Quantum Physics| High yield revision, Exams of Physics

Quantum Physics| High yield revision Quantum Physics| High yield revision

Typology: Exams

2025/2026

Available from 03/23/2026

christine-boyle
christine-boyle 🇺🇸

3.6

(7)

3.9K documents

1 / 9

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Quantum Physics| High yield revision
Blackbody Radiation - Answer-Radiation properties are
independent of the material. The maximum of the distribution
shifts to smaller wavelengths as the temperature is increased.
The total power radiated increases with the temperature. One of
the outstanding exceptions that classical physics could not
explain, dubbed the "ultraviolet catastrophe" by Paul Ehrenfest.
Blackbody - Answer-Has the ideal property that it absorbs all the
radiation falling on it and reflects none.
Discovery of the Electron - Answer-J.J. Thomson observed that
monoatomic gases could be ionized by x rays/cathode rays, thus
implying the atom itself must have charged constituents that can
be separated. These individual parts could be deflected by an
electric field as if they were negatively charged.
Crossed-Field Experiment - Answer-Performed by J.J. Thomson,
attempting to determine anything about electrons. He realized he
could determine their q/m ratio by finding their velocity through
derivations of the equations pictured and r=(mv)/(qB).
pf3
pf4
pf5
pf8
pf9

Partial preview of the text

Download Quantum Physics| High yield revision and more Exams Physics in PDF only on Docsity!

Quantum Physics| High yield revision

Blackbody Radiation - Answer-Radiation properties are independent of the material. The maximum of the distribution shifts to smaller wavelengths as the temperature is increased. The total power radiated increases with the temperature. One of the outstanding exceptions that classical physics could not explain, dubbed the "ultraviolet catastrophe" by Paul Ehrenfest. Blackbody - Answer-Has the ideal property that it absorbs all the radiation falling on it and reflects none. Discovery of the Electron - Answer-J.J. Thomson observed that monoatomic gases could be ionized by x rays/cathode rays, thus implying the atom itself must have charged constituents that can be separated. These individual parts could be deflected by an electric field as if they were negatively charged. Crossed-Field Experiment - Answer-Performed by J.J. Thomson, attempting to determine anything about electrons. He realized he could determine their q/m ratio by finding their velocity through derivations of the equations pictured and r=(mv)/(qB).

Millikan oil-drop experiment - Answer-Robert Milikan discovered the charge and subsequent mass of the electron by balancing charged, aerosolized drops of oil with an electric field, so that mg = qE of the drop. Thus, solving for q gave him the charge of the drop. It was noted that each drop was an integer multiple of a certain minimum charge value. Thomson's atomic model - Answer-Referred to as "plum-pudding model" or the "raisin-cake model" because of the resemblance. Thomson hypothesized the atom was a spherical cloud of positive charge with negative electrons embedded in them. Rutherford's atomic model - Answer-Known as the "nuclear model of the atom". Rutherford hypothesized that electrons orbit a small (massive compared to electron) nucleus. This came about through his observation that some alpha particles were reflected at large angles or backwards when going through thin metal foils, believing this to be caused by the alpha particle approaching close to the nucleus and being deflected the opposite way due to their like charges.

Methods of electron emission - Answer-Thermionic emission (application of heat allows electrons to gain enough energy to escape), Secondary emission (electron gains enough energy by transfer from a high-speed particle that strikes the material from outside), Field emission (a strong external electric field pulls the electron out of the material), Photoelectric effect (Incident light [Electromagnetic radiation] shining on the material transfers energy to the electrons,allowing them to escape). Photoelectrons - Answer-Ejected electrons (specifically caused by EM radiation?) Work function - Answer-It is the minimum binding energy of the electron to the material, or inversely, it is the minimum extra kinetic energy that allows electrons to escape the material. Represented by 𝜙. Energy quantum - Answer-E = hf Bremsstrahlung - Answer-The process by which photons are emitted by an electron slowing down. ("braking radiation")

p (momentum of a particle moving at light-speed) - Answer-E/c => hf/c => h/λ Compton effect - Answer-The process of elastic photon scattering from electrons Pair production - Answer-The creation of an elementary particle and its anti-particle. Often refers specifically to a photon creating an electron-positron pair near a nucleus but can more generally refer to any neutral boson creating a particle-antiparticle pair. Positronium - Answer-Atomlike configuration formed from positron-electron pair. They orbit around a common center for typically 10 E-11 s. Pair annihilation - Answer-The process of a particle and anti- particle colliding into each other to produce electromagnetic radiation. Bohr radius - Answer-0.53 E-10 m, orbit of the hydrogen atom, represented by na_0, where n is an integer called the principal quantum number.

Bohr's principle of complementarity - Answer-It is not possible to describe physical observables simultaneously in terms of both particles and waves. Uncertainty principle - Answer-Establishes limits on the simultaneous knowledge of the values of momentum and position. Wave function - Answer- Probability density - Answer-Represented by psi squared (or its conjugate), it is the probability of finding a particle in a given volume at a given instant in time. Normalization - Answer-Integration of the probability density from negative infinity to positive infinity. The Copenhagen interpretation - Answer-Interpretation of quantum results. Strongly supported by Max Born, Wolfgang Pauli, Bohr and Heisenberg. It promotes the collapse of the wave function upon measurement. It is generally based on the following: 1) The uncertainty principle, 2) The complementary

principle, and 3) The statistical interpretation of Born, based on probability determined by the wave function. Boundary conditions - Answer-An acceptable wave function must satisfy the Schrodinger equation and : 1) In order to avoid infinite probabilities, (PSI) must be finite everywhere, 2) In order to avoid multiple values of the probability, (PSI) bust be single values, 3) For finite potentials, (PSI) and (partial d(PSI)/dx) must be continuous, and 4) in order to normalize the wave functions, (PSI) must approach zero as x approaches + or - infinity. Schrodinger wave equation - Answer- Time-independent Schrodinger wave equation - Answer- Expectation value - Answer-The wave function is calculated to find the expected result of the average of many measurements of a given quantity. Denoted by Physical observable - Answer-Any measurable quantity for which we can calculate the expectation value.