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subject: prob and stats, year 2026, course intro to prob and stats
Typology: Cheat Sheet
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[12pt]article amsmath, amssymb geometry margin=1in
Theorem 2.3 (Conditional Probability)
P (A|B) = P^ ( PA (^ ∩B^ )B ), P (B) > 0
Multiplication Rule
P (A ∩ B) = P (A|B)P (B)
Independence P (A ∩ B) = P (A)P (B)
Theorem 2. P (B) =
i
P (B|A i )P (A i )
Theorem 2.5 (Bayes)
P (A i |B) = ∑P^ (B|A i )P^ (A i ) j P^ (B|A j^ )P^ (A j^ )
f X (x) =
y
f (x, y)
Cov(X, Y ) = E[XY ] − E[X]E[Y ]
ρ = Cov σ X (X, Y σ Y^ )
A disease affects 4% of a population. If infected, the test is positive 95% of the time. If not infected, the test is positive 8% of the time. Find P (D|+).
A component succeeds with probability 0.7 independently. In 12 trials:
Let X ∼ N (80, 16).
Given pmf:
x 1 2 3 P (X = x) 0. 2 0. 5 0. 3 Compute E[X] and V ar(X).
Joint pmf:
y = 0 y = 1 x = 0 0. 3 0. 2 x = 1 0. 1 0. 4