MATH 203 Test 3 Review: Hypothesis Testing and Chi-Square Distribution, Exams of Statistics

Problems related to hypothesis testing using the z-test and the chi-square distribution. Topics include testing mean differences between two groups, testing proportions, and calculating probabilities and confidence intervals for chi-square distributions.

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Pre 2010

Uploaded on 07/29/2009

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MATH 203 Test 3: Part I โ€“ No Calc. Review Problems
1. Below are sample data on SAT scores for college-bound students. The scores are
assumed to be normally distributed and the given โ€™s are based on past tests. Let
1
be the true average SAT score among all college-bound females and let
2
be the true
average SAT score among all college-bound males.
n
x
Females 300 1079.6 180
Males 250 1040.5 150
(a) Test H0:
1=2
vs. Ha:
1>2
. Use
the
P
-value to explain the conclusion in detail.
(b) Test H0:
1โˆ’2
= 40 vs Ha:
1โˆ’2
< 40.
Use the
P
-value to explain the conclusion in
detail.
(c) Give the numerical formula for the test statistic in Part (b) and state the distribution
that it follows.
(d) If the scores were not assumed to be normal, or if we had to use
S
values instead,
why could we still use a 2Sample Zโ€“Test?
โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“
2. A survey of WKU faculty found that 110 out of 200 (55%) oppose having a Winter
term. A survey of staff found that 58 out of 100 (58%) oppose it. Let p
1
be the true
proportion of faculty who oppose and let p
2
be the true proportion of staff who
oppose. Use the screens below to see if there is enough evidence to reject the
hypothesis that the proportions in opposition are equal.
(a) State the null hypothesis and give an appropriate one-sided alternative.
(b) Assuming the null hypothesis is true, give the fraction form of the โ€œpooled
estimateโ€ of the proportion of Faculty/Staff in opposition to Winter Term.
(c) Show how to find the test stat in this case and state the distribution that it follows.
(d) For your alternative in Part (a), use the appropriate
P
-value to explain your
conclusion about H0 in detail using = 0.05.
(e) To test H0: p
1
โ€“ p
2
= โ€“0.05, what is the appropriate alternative and what is the test
statistic? Explain if you can reject H0 at the 0.05 level of significance.
pf3
pf4

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MATH 203 Test 3: Part I โ€“ No Calc. Review Problems

  1. Below are sample data on SAT scores for college-bound students. The scores are assumed to be normally distributed and the given โ€™s are based on past tests. Let (^1)

be the true average SAT score among all college-bound females and let 2 be the true average SAT score among all college-bound males.

n (^) x Females 300 1079.6 180 Males 250 1040.5 150

(a) Test H 0 : 1 = 2 vs. Ha : 1 > 2. Use

the P -value to explain the conclusion in detail.

(b) Test H 0 : 1 โˆ’ 2 = 40 vs Ha : 1 โˆ’ 2 < 40.

Use the P -value to explain the conclusion in detail.

(c) Give the numerical formula for the test statistic in Part (b) and state the distribution that it follows. (d) If the scores were not assumed to be normal, or if we had to use S values instead, why could we still use a 2Sample Zโ€“Test? โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“

  1. A survey of WKU faculty found that 110 out of 200 (55%) oppose having a Winter term. A survey of staff found that 58 out of 100 (58%) oppose it. Let p 1 be the true

proportion of faculty who oppose and let p 2 be the true proportion of staff who oppose. Use the screens below to see if there is enough evidence to reject the hypothesis that the proportions in opposition are equal.

(a) State the null hypothesis and give an appropriate one-sided alternative.

(b) Assuming the null hypothesis is true, give the fraction form of the โ€œpooled estimateโ€ of the proportion of Faculty/Staff in opposition to Winter Term.

(c) Show how to find the test stat in this case and state the distribution that it follows.

(d) For your alternative in Part (a), use the appropriate P -value to explain your conclusion about H 0 in detail using = 0.05.

(e) To test H 0 : p 1 โ€“ p 2 = โ€“0.05, what is the appropriate alternative and what is the test

statistic? Explain if you can reject H 0 at the 0.05 level of significance.

Part II โ€“ Calculators Allowed

  1. Compute probabilities and bounds of a specific chi-square distribution. The chart of the chi-square scores will be provided.

(a) Compute and show a shaded graph the following probabilities. Also label the x - value where the maximum of the distribution curve occurs:

(i) P (12 โ‰ค 2 (19) โ‰ค 25) (ii) P ( 2 (17) โ‰ค 20) (iii) P ( 2 (22) โ‰ฅ 20)

(b) Use the Chi-Square Score Chart to give L and R such that

(i) P L ( โ‰ค 2 (19) โ‰ค R ) = 0.90 (ii) P L ( โ‰ค 2 (17) โ‰ค R ) = 0.95 (iii) P L ( โ‰ค 2 (22) โ‰ค R ) = 0.

  1. Packaged weights of Cheer detergent are normally distributed with mean of 53 ounces and a standard deviation 0.9 ounces.

(a) Suppose various random samples of size 40 are collected. Compute P (0.81 โ‰ค S โ‰ค 0.99).

(b) Suppose is unknown, but a random sampling of 30 packages yields S = 0.76. Find a 95% confidence interval for the true standard deviation.

(c) Using S = 0.86 from a sample of 30 packages, is there evidence at the 10% level of significance, to reject the claim that = 0.9? State initial and alternative hypotheses, give the test-statistic and P -value, and use the P -value to explain your conclusion in detail. What about if S = 1.1 from a sample of size 30?

โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“

  1. A report claims that consumer preferences for wireless communications are

Sprint Verizon T-Mobile Cingular AT&T Other 15% 18% 20% 16% 6% 25%

However a random telephone poll of 1200 adults in Kentucky gave the following preferences:

Sprint Verizon T-Mobile Cingular AT&T Other 150 210 220 200 70 350

(a) If the report were correct for Kentucky consumers, then what would be the expected numbers of preferences for each category?

(b) To test the goodness of fit, compute the Pearson test statistic and the P -value.

(c) Is there significant evidence to reject the reportโ€™s claim with regard to consumers in KY? Use the P -value to explain your conclusion.

โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“โ€“

(h) A chi-square test is to be conducted on the entire data table to see if the same proportions exist in each group for each category. If that were the case, then how many responses would you expect in the following four categories:

Instruction Campus Activities Freshman

Junior

(i) What is the P -value for the test? Do you conclude that choice of issue is independent or dependent of the class? If dependent, then give an example of two classes whose proportions on an issue are clearly different.