Pseudo Order reaction, Lecture notes of Chemistry

Pseudo Order reaction,order reaction

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2025/2026

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Pseudo โ€“ Order Reactions
A reaction in which one of the reactants is present in a large excess shows an order different from the
actual order. The experimental order which is not the actual one is referred to as the pseudo order.
Let us consider a reaction
A + B โŽฏโŽฏโ†’ products
in which the reactant B is present in a large excess. Since it is an elementary reaction, its rate law can be
written as,
rate = k [A] [B]
As B is present in large excess, its concentration remains practically constant in the course of reaction.
Thus the rate law can be written as,
rate = kโ€ฒ [A]
Where, the new rate constant kโ€ฒ = k [B].
Thus the actual order of the reaction is second-order but in practice it will be first-order.
Therefore, the reaction is said to have a pseudo-first order.
Examples of Pseudo-order Reactions: Hydrolysis of sucrose:
Sucrose upon hydrolysis in the presence of a dilute mineral acid gives glucose and fructose.
C12H22O11 + H2O โŽฏโŽฏโ†’ C6H12O6 + C6H12O6
Sucrose (excess) glucose fructose
If a large excess of water is present, [H2O] is practically constant and the rate law may be written
as Rate = k [C12H22O11] [H2O]
= kโ€™ [C12H22O11]
The reaction though of second-order is experimentally found to be first-order. Thus it is a pseudo
first-order reaction.
First Order Reactions (Integrated form of reaction rate for first order
reaction)
Let us consider a first order reaction A โŽฏโŽฏโ†’ products
Initial conc. a 0
Final conc. a โ€“ x x
Suppose that at the beginning of the reaction (t = 0), the concentration of A is a moles litreโ€“1. If
after time t, x moles of A have changed, the concentration of A is a โ€“ x.
We know that for a first order reaction, the rate of reaction, dx/dt, is directly proportional to the
concentration of the reactant.
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Pseudo โ€“ Order Reactions

A reaction in which one of the reactants is present in a large excess shows an order different from the

actual order. The experimental order which is not the actual one is referred to as the pseudo order.

Let us consider a reaction

A + B โŽฏโŽฏโ†’ products

in which the reactant B is present in a large excess. Since it is an elementary reaction, its rate law can be

written as,

rate = k [A] [B]

As B is present in large excess, its concentration remains practically constant in the course of reaction.

Thus the rate law can be written as,

rate = k โ€ฒ [A]

Where, the new rate constant k โ€ฒ = k [B].

Thus the actual order of the reaction is second-order but in practice it will be first-order.

Therefore, the reaction is said to have a pseudo-first order.

Examples of Pseudo-order Reactions: Hydrolysis of sucrose:

Sucrose upon hydrolysis in the presence of a dilute mineral acid gives glucose and fructose.

C

12

H

22

O

11

+ H

2

O โŽฏโŽฏโ†’ C

6

H

12

O

6

+ C

6

H

12

O

6

Sucrose (excess) glucose fructose

If a large excess of water is present, [H 2

O] is practically constant and the rate law may be written

as

Rate = k [C 12

H

22

O

11

] [H

2

O]

= k

โ€™

[C

12

H

22

O

11

]

The reaction though of second-order is experimentally found to be first-order. Thus it is a pseudo

first-order reaction.

First Order Reactions (Integrated form of reaction rate for first order

reaction)

Let us consider a first order reaction

A โŽฏโŽฏโ†’ products

Initial conc. a 0

Final conc. a โ€“ x x

Suppose that at the beginning of the reaction ( t = 0), the concentration of A is a moles litre

  • 1 . If

after time t , x moles of A have changed, the concentration of A is a โ€“ x.

We know that for a first order reaction, the rate of reaction, dx / dt , is directly proportional to the

concentration of the reactant.

Thus,

๐‘‘๐‘ฅ

(๐‘Žโˆ’๐‘ฅ)

Integration of the expression (1) gives

  • 1n ( a โ€“ x ) = kt + I ..................................(2)

Where I is the constant of integration.

The constant k may be evaluated by putting t = 0 and x = 0. Thus, I = โ€“ 1n a

Substituting for I in equation (2)

โˆ’ln

= ๐‘˜๐‘ก โˆ’ ln ๐‘Ž

ln

๐‘Ž

๐‘Žโˆ’๐‘ฅ

k =

1

๐‘ก

ln

๐‘Ž

๐‘Žโˆ’๐‘ฅ

Changing into common logarithms, k =

log

The value of k can be found by substituting the values of a and ( a โ€“ x ) determined experimentally

at time interval t during the course of the reaction.

