Questions on Implicit Differentiation - Assignment 1 | MS 125, Assignments of Calculus

Material Type: Assignment; Professor: Kim; Class: Calculus I; Subject: Mathematics (MS); University: Jacksonville State University; Term: Unknown 1989;

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Pre 2010

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Worksheet ----MS125 Calculus I Dr. Y. Kim
3.8 Implicit Differentiation
What is an implicit function?
Function that can be written in the form )(xfy
=
is called an explicit function of x. However an
equation in x and y, such as 4
22
=+ yx , is said to give an implicit function of x. The graph of
4
22
=+ yx is the circle with the center )0,0( and the radius 2. Since there are x-values which
correspond to two y-values, y is not a function of x on the whole circle. But the equation represents
a curve which has a tangent line at each point. The slope of each tangent line can be found by
differentiating the equation with respect to x. This differentiation is called the implicit
differentiation
.
Tip:
Consider each y as a function of x.
Ex1) Compute the following
1.
[
]
3
4x
dx
d
2.
[
]
3
y
dx
d
3.
[ ]
yx
dx
d
32 +
4.
[
]
2
xy
dx
d
Ex2) Differentiate each implicit function (or Find
dx
dy
)
1. 13
2
=
xy
2. 4
22
=+
yx
3. 5
=
xy
4. 125
323
=++
yxyx
5. 0
252
=+
yxex y
6.
)cos(xyy
=
Ex3) Find the slope of the tangent line to the graph of the equation 4
22 =+ yx at the point
)3,1(
.
HOMEWORK
: 1~33 odd

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Worksheet ----MS125 Calculus I Dr. Y. Kim

3.8 Implicit Differentiation

What is an implicit function? Function that can be written in the form y = f ( x )is called an explicit function of x. However an equation in x and y , such as x^2 + y^2 = 4 , is said to give an implicit function of x. The graph of x^2 + y^2 = 4 is the circle with the center ( 0 , 0 )and the radius 2. Since there are x -values which correspond to two y -values, y is not a function of x on the whole circle. But the equation represents a curve which has a tangent line at each point. The slope of each tangent line can be found by differentiating the equation with respect to x. This differentiation is called the implicit differentiation.

Tip: Consider each y as a function of x.

Ex1) Compute the following

1. [ 4 x^3 ]

dx

d

2. [ y^3 ]

dx

d

3. [ x y ]

dx

d 2 + 3

4. [ xy 2 ]

dx

d

Ex2) Differentiate each implicit function (or Find dx

dy )

  1. y − 3 x^2 = 1
  2. x^2 + y^2 = 4
  3. xy = 5
  4. x^3 + 5 xy^2 + 2 y^3 = 1
  5. x^2 eyx^5 + y^2 = 0
  6. y =cos( xy )

Ex3) Find the slope of the tangent line to the graph of the equation x^2 + y^2 = 4 at the point ( 1 , 3 ).

HOMEWORK : 1~33 odd