Problem Set 4 - Quantum Physics I | PHY 471, Assignments of Quantum Physics

Material Type: Assignment; Class: Quantum Physics I; Subject: Physics; University: Michigan State University; Term: Fall 2006;

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Physics 471 Problem Set 4 Fall 2006
16. A particle of mass min an infinite potential well of width ahas the initial wave function
Ψ(x, 0) = Asin3(πx/a).
(a) Normalize Ψ(x, 0).
(b) Express Ψ(x, 0) in terms of the energy eigenstates
ψn(x) = s2
asin(nπx/a), n = 1,2,3,··· ,
as
Ψ(x, 0) = X
n
Cnψn(x).
Hint: There are only two terms in the expansion and they can be found by expressing
sin3(x) as a combination of sin(x) and sin(3x) using
e3ix = (cos(x) + isin(x))3.
(c) Obtain Ψ(x, t) and find hxias a function of time.
17. The wave function for a particle of mass mmoving in the potential
V=
for x= 0
0 for 0 < x a
V0for xa
is
ψ(x) = (Asin(kx) for 0 < x a
Ceκx for xa
with
k=s2mE
¯h2κ=s2m(V0E)
¯h2.
(a) Apply the boundary conditions at x=aand obtain the transcendental equation
which determines the bound state energies E.
(b) If
s2mV0a2
¯h2= 3π ,
determine the allowed bound state energies. Express your answers in the form of a
numerical factor multiplying the dimensional factor h2/2ma2). (Note: The
FindRoot[ ] command in Mathematica is one way to locate solutions to the transcen-
dental equation.)
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Physics 471 Problem Set 4 Fall 2006

  1. A particle of mass m in an infinite potential well of width a has the initial wave function

Ψ(x, 0) = A sin^3 (πx/a).

(a) Normalize Ψ(x, 0). (b) Express Ψ(x, 0) in terms of the energy eigenstates

ψn(x) =

√ 2 a

sin(nπx/a) , n = 1, 2 , 3 , · · · ,

as Ψ(x, 0) =

∑ n

Cnψn(x).

Hint: There are only two terms in the expansion and they can be found by expressing sin^3 (x) as a combination of sin(x) and sin(3x) using

e 3 ix^ = (cos(x) + i sin(x))^3.

(c) Obtain Ψ(x, t) and find 〈x〉 as a function of time.

  1. The wave function for a particle of mass m moving in the potential

V =

  

∞ for x = 0 0 for 0 < x ≤ a V 0 for x ≥ a

is ψ(x) =

{ A sin(kx) for 0 < x ≤ a Ce−κx^ for x ≥ a with

k =

√ 2 mE ¯h^2

κ =

√ 2 m(V 0 − E) ¯h^2

(a) Apply the boundary conditions at x = a and obtain the transcendental equation which determines the bound state energies E. (b) If (^) √ 2 mV 0 a^2 ¯h^2

= 3π ,

determine the allowed bound state energies. Express your answers in the form of a numerical factor multiplying the dimensional factor (¯h^2 / 2 ma^2 ). (Note: The FindRoot[ ] command in Mathematica is one way to locate solutions to the transcen- dental equation.)

  1. (a) Given that the normalization factor for the wave function corresponding to the nth energy En in the previous problem is

An =

√ 2 a

√ κna 1 + κna

normalize the wave function for the lowest energy state in the previous problem. (b) What is the probability that a measurement of the position of a particle in the ground state will give a result ≥ a?