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An introduction to reaction stoichiometry, focusing on mole-to-mole and mass-to-mass calculations. It covers stoichiometric relations in chemical equations, conversion methods using mole ratios, and mass calculations using balanced equations and gravimetric analysis. Examples are included to illustrate the concepts.
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water produced from 3.4 mol O 2.
2
2
to produce 3.5 mol H 2 O by combustion of methane ( CH 4 ). ⇒ balanced equation: CH 4 + 2O 2 →→ CO 2 + 2H 2 O ⇒ mole ratio (conversion factor): 2 mol O 2 ⇔⇔ 2 mol H 2 O [2 mol O 2 /2 mol H 2 O]
2 2
2
Fig. 4.
2
2
4 2
2 4 10
2
4 10
4 10 4 10
4 10
3 4 10
19 kg O
9 10 gO 1 molO
0 gO 2 molCH
13 molO
1 molCH 1 kgCH
10 gCH
⇒ mole ratio: [1 mol Ba2+/1 mol BaSO 4 ] ⇒ molar masses: BaSO 4 →→ 233.40 g/mol Ba →→ 137.34 g/mol
2 4
2
4
4 4
⇒ mass %:
Fig. 4.