Problem Set 4 - Electrical Circuit Analysis I | EE 213, Assignments of Electrical Circuit Analysis

Material Type: Assignment; Professor: English; Class: ELECTRICAL CIRCUIT ANALYSIS I; Subject: Electrical Engineering; University: University of Alabama - Huntsville; Term: Unknown 1989;

Typology: Assignments

Pre 2010

Uploaded on 07/23/2009

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EE 213 – Problem Set #4
1. Consider the following circuit and simplify it by making series and parallel combinations.
Then expand the circuit and solve for the current IX and Iy.
+
-
5
10V
5
10 40
3
Ix
8
100
Iy
2. Consider the following circuit and simplify the circuit to one resistor connected to the
voltage source. Then, expand the circuit and solve for the voltage, VX.
+
-4
12 V
VX
+
6
3
2
6
3. For the given circuit use the expansion/contraction technique to solve for the labeled
voltages and currents.
+
-
8
10 V
+
VX
17
40
6
+
VY
16
4IX
10 Ω
12
pf3

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EE 213 – Problem Set #

  1. Consider the following circuit and simplify it by making series and parallel combinations. Then expand the circuit and solve for the current IX and Iy.

5 Ω

10V

5 Ω

10 Ω 40 Ω

3 Ω

Ix

8 Ω

100 Ω

Iy

  1. Consider the following circuit and simplify the circuit to one resistor connected to the voltage source. Then, expand the circuit and solve for the voltage, VX.

12 V

VX

  1. For the given circuit use the expansion/contraction technique to solve for the labeled voltages and currents.

8 Ω

+^ 10 V VX −

17 Ω

40 Ω

6 Ω

VY −

16 Ω

4 Ω IX

10 Ω 12 Ω

  1. Consider the following circuit, (a) Using Nodal Analysis solve for the voltage VX and (b) using Mesh Analysis, solve for the voltage VX. Show that you get the same answer for VX.

2 A

6 Ω

3 Ω

2 Ω

  • 10 V
  • V (^) X -

2 Ω

6 V

  1. Consider the following circuit, (a) Using Nodal Analysis solve for the currents I 1 and IX and (b) using Mesh Analysis, solve for the currents I 1 and IX. Show that you get the same answers. 60 V

2A

10 Ω

20 Ω

2I 1

Ix

-^ +

30 Ω I 1

  1. Consider the following circuit, (a) Using Nodal Analysis solve for the current IO and (b) using Superposition, solve for the current IO. Show that you get the same answers.

12 V 2A

2 Ω

1 Ω

-^ +

2 Ω IO

4 A