Quiz 1 with Solutions - Principles of Chemistry II | CH 302, Quizzes of Chemistry

Material Type: Quiz; Professor: Laude; Class: PRINCIPLES OF CHEMISTRY II; Subject: Chemistry; University: University of Texas - Austin; Term: Spring 2014;

Typology: Quizzes

2013/2014

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Version 385 CH 302 Quiz 1 2014 laude (51790) 1
This print-out should have 10 questions.
Multiple-choice questions may continue on
the next column or page find all choices
before answering.
001 5.0 points
You’re running late for class (again) and still
need to eat lunch. You remember Dr. Laude
saying something about how adding salt to
water increases the boiling point, thus allow-
ing faster cooking. If you have 1 cup (8 fl. oz.
= 250 mL = 250 g) of H2O, how many grams
of CaCl2should you add in order to raise the
boiling point from 100C to 105C?
1. 60.2 g
2. 135.5 g
3. 90.3 g correct
4. 361.3 g
Explanation:
Tb=m·i·kb
5 = m·3·0.512
m= 3.255
mass =m·V·M W
mass = 3.155 ·0.25 ·110.98
mass = 90.3
Or, without a calculator...
mass 3.2·0.25 ·110
mass 88
Which only leaves one right answer.
002 5.0 points
Water from a local stream is added to one
side of the U-tube shown below. Pure water
is placed in the tube on the other side of the
semipermeable membrane. With the left side
open to barometric pressure of 1.0 atm and
1.15 atm applied to the right side, the two
liquids do not move.
1.00 atm
1.15 atm
BA
In which half of the U-tube is the pure water
located?
1. Acorrect
2. B
3. Not enough information is given.
Explanation:
003 5.0 points
Both ammonia and phosphine (PH3) are sol-
uble in water. Which is least soluble and
why?
1. ammonia; the NH bonds are so strong
that they cannot break to enable the ammonia
to hydrogen-bond with water.
2. phosphine; the PH bonds are so strong
that they cannot break to enable phosphine
to hydrogen-bond with water.
3. ammonia; it is too small to be hydrated
by water molecules.
4. phosphine; it does not form hydrogen
bonds with water molecules. correct
5. ammonia; it does not form hydrogen
bonds with water molecules.
Explanation:
PH3is least soluble because it cannot form
hydrogen bonds with water.
004 5.0 points
Estimate the enthalpy of vaporization of CCl4
given that at 25C and 58C its vapor pressure
is 107 and 405 torr, respectively. Assume that
pf3
pf4

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This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering.

001 5.0 points You’re running late for class (again) and still need to eat lunch. You remember Dr. Laude saying something about how adding salt to water increases the boiling point, thus allow- ing faster cooking. If you have 1 cup (8 fl. oz. = 250 mL = 250 g) of H 2 O, how many grams of CaCl 2 should you add in order to raise the boiling point from 100◦C to 105◦C?

  1. 60.2 g
  2. 135.5 g
  3. 90.3 g correct
  4. 361.3 g

Explanation: ∆Tb = m · i · kb

5 = m · 3 · 0. 512

m = 3. 255

mass = m · V · M W

mass = 3. 155 · 0. 25 · 110. 98

mass = 90. 3

Or, without a calculator...

mass ≈ 3. 2 · 0. 25 · 110

mass ≈ 88

Which only leaves one right answer.

002 5.0 points Water from a local stream is added to one side of the U-tube shown below. Pure water is placed in the tube on the other side of the semipermeable membrane. With the left side open to barometric pressure of 1.0 atm and 1.15 atm applied to the right side, the two liquids do not move.

1.00 atm

1.15 atm

A B

In which half of the U-tube is the pure water located?

  1. A correct
  2. B
  3. Not enough information is given. Explanation:

003 5.0 points Both ammonia and phosphine (PH 3 ) are sol- uble in water. Which is least soluble and why?

  1. ammonia; the N−H bonds are so strong that they cannot break to enable the ammonia to hydrogen-bond with water.
  2. phosphine; the P−H bonds are so strong that they cannot break to enable phosphine to hydrogen-bond with water.
  3. ammonia; it is too small to be hydrated by water molecules.
  4. phosphine; it does not form hydrogen bonds with water molecules. correct
  5. ammonia; it does not form hydrogen bonds with water molecules. Explanation: PH 3 is least soluble because it cannot form hydrogen bonds with water.

004 5.0 points Estimate the enthalpy of vaporization of CCl 4 given that at 25◦C and 58◦C its vapor pressure is 107 and 405 torr, respectively. Assume that

the enthalpy of vaporization is independent of the temperature.

  1. 3.98 kJ·mol−^1
  2. 48.6 kJ· mol−^1
  3. 33.1 kJ·mol−^1 correct
  4. 486 J·mol−^1
  5. 142 kJ·mol−^1

Explanation: T 1 = 25◦C + 273.15 = 298.15 K P 1 = 107 torr T 2 = 58◦C + 273.15 = 331.15 K P 2 = 405 torr Using the Clausius-Clapeyron equation,

ln

P 2

P 1

∆H vap◦ R

T 1

T 2

∆Hvap^0 =

R ln

P 2

P 1

T 1

T 2

8 .314 J · mol−^1 · K 1 298 .15 K

331 .15 K

×ln

405 torr 107 torr

= 33109.5 J · mol−^1

005 5.0 points Pure ethylene glycol has a vapor pressure of 28 torr and pure acetaldehyde has a vapor pressure of 756 torr. A mixture of 6 moles of ethylene glycol and 2 moles of acetaldehyde would have what total vapor pressure?

  1. 196 torr
  2. 189 torr
  3. 21 torr
  4. 210 torr correct
    1. 588 torr Explanation: Ptotal = χa · Pa + χb · Pb + ... Ptotal = 0. 75 · 28 torr + 0. 25 · 756 torr Ptotal = 210 torr

006 5.0 points Which of the following sets of values for ∆Hlattice, ∆Hhydration and ∆Hsolution, respec- tively, could describe a salt that dissolves en- dothermicly?

  1. −39, −76 and −39 kJ · mol−^1
  2. −39, 64 and −38 kJ · mol−^1
  3. 103, 90 and 29 kJ · mol−^1
  4. 103, −71 and 32 kJ · mol−^1 correct Explanation:

∆Hlattice + ∆Hhydration = ∆Hsolution

Keeping in mind that ∆Hlattice is always en- dothermic, ∆Hhydration is always exothermic, and ∆Hsolution is the sum of the two and for this problem must be endothermic, only the values 103, −71 and 32 kJ · mol−^1 satisfy these constraints.

007 5.0 points Consider the phase diagram for water.

400

100

50

1

pressure (atm)

temperature (K)

100 200 300 400 500

  1. O 2 dissolves in water exothermically, so decreasing the temperature increases its solu- bility in water. correct
  2. O 2 dissolves in water endothermically, so decreasing the temperature decreases its solubility in water.
  3. O 2 dissolves in water endothermically, so decreasing the temperature increases its solubility in water.
  4. O 2 dissolves in water exothermically, so decreasing the temperature decreases its sol- ubility in water.

Explanation: All gases dissolve exothermically as they leave the high velocity gas phase and enter the lower velocity aqueous phase, the corre- sponding kinetic energy is lost as heat.