Math 1030 Assignment 3: Unit Conversions and Potion Making, Assignments of Mathematics

The solutions to assignment 3 of math 1030. It includes calculations for converting units of length and volume, as well as a problem involving the creation of a potion with given quantities of solid ingredients and cooking time. The document also includes conversion factors for various units.

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Pre 2010

Uploaded on 08/31/2009

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Assignment 3
Math 1030
Due Friday, September 14th
Name: Solutions
1. Fundamental vs. Derived Units
For the units below make a list of the fundamental units and a list of
the derived units:
{speed, acceleration, energy, length, time, volume }
Solution
Fundamental Units
length
time
Derived Units
speed
acceleration
energy
volume
1
pf3
pf4
pf5

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Assignment 3

Math 1030

Due Friday, September 14th

Name: Solutions

  1. Fundamental vs. Derived Units

For the units below make a list of the fundamental units and a list of the derived units:

{ speed, acceleration, energy, length, time, volume }

Solution

Fundamental Units

length time

Derived Units speed acceleration energy volume

  1. Unit Conversions

Convert the following:

(a) 1 kilometer into inches.

Solution The appropriate conversion factor here is:

2.54 cm = 1 in.

Using this we can compute the solution:

1 km

( (^1000) m

1 km

) ( (^100) cm

1 m

) ( (^1) in

  1. 54 cm

) ≈ 39 , 370 in

(b) 10 gallons into liters.

Solution If we look up the conversion factor the appropriate one here is:

1 gallon = 3.785 liters

So, our calculation is:

10 gal

(

  1. 785 L 1 gal

) = 37. 85 L

(c) 65 miles per hour into meters per second.

Solution The appropriate conversion factor here is:

1.609 km = 1 mile

And so our calculation is: ( 65 miles hour

) ( 1 hour 60 min

) ( 1 min 60 sec

) (^

  1. 609 km 1 mile

) ( 1000 m 1 km

) ≈ 29. 05

m s

Amount of moondust required:

1 snarf ling

(

  1. 3 L snarf ling

) ( 1 snarblat

. 7 L

) ( 3 goldblats snarblat

) ( 17 g goldblat

)

= 167. 57 g of moondust.

Amount of time required to cook:

1 snarf ling

(

  1. 3 L snarf ling

) ( 1 snarblat

. 7 L

) ( 3 tocs snarblat

) ( 13 min tock

) ( 60 s min

)

≈ 7 , 688 seconds to cook.

  1. Compound Units Problem

An empty water tank is in the shape of a sphere with a radius of 24 meters. Water flows into the tank at a rate of 18 cubic yards per second. How many minutes will it take until the tank is full? 1 meter = 1.094 yards.

Solutions The total volume of the sphere is given by the formula for the volume of a sphere:

V =

πr^3 =

π(24m)^3 = 57, 905. 8 m^3.

Our rate is in terms of cubic yards, so we have to convert our volume to cubic yards:

57 , 905. 8 m^3

(

  1. 094 yards 1 m

) 3 = 75, 818. 3 yards^3

Now, to calculate the amount of time it requires, we just divide the total volume we need to fill by the rate:

t =

volume rate

75 , 818. 3 yards^3 18 yards^3 s

= 4, 212. 13 seconds ≈ 70 minutes.