Probability Distribution Functions in Quantum Mechanics and Statistics - Prof. Lucien M. C, Study notes of Quantum Mechanics

An introduction to probability distribution functions (pdfs) in quantum mechanics and statistics. It discusses the interpretation of the square of the quantum mechanical wave function as a probability distribution, the concept of normalization, discrete and continuous pdfs, moments of a pdf, and combining probabilities using or and and. Examples are given using the boltzmann distribution and dice rolls. The document also introduces the concept of a general weighted average of a function using moments.

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Uploaded on 09/24/2009

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Chapter-2 Probab ility Distribution Functions
The square of the quantum mechanica l wave function P(x) = Ψ∗Ψ is interpreted as a probability
distribution in quan tum mechanics.
More formally a probability distribution function (PDF), P( x), can be descr ibed in terms of the number of
similar systems
Ω
(x) in a large ensemble of systems Ω(N), where P(x) is the probability of obtaining
outcome ‘x’ when
Ω
(N) is sampled , tested measured, etc.
P(x)=lim
!(N)"#
!(x)
!(N)
Normalization
The PDF must be normalized over it's domain of definition
.
Pi(x)
! =1 or P(x)=1
a
b
"
Discrete PDFs
A discrete PDF may occur from random sampling of
Ω
(N) to obtain similar outcomes
Ω
(x).
Consider the discrete distribution of th e # of events vs x=0-10 eg.
* N = 19
* * * P(0) =1/19 P(5) = 3/19
* * * * * * P(1) =2/19 P(6) = 2/19
* * * * * * * * * P(2) =4/19 P(7) = 1/19
0 1 2 3 4 5 6 7 8 9 P(3) =3/19 P(8) = 1/19
x P(4) =2/19 P(9) = 0/19
Normalization = 1/N
P(x)=
0
9
!
P(0) + P(1) + ...........+P(9) = 1
Continuous Distributions
Continuous PDFs may come from theoretical predictions or fitting a discrete PDF to a continuous form. In
the later case one may argue that we have used our best estimate of the PDF and we will have to consider it
being approximate.
Consider the norm alization of the Boltzmann distribution
P
Boltzmann(E)=Ae!E/kT 0 "E" #
A e!E/kT dE =
0
"
# 1 , A!kT
( )
e!E/kT |0
"=1
A=1
kT
Moments of a PDF
The moments of a PDF are the weighted average of powers of variable ‘x’ taken with the PDF.
< xn> =
<xn>= xn!
"P(x)
or
The zeroth moment is the normalization condition:
1)
<x0>= 1
P(x)
pf3

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Chapter- 2 Probability Distribution Functions The square of the quantum mechanical wave function P(x) = Ψ∗Ψ is interpreted as a probability distribution in quantum mechanics. More formally a probability distribution function (PDF), P(x) , can be described in terms of the number of similar systems Ω (x) in a large ensemble of systems Ω(N), where P(x) is the probability of obtaining outcome ‘ x ’ when Ω (N) is sampled, tested measured, etc. P ( x ) = (^) !(l N im)"#!^ !(( Nx )) Normalization The PDF must be normalized over it's domain of definition

.! Pi ( x )= 1 or P ( x ) = 1

a

b

Discrete PDFs A discrete PDF may occur from random sampling of Ω (N) to obtain similar outcomes Ω (x). Consider the discrete distribution of the # of events vs x=0-10 eg.

  • _N = 19
          • _^ _ _^ __^ P(0) =1/19P(1) =2/19^ _P(5) = 3/19P(6) = 2/
                • *_ 0 1 2 3 4 5 6 7 8 9 (^) P(2) =4/19P(3) =3/19 P(7) = 1/19P(8) = 1/ x P(4) =2/19 P(9) = 0/ Normalization = 1/N

P ( x ) = 0

9

!^ P(0) + P(1) + ...........+P(9) = 1

Continuous Distributions Continuous PDFs may come from theoretical predictions or fitting a discrete PDF to a continuous form. In the lat being approximate.er case one may argue that we have used our best estimate of the PDF and we will have to consider it Consider the normalization of the Boltzmann distribution PBoltzmann ( E ) = Ae! E^ /^ kT^ 0 " E " #

A 0 " # e! E^ /^ kT^ dE = 1 , A (! kT ) e! E^ /^ kT^ | 0 "^ = 1

A = (^) kT^1 Moments of a PDF The moments of a PDF are the weighted average of powers of variable ‘ x’ taken with the PDF.

< xn> = < xn^ >= " xn^! P ( x ) or " xn^! P ( x ) dx

The zeroth moment is the normalization condition: 1) < x^0 >= 1

P(x)

Mean, Variance, and r.m.s, skewness, kurtosis It is useful to define the mean, variance, and root mean square of a PDF in terms of the moments.

2) mean

< x > = ! x P ( x ) dx = " x Pn ( x )

3) s = variance < (x-) (^2) > = < x (^2) - 2x+ (^2) > = < x^2> - 2<x>+<> = < x^2> - 2 + s = < x^2 >! < x >^2 4) r.m.s. σ =

s =

< x^2 >! < x >^2

Combining Probabilities: OR and AND (independent events) Case of OR : If I ask what is the probability that a measurement x=a OR x=b is made on subsequent trials then: P ( a | b ) = P ( a ) + P ( b ) + Cov ( a , b ) !# " = 0 #$ Example: Dice 2 or 3: P2|3) = 1/6/+ 1/6= 1/ Case of If I ask what is the probability that a measurement AND : x=a AND x=b is made on subsequent trials then: P ( a! b ) = P ( a )i P ( b ) Example: Dice 2 and 3: P(2+3) = 1/6 * 1/6= 1/ Russian Roulette N times Pn^ Survival^ =! "#^56 $ %&^! "#^56 $ %&^! "#^56 $ %&^! "#^56 $ %& .... =! "#^56 $ %&

n

5) We can define the weighted average of a general wel General f(x) l defined function f(x) in terms of moments as :

< f ( x ) > = < a + bx + x^2 + + x^3 + .... > = a + b < x > + c < x^2 > + d < x^3 > +......