Math 112: Derivatives Review for Exam I - Prof. Jennifer Taggart, Exams of Mathematics

A review for exam i of math 112, focusing on derivatives. It covers the concept of derivatives as the slope of the tangent line, the relationship between derivatives and velocity, and the methods for computing derivatives. The document also includes rules for exponents and instructions on how to determine the general shape of a function from its derivative.

Typology: Exams

Pre 2010

Uploaded on 03/11/2009

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Math 112
Review for Exam I
This test is all about derivatives!
f0(m) is the slope of the tangent line to f(x) at x=m
The derivative of distance is the instantaneous speed. That is, instantaneous speed is the
slope of a tangent line to the graph of distance.
The derivative of T R is MR. That is, you can think of MR as the slope of a tangent line
to the graph of T R.
The derivative of T C is M C.
We have two methods for computing derivatives. You must be able to do both!
the long way:
To compute f0(m), compute the slope of the secant line through f(x) at x=mand x=m+h.
slope of secant = f(m+h)f(m)
h.
Simplify this expression and let hgo to 0 to get the slope of the tangent line, f0(m).
using the derivative rules (This should be your default method do this unless you’re told
otherwise.)
Given the graph of f(x), you should be able to determine the general shape of f0(x):
If f(x) is increasing, then f0(x) is positive (the graph of f0(x) is above the x-axis).
If f(x) is decreasing, then f0(x) is negative (the graph of f0(x) is below the x-axis).
If f(x) has a horizontal tangent, then f0(x) = 0 (the graph of f0(x) is hitting the x-axis).
Given the graph of f0(x), you should be able to determine the general shape of f(x):
If f0(x) is positive, then f(x) is increasing.
If f0(x) is negative, then f(x) is decreasing.
If f0(x) = 0, then f(x) has a horizontal tangent line at x.
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Math 112 Review for Exam I This test is all about derivatives!

  • f ′(m) is the slope of the tangent line to f (x) at x = m
  • The derivative of distance is the instantaneous speed. That is, instantaneous speed is the slope of a tangent line to the graph of distance.
  • The derivative of T R is M R. That is, you can think of M R as the slope of a tangent line to the graph of T R.
  • The derivative of T C is M C.

We have two methods for computing derivatives. You must be able to do both!

  • the long way:

To compute f ′(m), compute the slope of the secant line through f (x) at x = m and x = m+h.

slope of secant =

f (m + h) − f (m) h

Simplify this expression and let h go to 0 to get the slope of the tangent line, f ′(m).

  • using the derivative rules (This should be your default method — do this unless you’re told otherwise.)

Given the graph of f (x), you should be able to determine the general shape of f ′(x):

  • If f (x) is increasing, then f ′(x) is positive (the graph of f ′(x) is above the x-axis).
  • If f (x) is decreasing, then f ′(x) is negative (the graph of f ′(x) is below the x-axis).
  • If f (x) has a horizontal tangent, then f ′(x) = 0 (the graph of f ′(x) is hitting the x-axis).

Given the graph of f ′(x), you should be able to determine the general shape of f (x):

  • If f ′(x) is positive, then f (x) is increasing.
  • If f ′(x) is negative, then f (x) is decreasing.
  • If f ′(x) = 0, then f (x) has a horizontal tangent line at x.

Rules for exponents:

  • xaxb^ = xa+b
  • x

a xb^ =^ x

a−b

  • x−a^ = (^) x^1 a ; (^) x−^1 a = xa
  • xa/b^ = b

xa

  • (xa)b^ = xab
  • x^0 = 1
  • x^1 = x