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Material Type: Assignment; Class: Quantum Physics I; Subject: Physics; University: Michigan State University; Term: Fall 2006;
Typology: Assignments
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Physics 471 Problem Set 4 Fall 2006
Ψ(x, 0) = A sin^3 (πx/a).
(a) Normalize Ψ(x, 0). (b) Express Ψ(x, 0) in terms of the energy eigenstates
ψn(x) =
√ 2 a
sin(nπx/a) , n = 1, 2 , 3 , · · · ,
as Ψ(x, 0) =
∑ n
Cnψn(x).
Hint: There are only two terms in the expansion and they can be found by expressing sin^3 (x) as a combination of sin(x) and sin(3x) using
e 3 ix^ = (cos(x) + i sin(x))^3.
(c) Obtain Ψ(x, t) and find 〈x〉 as a function of time.
∞ for x = 0 0 for 0 < x ≤ a V 0 for x ≥ a
is ψ(x) =
{ A sin(kx) for 0 < x ≤ a Ce−κx^ for x ≥ a with
k =
√ 2 mE ¯h^2
κ =
√ 2 m(V 0 − E) ¯h^2
(a) Apply the boundary conditions at x = a and obtain the transcendental equation which determines the bound state energies E. (b) If (^) √ 2 mV 0 a^2 ¯h^2
= 3π ,
determine the allowed bound state energies. Express your answers in the form of a numerical factor multiplying the dimensional factor (¯h^2 / 2 ma^2 ). (Note: The FindRoot[ ] command in Mathematica is one way to locate solutions to the transcen- dental equation.)
An =
√ 2 a
√ κna 1 + κna
normalize the wave function for the lowest energy state in the previous problem. (b) What is the probability that a measurement of the position of a particle in the ground state will give a result ≥ a?