ECE 3050 Analog Electronics Quiz 2 - Solving for R4 and R3 in an Electronic Circuit - Prof, Quizzes of Electrical and Electronics Engineering

A quiz for the ece 3050 analog electronics course, focusing on solving for the values of resistors r4 and r3 in a given electronic circuit using given specifications and formulas. The quiz includes the circuit diagram, instructions, and spaces for students to fill in their answers.

Typology: Quizzes

Pre 2010

Uploaded on 08/05/2009

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ECE3050AnalogElectronicsQuiz2
May 23, 2008
Professor Leach Last Name: First Name:
Instructions. Print your name in the spaces above. Place a box around any answer. Honor Code Statement:
I have neither given nor received help on this quiz. Initials
1. For the circuit given, V+=15V,V=15 V,R1=30k,R2=10k,R5=9.2k,ID=1.5mA,and
IC=1.25 mA.FortheMOSFET,ID=10
3×(VGS 2)2.FortheBJT,VBE =0.65 V and β=49.
(a) Solve for R4for the specified ID.
VGG =V+R2+VR1
R1+R2
=7.5V RGG =R1kR2=7.5k
VGS =rID
K+VTO =3.225 V R4=VGG VVGS
ID
=2.84 k
(b) Solve for R3for the specified IC.
VBB =V+IDR3RBB =R3
VBB V=IC
βRBB +VBE +IC
αR5
=V+IDR3V=IC
βR3+VBE +IC
αR5
=R3=
V+VVBE IC
αR5
IC
β+ID
=11.55 k
1

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ECE 3050 Analog Electronics Quiz 2 May 23, 2008

Professor Leach Last Name: First Name: Instructions. Print your name in the spaces above. Place a box around any answer. Honor Code Statement: I have neither given nor received help on this quiz. Initials

  1. For the circuit given, V +^ = 15 V, V −^ = −15 V, R 1 = 30 kΩ, R 2 = 10 kΩ, R 5 = 9.2 kΩ, ID = 1.5 mA, and IC = 1.25 mA. For the MOSFET, ID = 10−^3 × (VGS − 2)^2. For the BJT, VBE = 0.65 V and β = 49. (a) Solve for R 4 for the specified ID.

VGG =

V +R 2 + V −R 1

R 1 + R 2

= 7.5 V RGG = R 1 kR 2 = 7.5 kΩ

VGS =

r ID K

+ VT O = 3.225 V R 4 =

VGG − V −^ − VGS

ID

= 2.84 kΩ

(b) Solve for R 3 for the specified IC.

VBB = V +^ − IDR 3 RBB = R 3

VBB − V −^ =

IC

β

RBB + VBE +

IC

α

R 5

=⇒ V +^ − IDR 3 − V −^ =

IC

β

R 3 + VBE +

IC

α

R 5

=⇒ R 3 =

V +^ − V −^ − VBE −

IC

α

R 5

IC

β

+ ID

= 11.55 kΩ