Physics 3A: Quiz 2a Solutions - Instantaneous and Average Velocities, Acceleration, Quizzes of Physics

The solutions to quiz #2a of physics 3a: basic physics i, covering topics such as instantaneous velocity, average velocity, and acceleration. Students are required to identify false statements, determine the part of motion with upward acceleration, and calculate the constant acceleration of a train based on given data.

Typology: Quizzes

Pre 2010

Uploaded on 09/17/2009

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Physics 3A: Basic Physics I
Quiz #2a: Solutions
Name:XXXXXXXXXXXXXXX_________
Student ID #:_________________________
Discussion Section:____________________
Date:10/12/04_________________________
Signature:____________________________
v
๎˜€
d
๎˜
t
๎˜‚
vx
๎˜ƒ
๎˜
x
๎˜
t
vx
๎˜ƒ
lim
๎˜„
t
๎˜…
0
๎˜
x
๎˜
t
๎˜€
dx
dt
xf
๎˜€
xi
๎˜†
vxt
๎˜‡
a
๎˜ƒ
๎˜๎˜‰๎˜ˆ
v
๎˜
t
ax
๎˜ƒ
lim
๎˜„
t
๎˜…
0
๎˜
vx
๎˜
t
๎˜€
d v x
d t
v
xf
๎˜Š
v
xi
๎˜‹
a
x
t
xf
๎˜€
xi
๎˜†
1
2
๎˜Œ
vxi
๎˜†
vxf
๎˜
t
vf
2
๎˜€
vi
2
๎˜†
2a
๎˜Œ
xf
๎˜Ž
xi
๎˜
g
๎˜
9.80 m
๎˜
s2
๎˜
32.0 ft
๎˜
s2
(circle the letter of your answer)
1. (2 pts) Which of the following statements is false?
a.) The instantaneous velocity can be โ€œalwaysโ€ equal to the average velocity
during a given time interval with a non-zero acceleration.
b.) The average velocity vector can be zero if the average speed is non-zero.
c.) The instantaneous velocity can be smaller than the average velocity.
d.) The instantaneous velocity can be larger than the average velocity.
2. (2 pts) You just graduated from UCI! You throw your cap straight up into the air. It
goes up, stops and then comes back down. During which part of the motion is the
acceleration vector of the cap upward, toward the sky?
a.) When you first let go of the cap and it starts upward.
b.) When the cap is at its highest point and its velocity is zero.
c.) When the cap is falling back down to the ground
d.) All of the above
e.) None of the above
3. (6 pts) Late as usual, Tony rushes down onto a subway platform to find his train
already departing. He stops and watches the cars go by. Each car is 10.5 m long. The
first moves past me, I mean him, in 1.25 s and the second in 1.00 s. What is the
constant acceleration of the train? (use back of sheet as well, circle your final
answer and show all work)
pf2

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Physics 3A: Basic Physics I Quiz #2a: Solutions

Name:XXXXXXXXXXXXXXX_________ Student ID #:_________________________ Discussion Section:____________________ Date:10/12/04_________________________ Signature:____________________________

v d

t

vx 

x

t

vx  lim

t  0

x

t

dx dt

xf xi  vx t a 

v

t

ax  lim

t  0

vx

t

d v (^) x d t

vxf vxi ax t xf xi ^1

v xi  vxf t

xf xi  vx t 

ax t^2 vf^2 vi^2  2 a xf  xi g  9.80 m s^2  32.0 ft s^2

(circle the letter of your answer)

  1. (2 pts) Which of the following statements is false?

a.) The instantaneous velocity can be โ€œalwaysโ€ equal to the average velocity during a given time interval with a non-zero acceleration. b.) The average velocity vector can be zero if the average speed is non-zero. c.) The instantaneous velocity can be smaller than the average velocity. d.) The instantaneous velocity can be larger than the average velocity.

  1. (2 pts) You just graduated from UCI! You throw your cap straight up into the air. It goes up, stops and then comes back down. During which part of the motion is the acceleration vector of the cap upward, toward the sky?

a.) When you first let go of the cap and it starts upward. b.) When the cap is at its highest point and its velocity is zero. c.) When the cap is falling back down to the ground d.) All of the above e.) None of the above

  1. (6 pts) Late as usual, Tony rushes down onto a subway platform to find his train already departing. He stops and watches the cars go by. Each car is 10.5 m long. The first moves past me, I mean him, in 1.25 s and the second in 1.00 s. What is the constant acceleration of the train? (use back of sheet as well, circle your final answer and show all work)

draw picture:

Concept: constant acceleration, 1-D motion.

Want average acceleration given by: a

v

t

v 2  v 1

t 2  t 1

, need v2 & v1 (of each car):

v 1

x

t

10.5 m 1.25 s

8.40 m

s v 2

x

t

10.5 m 1.00 s

10.5 m

s

these average velocities occur at middle of each car, so โˆ†t = 0.625 + 0.500 = 1.13 s and so a is given by:

a 

v

t

1.86 m

s^2