




















































Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
Various topics related to probability distribution and binomial distribution. It includes questions and explanations on concepts such as expected value, probability, variance, standard deviation, and normal approximation to the binomial distribution. A comprehensive understanding of these statistical concepts and their applications in various scenarios. It could be useful for students studying topics in probability, statistics, and decision analysis at the university level.
Typology: Exams
1 / 60
This page cannot be seen from the preview
Don't miss anything!





















































x x
x
Explanation (a) μ x = 0 × .02 + 1 × .18 + 2 × .18 + 3 × .46 + 4 × .09 + 5 × .07 = 2. (b) σ 2 = (0-2.63)^2 × .02 + (1-2.63)^2 × .18 + (2-2.63)^2 × .18 + (3-2.63)^2 × .18 + (4-2.63)^2 ×. 46 + (5-2.63)^2 ×. = .1383 + .4782 + .0714 + .0630 + .1689 + .3932 = 1.
(c) σ x = SQRT(1.31) = 1.
Explanation Mean = np = 12(.37) = 4. Standard Deviation = √( npq ) = √*(12)(.37)(.63)+ = 1.
X P(X) 3 1/ 4 1/ 5 3/ 6 3/
What is the expected value of X?
Explanation
E [ X ] = 3 ( 1 / 8 )+ 4 ( 1 / 8 )+ 5 ( 3 / 8 )+ 6 ( 3 / 8 )= 40 / 8 = 5.
Explanation Most of the values for this binomial distribution are on the left-hand side of the graph.
X P ( X ) 0 5/ 1 4/ 2 1/ 3
Explanation
All values of P ( X ) need to sum to 1, so 5/15 + 4/15 + 1/15 = 10/15 means P ( X = 3) = 5/15.
left skewed
P ( X ) = n !/[ x !( n − x )!] × px (1 − p ) n − x , for x = 4, when p = .20 and n = 30.
Compute the variance value of X.
Explanation E[X] = (1)(.1) + (2)(.5) + (3)(.2) + (4)(.2) = 2. σ 2 xσ2x = (1 − 2.5)^2 (.1) + (2 − 2.5)^2 (.5) + (3 − 2.5)^2 (.2) + (4 − 2.5)^2 (.2) =.
Explanation
N is the number of trials in an experiment and x is the number of successes in that experiment.
Explanation Σ P ( X ) = n !/[ x !( n − x )!] × px (1 − p ) n−x , for x = 1, 3, 5; or look up in binomial table where x = 1 or 3 or 5 when p = .5 and n = 10.
Explanation
Where n is the number of trials, p is the number of successes and q is the number of failures.
Explanation Mean = np = 50(.64) = 32
Excel Output of the Binomial Distribution with n = 24, p = .04, and q =.
Binomial distribution with n = 24 and p =.
x P ( X = x ) 0 0. 1 0. 2 0. 3 0. 4 0.
P ( x ≥ 2) = 1 – P ( x ≤ 1) = 1 – .7509 =.
Explanation P ( X = 5) = (.4)^5 =.
(b) For each value of x , calculate p ( x ). (Round final answers to 4 decimal places.)
(c) Find P ( x = 3). (Round final answer to 4 decimal places.)
(d) Find P ( x ≤ 3). (Do not round intermediate calculations. Round final answer to 4 decimal places.)
(e) Find P ( x < 3). (Do not round intermediate calculations. Round final answer to 4 decimal places.)
(f) Find P ( x ≥ 4). (Do not round intermediate calculations. Round final answer to 4 decimal places.)
(g) Find P ( x > 2). (Do not round intermediate calculations. Round final answer to 4 decimal places.)
p.
Explanation All trials are independent and you do not replace once you have a success or failure.
Explanation P ( X ) = n !/[ x !( n − x )!] × px (1 − p ) n−x , for x = 0 when p = .19 and n = 20.
Explanation μx = (−30)(.15) + (120)(.85) = −4.50 + 102 = 97.
Explanation
The random variable of interest needs to be discrete.
Explanation P ( x ≥ 5) = .0319 + .0089 + .0020 + .0004 + .0001 =.
P ( X ) = n !/[ x !( n − x )!] × px (1 − p ) n−x , for x = 10, when p = .19 and n = 20.
Explanation
Binomial standard deviation = σ = √( npq ) = √*(36)(.5)(.5)+ = √9 = 3
(2) Use the binomial formula to calculate the probability that at least three customers make a purchase. (Round your answer to 4 decimal places.)
(3) Use the binomial formula to calculate the probability that two or fewer customers make a purchase. (Round your answer to 4 decimal places.)
(4) Use the binomial formula to calculate the probability that at least one customer makes a purchase. (Round your answer to 4 decimal places.)
Explanation
(1) P ( x = 5) =.
(2) P ( x ≥ 3) = 1 – P ( x ≤ 2) = 1 – .4618 =.
(3) P ( x ≤ 2) =.
(4) P ( x ≥ 1) = 1 – P ( x = 0) = 1 – .0308 =.
Explanation
E [ X ] = 1 ( 1 / 6 )+ 2 ( 1 / 6 )+ 3 ( 1 / 6 )+ 4 ( 1 / 6 )+ 5 ( 1 / 6 )+ 6 ( 1 / 6 )
Explanation σ^2 = (5)(.4)(.6) = 1.
Explanation Σ P ( X ) = n !/[ x !( n − x )!] × px (1 − p ) n−x , for x = 0, 1, 2, 3 when p = .25 and n = 6.
Explanation Yes the probability is greater than 0.05 and therefore we do not reject the null hypothesis.
Explanation It could take someone infinite number of minutes to finish the 1 mile.
Explanation It is similar to a bell curve.
Multiple Choice
-. Correct -. -. -. Explanation
P ( X ≥ 2) = 1 − [ P ( X = 0) + p ( X = 1)] = 1 − [.3585 + .3774] =.
Explanation
Expected return = ( 0 )( 1 / 8 )+($2)( 1 )( 3 / 8 )+($2)( 2 )( 3 / 8 )+($2)( 3 )( 1 / 8 )= 3.
left skewed
Explanation
Probability of losing = 1 − probability of winning = 1 − 1/50 = 49/50.
Explanation This looks similar to a normal distribution.
Explanation μx = .7(−75,000) + .3(325,000) = −52,500 + 97,500 = 45,