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An introduction to the notation and prerequisites for isye 2028, a course on mathematical concepts. It covers summation and product notation, integration and differentiation, and the properties of exponential and logarithmic functions. Students are expected to be familiar with calculus and basic mathematical concepts. The document also includes suggested exercises to help reinforce the concepts.
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Just a brief review of some notation you should know and some short questions.
We often use roman letters {X, Y, x, y...} for things we hope to measure or model; greek letters {α, β, θ} for quantities we’ll infer from directly measured quantities.
We work with indexed vectors alot, like:
X = (X 1 , X 2 , ..., Xn)
or
x = (x 1 , x 2 , ..., xn)
or any
stuf f = (stuf f 1 , stuf f 2 , ..., stuf fn)
∑^ n
i=
stuf fi = stuf f 1 + stuf f 2 + · · · + stuf fn
is translated as: Start with stuf f 1 and add it to stuf f 2 and keep on adding until stuf fn. The stuf f to do (n times) can be as simple to do as taking a bunch of numbers {x 1 , x 2 , ...x 3 } and dividing it by the total number, i.e.
∑^ n
i=
xi n
n
∑^ n
i=
xi =
x 1 + x 2 + · · · + xn n
or something more complicated, like taking each of those numbers, subtracting some other number, squaring the result, and dividing that by n − 1
∑^ n
i=
(xi − μ)^2 n − 1
Just like summation, but the indexed items are separated by multiplication in place of addition
∏^ n
i=
xi = x 1 · x 2 · · · xn
3 Integration, differentiation, exp, log...
...of simple functions should all be familiar from calculus. Principally, remember that inte- gration and differentiation are linear operators meaning you can integrate and differentiate — usually – across sums.
You might have forgotten this important result about the derivative of the inverse of a function f , (f −^1 )′:
(f −^1 (x))′^ =
f ′(f −^1 )(x)
We will look at multiple integration some time in the future. Remember that you can usually switch the order of integration without too much trouble.
∫ (^) b
a
∫ (^) d
c
f (x)g(y)dydx = · · ·
∫ (^) b
a
(f (x)
∫ (^) d
c
g(y)dy)dx = · · · ∫ (^) d
c
g(y)dy
∫ (^) b
a
f (x)dx
You should also remember the very important substitution method for integration, with u = g(x).
∫ f (u)du =
f (u)
du dx
dx
And also integrate by parts
∫ (^) b
a
f g′^ = f g|ba −
∫ (^) b
a
f ′g
which might look more familiar to you if you let u = f and v = g.
4 Suggested Exercises
∑n i=1 c^ ·^ i^ =?, when^ c^ is a constant.
i=0 r i (^) =?, when |r| < 1.
∏n i=1 c^ ·^ e
xi (^) , when x = (x 1 , ..., xn) and c is a constant.
f (x) =
i=
f (i)(a) i!
(x − a)i
where f (i)^ indicates the ith derivative of f and i! = i · (i − 1) · (i − 2) · · · 1. Find the taylor series for f (x) = ex^ at a = 0.
0 e
−ttk− (^1) dt. (ii) Use substitution to evaluate
0 e
−ste−λtdt and express as a function of s, if λ is a constant.