : 540 588
mercury gas Color: Violet Blue _ Green (^) Yellow Orange Red_
Wavelength (nm): " :
krypton gas Color: Violet Blue _ Green (^) Yellow Orange Red_
Wavelength (nm): " :
2. From the Table below which gas has peaks that are closest to your measurments? ANS: ______________________________
unknown gas Violet Blue _ Green (^) Yellow Orange Red_
Table of brightest lines in the spectrum of various gases
(^3). List peaks inconsistent with your gas choice (NONE if there are none) ________________
Phy25 2 Spring 2015 Practical Laboratory 2: Emission Spectra
4. (^) For a line with a wavelength of (λ±δλ) nm, calculate the energy and its uncertainty for
the photon emitted, in electron-volts and in joules (Ref. Eq. 2.2) using scientific notation.
Show calculations below. _______________eV ________________J