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Resistances-Electro Mechanical Systems-Quiz Solution, Exercises of Electromechanical Systems and Devices

Cochin University of Science and TechnologyElectromechanical Systems and Devices

The course gives an introduction to various principles and applications pertaining to electrical machines. The course covers magnetic circuits, single phase transformer and equivalent circuit, auto transformer, basic concepts of electromechanical energyc onversion, DC and AC machines modeling and, steady state analysis.It includes: Resistors, Synthesize, Terminals, Ohm-Meter, Configuration, Phase, Angle, Capacitor, Inductor, Potential, Difference

Typology: Exercises

2011/2012

Uploaded on 07/31/2012

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QUIZ ZERO SOLUTION
NOTE: This quiz will NOT be graded. You are requested to NOT write your name on it.
1. Using only 1k ohm resistors, synthesize a resistor of 3/5k ohm and a resistor of 5/3k ohm. Use no
more than four 1k ohm resistor in each case. [1]
Solution part a
Solution part b
2. You are given a black box with three terminals. The box is known to contain five 1 ohm resistors.
Using an ohm-meter, it is known that the resistance between the terminals is as following:
A-B: 1.5 ohms
B-C: 3.0 ohms
A-C: 2.5 ohms
Determine the configuration of the five resistors inside the box. [1]
1
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QUIZ ZERO SOLUTION

NOTE: This quiz will NOT be graded. You are requested to NOT write your name on it.

1.more than four 1k ohm resistor in each case. [1] Using only 1k ohm resistors, synthesize a resistor of 3/5k ohm and a resistor of 5/3k ohm. Use no Solution part a

Solution part b

  1. You are given a black box with three terminals. The box is known to contain five 1 ohm resistors.

Using an ohm-meter, it is known that the resistance between the terminals is as following: A-B: 1.5 ohms B-C A-C: 3.0 ohms: 2.5 ohms Determine the configuration of the five resistors inside the box. [1]

1

2

Solution

  1. For the circuit diagram shown below, determine the source voltage V and phase angle.[2]

Solution Zc = (^) wC^1 = (^2) โˆ—piโˆ—(1โˆ— 1031 )โˆ—(10โˆ— 10 โˆ’ (^6) ) = 15. 9 ohm Ztotal = โˆš(10 โˆ— 103 )^2 + (15.9)^2 = 10kohm V = IZ = 0. 2 โˆ— 10 โˆ’^3 โˆ— 10 โˆ— 103 = 2V ฮธ = arctan( (^1015) โˆ— 10.^93 ) = 0. 091 deg