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ELPGE.GA7 resonance calculation x"+ 6x'+ 45X = 50 ws wot Find the amplitude Alo) of the sheady-state response furchon Xp (the park cular sala from the method of undelermined constants ) and find buth the pealg value Wp 70 for which Al(usp) =O as well as Alwp) and then conpare the ratio Alu} / Ato) with the qualrhy” factor Q= web, - Ax" ex Gugy = 50 suk bo= G~> tor Weo= VG, i= [4S = WE ¥ GTI a Qu tater + WE a 12 (slightly underdamped) Aside: The transient soluchan is the homepencs sdlq ef this DIE. only necessary to desenbe how the systems transrhons from the inthal one fo the sheady state: reror+4#Ss=0 4 C=-2BE6L 7 Y= BK Ce ces G4 sn OE) “this deays to less than (% of ts inbal ampl tude Wy Z£= a . 45 [Xp= Cz cos wh t Ce sin wt] 6 (xp!= Oo Cesnul +0 Cy ost J 1 D9" ure, eat —utcasinat] Xe GMe'+ AS % p= [4S Gr Gua cg Gost + [Gu cy F Cas-urjcy smut = TOasut er We = 50 . =O wo asus \{e |; (t\- lal: & \_ fas-w?-wo \fS0\ _ 50 toe Go 45-Wr E542)? + Bou? wo Hw ILO "OSM 600 Al) =IG+G@ = 50 [enn aut . 80 Gop t Bes? GS-2 4 ZOeyt O= A(d= 2 50 (as-ozery P= -L our zour) % 50. La (acura) +36@J) 2 4S- ee On For wes =O 7 ote ap tog Q21= BS Y SND compared to Woe Sax 6,71 SO. Ales) = - 50 fos SO = SO as Veszprsen TieiGiaes Trexom 21087 Bo7 ia? 139 A(o\= 22 10 zt A) JA) = 2B a = = = aio xt, N/A) = Boe 25 €9(@= 112) Las oe 2 , SUAS 36 4 Cslightly bigger) pt al goss thens gre at equililorum 1 x{o)=0= x! fe) x= =Kit¥p= © re wasthtcegin nee) + & ht + GHP = ge 3c twsltteasin cr) 4 OF *(- 6a, goserer 6p cos) t tagannt + VGas Gt YBa Atc =O 3 GUS Ce KMQ= ~3G 460, 4821 C405 C2= BO~HR7CE WE i CF -35/36, = 3a 7 Aw) See 0 AG Fears espn poh we ( . 8 = = [28738 ne ieereay off) ie fy) jase 3b 48G Bw BE ect wa smc 425 (sere s Gsm Frt] 
