Linear Algebra: Determinants, Inverse Matrices, and Eigenvalues, Study notes of Mechanical Engineering

An in-depth review of linear algebra concepts, focusing on determinants, matrix inverses, and eigenvalues. Determinants are calculated using the formula given by equation (1) in the document, and properties such as multiplicative and interchange properties are discussed. The document also covers the concept of matrix inverses and their relationship to determinants. Lastly, eigenvalues and eigenvectors are introduced, and methods for finding them are provided.

Typology: Study notes

Pre 2010

Uploaded on 03/28/2010

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Linear Algebra - review problems
1 Determinants
Let Abe a n×nsquare matrix with coefficients aij (1 i, j n). The determinant of Ais computed
as follows:
|A|=
n
!
j=1
ajα(1)j+α|˜
Ajα|(1)
where αis a fixed integer between 1 and nand ˜
Ajαis the (n1) ×(n1) matrix obtained from Aby
removing the j-th row and the α-th column. ˜
Ajαhas coefficients:
˜
Ajα=
a11 . . . a1,(α1) a1,(α+1) . . . a1n
.
.
..
.
..
.
.
a(j1),1. . . a(j1),(α1) a(j1),(α+1) . . . a(j1),n
a(j+1),1. . . a(j+1),(α1) a(j+1),(α+1) . . . a(j+1),n
.
.
..
.
..
.
.
an1. . . an,(α1) an,(α+1) . . . an,n
Note that column αand row jare missing.
Some properties of the determinant:
1. |AB|=|A|·|B|,
2. if |A|$= 0, then Ais non singular and A1exists. Then |A1|=1/|A|.
3. if |A|$= 0, then the columns of Aare linearly independent. Defining the column vector akas the
k-th column of A that means that ak=
a1k
a2k
.
.
.
ank
:
A·x=
n
!
j=1
xjaj=0x=0.
If a linear combination of columns of Ais equal to zero, the coefficients (xi) of the combination are
all equal to zero.
4. Conversely, |A|$= 0 is equivalent to any of the three following statements:
1
pf3
pf4

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Linear Algebra - review problems

1 Determinants

Let A be a n × n square matrix with coefficients aij (1 ≤ i, j ≤ n). The determinant of A is computed

as follows:

|A| =

∑^ n

j=

ajα (−1)

j+α | A˜ (^) j α| (1)

where α is a fixed integer between 1 and n and A˜ (^) jα is the (n − 1) × (n − 1) matrix obtained from A by

removing the j-th row and the α-th column. A˜ (^) jα has coefficients:

jα =

a 11... a 1 ,(α−1) a 1 ,(α+1)... a 1 n

. . .

a(j−1), 1... a(j−1),(α−1) a(j−1),(α+1)... a(j−1),n

a(j+1), 1... a(j+1),(α−1) a(j+1),(α+1)... a(j+1),n

. . .

an 1... an,(α−1) an,(α+1)... an,n

Note that column α and row j are missing.

Some properties of the determinant:

1. |AB| = |A| · |B|,

  1. if |A| $= 0, then A is non singular and A

− 1 exists. Then |A

− 1 | = 1/|A|.

  1. if |A| $= 0, then the columns of A are linearly independent. Defining the column vector a (^) k as the

k-th column of A – that means that a (^) k =

a 1 k

a 2 k

. . .

ank

A · x =

∑^ n

j=

xj a (^) j = 0 ⇔ x = 0.

If a linear combination of columns of A is equal to zero, the coefficients (xi ) of the combination are

all equal to zero.

  1. Conversely, |A| $= 0 is equivalent to any of the three following statements:

− there exists a linear combination of columns of A equal to zero with coefficients that are not

all equal to zero:

∑n

j=

xj aj = 0 with at least one non zero xj.

− there exists x $= 0 such that A · x = 0,

− one of the column of A can be expressed as a linear combination of the others.

(Make sure that you understand why these three statements are equivalent).

  1. Exchanging two rows or columns of a matrix flips the sign of the determinant.
  2. Adding to one row the product of another row by a constant λ lives the determinant unchanged.

Example: ∣ ∣ ∣ ∣

a b

c d

a b

c + λa d + λb

In the same way, adding to a column of A the product of another column with a constant μ lives

the determinant unchanged. Example:

a b

c d

a b + μa

c d + μc

  1. The determinant of a diagonal matrix is equal to the product of the diagonal elements.
  2. The determinant of an upper or lower triangular matrix is equal to the product of its diagonal

elements.

  1. The determinant of a 2 × 2 matrix A is computed as follows:

|A| =

a b

c d

∣ =^ ad^ −^ bc.

Problems

Compute the determinant of the following matrices:

1. A =

2. B =

3. C =

with D =

λ (^1)

.. .

λ (^) n

 the diagonal matrix with diagonal coefficients equal to the eigenvalues of

A, and V a matrix whose columns are eigenvectors v (^) i associated with each of the different eigenvalues.

The first column of V is v 1 , an eigenvector associated with λ 1 , the second column is v 2 , an eigenvector

associated with λ 2 , etc....

Problems

Find the eigendecomposition of the following matrices:

1. A 1 =

2. A 2 =