A First Order Reaction Never Goes To Completion:

For a first order reaction,

[๐ด] = [๐ด]

๐‘œ

โˆ’๐‘˜๐‘ก

Where [A] o

is the concentration of reactants at t = 0, and [A] is the concentration of reactant at

timeโ€˜tโ€™

When the reaction reaches the completion, [A] is zero, putting [A] = 0 in the equation (1),

we get,

0 = [A]

o

โˆ’๐‘˜๐‘ก

Or ๐‘’

โˆ’๐‘˜๐‘ก

But ๐‘’

โˆ’๐‘˜๐‘ก

= 0 only when t = โˆž

This means a first order reaction takes infinite time to completion or never ends.

Initial Conc. a 0

Final Conc. a โ€“ x x

Let the initial concentration of A be a moles litre

  • 1

and after time t , x , moles have reacted. Therefore, the

concentration of A becomes ( a โ€“ x ). The rate law may be written as:

3

3

3

On integration, it gives

1

2 (๐‘Žโˆ’๐‘ฅ)

2

Where I is integration constant. I can be evaluated by putting x = 0 and t = 0. Thus,

1

2 ๐‘Ž

2

Substituting for I in equation (2)

2

2

2

2

1

๐‘ก

๐‘ฅ( 2 ๐‘Žโˆ’๐‘ฅ)

2 ๐‘Ž

2

.(๐‘Žโˆ’๐‘ฅ)

2

This is the integrated rate equation for a second order reaction.

Units Of Rate Constant

The units of rate constant for different orders of reactions are different.

Units of Zero order Rate constant

For a zero order reaction, the rate constant k is given by the expression,

๐‘œ

๐‘ฅ

๐‘ก

๐‘š๐‘œ๐‘™๐‘’/๐‘™๐‘–๐‘ก๐‘Ÿ๐‘’

๐‘ก๐‘–๐‘š๐‘’

Thus the units of k are mol L

  • 1

time

  • 1

Time may be given in seconds, minutes, days or years.

Units of First order Rate constant

The rate constant of a first order reaction is given by

  1. 03

๐‘ก

log

๐‘Ž

๐‘Žโˆ’๐‘ฅ

  1. 03

๐‘ก

log

[๐ด]

๐‘œ

[๐ด]

๐‘ก๐‘–๐‘š๐‘’ ร— ๐‘๐‘œ๐‘›๐‘๐‘’๐‘›๐‘ก๐‘Ÿ๐‘Ž๐‘ก๐‘–๐‘œ๐‘›

๐‘š๐‘œ๐‘™/๐ฟ

๐‘ก๐‘–๐‘š๐‘’ร—๐‘š๐‘œ๐‘™/๐ฟ

Thus the rate constant for the first order reaction is independent of the concentration. It has the unit

time

- 1

Units of Second order Rate constant

The rate constant for a second order reaction is expressed as

๐‘ก๐‘–๐‘š๐‘’ ร— ๐‘๐‘œ๐‘›๐‘๐‘’๐‘›๐‘ก๐‘Ÿ๐‘Ž๐‘ก๐‘–๐‘œ๐‘› ร— ๐‘๐‘œ๐‘›๐‘๐‘’๐‘›๐‘ก๐‘Ÿ๐‘Ž๐‘ก๐‘–๐‘œ๐‘›

๐‘ก๐‘–๐‘š๐‘’ ร— ๐‘š๐‘œ๐‘™/๐ฟ

Thus the units of k for a second order reactions are mol

- 1

L time

- 1

Units of Third order Rate constant

The rate constant for a third order reaction is

2

2

๐‘๐‘œ๐‘›๐‘๐‘’๐‘›๐‘ก๐‘Ÿ๐‘Ž๐‘ก๐‘–๐‘œ๐‘› ร— ๐‘๐‘œ๐‘›๐‘๐‘’๐‘›๐‘ก๐‘Ÿ๐‘Ž๐‘ก๐‘–๐‘œ๐‘›

๐‘ก๐‘–๐‘š๐‘’ ร— ๐‘๐‘œ๐‘›๐‘๐‘’๐‘›๐‘ก๐‘Ÿ๐‘Ž๐‘ก๐‘–๐‘œ๐‘›

2

ร— ๐‘๐‘œ๐‘›๐‘๐‘’๐‘›๐‘ก๐‘Ÿ๐‘Ž๐‘ก๐‘–๐‘œ๐‘›

2

๐‘ก๐‘–๐‘š๐‘’ ร— ๐‘๐‘œ๐‘›๐‘๐‘’๐‘›๐‘ก๐‘Ÿ๐‘Ž๐‘ก๐‘–๐‘œ๐‘›

2

๐‘ก๐‘–๐‘š๐‘’ ร— (

2

Thus the units of k for third order reaction are mol

- 2

L

2

time

- 1