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Microelectronic Circuits Quiz 10 for ECE 3040 - Solving Circuit Problems, Quizzes of Electrical and Electronics Engineering

Georgia Institute of Technology - Main CampusElectrical and Electronics Engineering

The tenth quiz for the microelectronic circuits course (ece 3040) focusing on solving problems related to potentiometer circuits, voltage gains, and currents. Students are required to find the values of resistors r1 and r2 to achieve a specific voltage gain, and then solve for i1, va, vb, and vo given certain voltages and resistances.

Typology: Quizzes

Pre 2010

Uploaded on 08/05/2009

koofers-user-ks3
koofers-user-ks3 🇺🇸

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ECE 3040 Microelectronic Circuits Quiz 10
July 21, 2004
Professor Leach Name
Instructions. Print your name in the space above. The quiz is closed-book and closed-notes. The quiz
consists of one problem. Honor Code Statement: I have neither given nor received help on this quiz.
Initials
1. The potentiometer has a resistance RP= 100 kΩ. The resistance from the potentiometer wiper to
ground is labeled xRp,where0≤x≤1. The voltage gain is a maximum when x=1. It is desired to
have vO/vI=30when x=1.WhenvO=10V, the current through R2is 1/3mA.
(a) Solve for R1and R2.
1+R2
R1
=30=⇒R1+R2=30R1
10 = 1
3(R1+R2)=1
3×30R1=⇒R1=1kΩ
R2=30R1−R1=29R1=29kΩ
(b) Plot the voltage gain vO/vIas a function of xfor 0≤x≤1.y=30x
vO
vI
=xRP
(1 −x)RP+xRP
×30 = 30x
0
5
10
15
20
25
30
0.2 0.4 0.6 0.8 1
x
1
pf2

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ECE 3040 Microelectronic Circuits Quiz 10 July 21, 2004

Professor Leach Name Instructions. Print your name in the space above. The quiz is closed-book and closed-notes. The quiz consists of one problem. Honor Code Statement: I have neither given nor received help on this quiz. Initials

  1. The potentiometer has a resistance RP = 100 kΩ. The resistance from the potentiometer wiper to ground is labeled xRp, where 0 ≤ x ≤ 1. The voltage gain is a maximum when x = 1. It is desired to have vO/vI = 30 when x = 1. When vO = 10 V, the current through R 2 is 1 /3 mA.

(a) Solve for R 1 and R 2.

R 2

R 1

= 30 =⇒ R 1 + R 2 = 30R 1

(R 1 + R 2 ) =

× 30 R 1 =⇒ R 1 = 1 kΩ R 2 = 30 R 1 − R 1 = 29R 1 = 29 kΩ

(b) Plot the voltage gain vO/vI as a function of x for 0 ≤ x ≤ 1. y = 30x

vO vI

xRP (1 − x) RP + xRP

× 30 = 30x

0

5

10

15

20

25

30

0.2 0.4 (^) x 0.6 0.8 1

  1. For vI = 8 V, R 1 = 1 kΩ, R 2 = 2 kΩ, R 3 = 3 kΩ, and R 4 = 4 kΩ, solve for i 1 , vA, vB , and vO.

i 1 = vI R 1 + R 3

= 2 mA vA = i 1 (R 1 + R 2 ) = 6 V

vB = vA − vI = −2 V vO = i 1 (R 2 + R 4 ) = 12 V