Relativity III - Lecture Notes - Modern Physics | PHY 3101, Study notes of Physics

Material Type: Notes; Class: INTRO MODERN PHYSICS; Subject: PHYSICS; University: University of Florida; Term: Fall 2000;

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PHY3101 Modern Physics Lecture Notes Relativity 3
D. Acosta Page 1 8/25/00
Relativity 3
Disclaimer: These lecture notes are not meant to replace the course textbook. The
content may be incomplete. Some topics may be unclear. These notes are only meant to
be a study aid and a supplement to your own notes. Please report any inaccuracies to the
professor.
Addition of Velocities
Now that we know that the Galilean transformation must be modified, it’s time to revisit
the topic of adding velocities. Consider two inertial frames S and S’ with a relative
velocity v.
u
d
x
dt
u u v
ucuc
x
x x
x x
=
=+
>=
in frame S'
in a Galilean transformation, which would imply
if
Consider the inverse Lorentz Transformation:
x x vty y z z
t t vx c
dx dxvdt
dt dtv c dx
=
+
=
=
=+
=+
=+
γ
γ
γ
γ
a
f
ch
af
c h
and
Take differentials:
,
/
/
2
2
x
y
z
S
x'
y'
z'
S'
v
ux
pf3
pf4
pf5

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Relativity 3

Disclaimer: These lecture notes are not meant to replace the course textbook. The content may be incomplete. Some topics may be unclear. These notes are only meant to be a study aid and a supplement to your own notes. Please report any inaccuracies to the professor.

Addition of Velocities

Now that we know that the Galilean transformation must be modified, it’s time to revisit the topic of adding velocities. Consider two inertial frames S and S’ with a relative velocity v.

u dx dt

u u v

u c u c

x

x x x x

in frame S'

in a Galilean transformation, which would imply if

Consider the inverse Lorentz Transformation:

x x vt y y z z

t t vx c

dx dx vdt dt dt v c dx

γ γ

γ γ

a f

c h

a f

c h

and

Take differentials:

2

2

x

y

z

S

x'

y'

z'

S'

v ux

Divide one by the other:

where we have divided by

Note that

u dx dt

dx vdt dt v c dx

u

dx dt

v

v c dx dt

dt

dx dt

u

x

x

x

= = ′ +^ ′

2

The velocity addition formulae are:

Note that even though y = y ′ and z = z ′ , that u (^) yu (^) y ′^ and u (^) zuz

Example : Consider a spacecraft that travels at 0.8 c from Earth and that launches a projectile with a relative velocity of 0.8 c. What is the velocity of the projectile from Earth? Galilean:!

Lorentz:

u c c c c

u c^ c c

x

x

If instead of a projectile we turned on a light beam, both observers on the spacecraft and on Earth would agree that the velocity of the light beam is c , as required by Einstein’s 2nd postulate.

The addition of velocity formulae tell us that nothing can exceed the speed of light.

u u^ v vu c

u

u vu c

u u vu c

x x x

y

y x

z z x

2

2

2

γ

γ

e j

e j

Now we substitute in for γ:

f v^ c v c

f

v c v c v c

= − f

2 2 0 0

a fa f

So the Doppler shift equations are:

Thus, when source and receiver approach each other, the frequency is shifted higher. We say that the light is blue-shifted.

When source and receiver recede from each other, the frequency is shifted lower. We say that the light is red-shifted. Red light has a lower frequency than blue light.

Modern electronics allow us to determine frequencies very accurately, so we can measure relative velocities accurately as well using this effect. Examples include Doppler weather radar, police radar, and even the expansion of the universe!

Lorentz Invariance

We have seen that some quantities change from one inertial frame to another (length, time, velocity, frequency). A quantity which does not change after a Lorentz

transformation is said to be Lorentz Invariant. One special invariant is the

Space-time Interval:

s c t x y z t t t x x x

a f 2 a f 2 a f 2 a f 2 a f^2

2 1 2 1

= − etc.

This is the generalization of Cartesian distance for 4-dimensional space-time. The same value for ∆ s is obtained for any inertial frame. So although length and time separately are not invariant from one frame to another, this particular combination is.

We can prove that this is true by applying the Lorentz transformation. For example, consider a subatomic particle which decays in a time τ in its rest frame.

f f v^ c v c

f f v^ c v c

0

0

Source and receiver approaching

Source and receiver receding

In the rest frame S’: t t x x y s c

1 ′ =^0 2 ′ =^1 ′ =^2 ′ =^1 ′ =^ =^0

, τ , τ

L

Now make a Lorentz transformation to another frame S moving at velocity v :

x x vt y y z z t t vx c x v x x v t t t s c v c v c c v c

v c s c

γ γ γ τ γ τ γτ γτ γ τ γ τ γ τ τ

τ

a f

c h

a f c h

c h

as in the rest frame

2

2 1 2 1 (^2 2 2 2 2 2 2 2 2 2 2 ) 2 2 2 2

2 2

Some terminology:

s

s

s

2

2

2

time - like

light - like

space - like

A frame exists where 2 events occur in one place, separated by time.

2 events are separated by the speed of light.

No light signal can connect the 2 events.