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Recursion Relations, Lecture Slide - Biology, Computational Biology, Medicine and Pharmacy, Robert F. Murphy, Recursion Relations, Parameter line, Finding steady states, Steady-state solutions
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Robert F. Murphy
Consider a species of insect that hatches in the spring, lays eggs in the fall and dies in the winter.
Let Ni be the number of insects in year i.
It is safe to say that the number of insects in a generation will be a function of the number in the previous generation, that is, Ni+1 = f (Ni).
Then f (Ni) = RNi.
Quite naturally, the behavior of Ni depends on R. R<1 Ni ?
Then f (Ni) = RNi.
Quite naturally, the behavior of Ni depends on R. R<1 Ni 0 R=1 Ni ?
Then f (Ni) = RNi.
Quite naturally, the behavior of Ni depends on R. R<1 Ni 0 R=1 Ni N 0 R>1 Ni
Unlimited growth is unrealistic; eventually something (e.g., food supply) will limit growth.
Assume R changes with Ni. Assume it decreases linearly as Ni increases R ( Ni ) = r [1- Ni / K ] with r,K > 0
Then
Ni+1 = rNi [1- Ni / K ]
(Demonstration D6)
From our modeling, we conclude that the system shows qualitatively different behavior for different parameter (r) values.
We can construct a parameter line to illustrate this.
0 1 2 3 r
monotonic monotonic oscillatory
unstable oscillatory
Calculate the difference to see if “final” value is stable and show qualitative conclusion for each value of r
We conclude for certain values of r that the final value of xi seems to vary with r. What determines the final value?
We can solve the recursion relation for a steady-state value. To do so, we look for values of xi for which xi+1 is the same, i.e., xi = xi+1 = xi r (1- xi )