Problem on Phase Circuit with Three Phase Transforms - Assignment 3 | ECE 3364, Assignments of Microelectronic Circuits

Material Type: Assignment; Professor: Hebert; Class: Circuits and Systems; Subject: (Electrical and Comp Engr); University: University of Houston; Term: Spring 2009;

Typology: Assignments

Pre 2010

Uploaded on 08/19/2009

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ECE 3364 HW 8, Spring 09, due 4/1
Problem 1.
Zline2
jwM
B
C
A
B
C
ZL-Y
N
ZL-Y
ZL-Y
A
bZline1
cZline1
a
Zline1
+
-
a’
n
b’
c’
+
-
+
-
ZS
ZS
ZS
v
a’n
~
v
c’n
~v
b’n
~
Zline2
Zline2
a
b
c
+
-
V
ab
~I
ab
~
I
aA
~
N
jwL
1
R
1
R
2
Zline2
Zline2
jwM
B
C
A
B
C
ZL-Y
ZL-Y
N
ZL-Y
ZL-Y
ZL-Y
ZL-Y
A
bZline1
Zline1
cZline1
Zline1
a
Zline1
Zline1
+
-
+
-
a’
n
b’
c’
+
-
+
-
+
-
+
-
ZS
ZS
ZS
ZS
ZS
ZS
v
a’n
~
v
a’n
v
a’n
~
v
c’n
~
v
c’n
v
c’n
~v
b’n
~
v
b’n
v
b’n
~
Zline2
Zline2
Zline2
Zline2
aa
bb
cc
+
-
V
ab
~
V
ab
V
abab
~I
ab
~
I
abab
~
I
aA
~
I
aA
~
N
jwL
1
jwL
1
R
1
R
1
R
2
R
2
Balanced 3 phase circuit with a three phase
Δ
Y
transformer.
rmsna VV o
01200
~
'=
22 jZs+=
510
1jZline +=
84
11 jLjR +=+
ω
146
22 jLjR +=+
ω
9=M
ω
14
2jZline +=
16112 jZ YL =
Find ba
I, the current in the secondary windings.

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ECE 3364 HW 8, Spring 09, due 4/

Problem 1.

jwM Z (^) line

B

C

A

B

C

Z L-Y

N

Z L-Y

Z

L-Y

A

b Z^ line

c Z^ line

a

Z (^) line

a’

n

b’

c’

Z

S

Z S

Z

S v (^) a’n

v (^) c’n

~ (^) v b’n

Z

line

Z (^) line

a

b

c

Vab

I

ab

I (^) aA

N

jwL 1

R (^1)

R (^2)

jwM ZZ (^) line2line

B

C

A

B

C

ZZ L-YL-Y

N

ZZ L-YL-Y

Z

L-Y

Z

L-Y

A

b ZZ^ line1line

c ZZ^ line1line

a

ZZ (^) line1line

a’

n

b’

c’

Z

S

Z

S

ZZ SS

Z

S

Z

S v (^) a’n

vv (^) a’na’n

v (^) c’n

vv (^) c’n (^) c’n

~ (^) v b’n

vv (^) b’nb’n

Z

line

Z

line

ZZ (^) line2line

aa

bb

cc

Vab

VVababab

I

ab

I

abab

I (^) aA

I (^) aA

N

jwLjwL 11

RR (^1 )

RR (^2 )

Balanced 3 phase circuit with a three phase Y −Δtransformer.

V (^) a n V rms

o 1200 0

~ ' = ∠

Z (^) s = 2 + j 2

Z (^) line 1 = 10 + j 5

R 1 (^) + j ω L 1 = 4 + j 8

R 2 (^) + j ω L 2 = 6 + j 14

ω M = 9

Z (^) line 2 = 4 + j 1

Z (^) LY = 112 − j 16

Find ab I , the current in the secondary windings.