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If your answer to a later part of a question is wrong because of a numerical slip-up in an earlier part, will you lose marks?
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๐๐๐๐๐๐๐๐ ๐๐๐๐๐๐๐๐๐๐๐๐ [units:^ ๐๐๐๐ ๐๐^
๐น๐น๐๐๐น๐น๐น๐น๐๐ ๐ด๐ด๐น๐น๐๐๐๐ [units:^ ๐๐ ๐๐^
โ2 (^) or ๐๐๐๐]
Buoyancy force = ๐๐๐๐๐๐๐๐๐๐๐๐ ๐๐ = ๐๐๐๐๐๐๐๐๐๐๐๐ ๐๐ ๐๐
Weight force = ๐๐๐๐๐๐๐๐๐๐๐น๐น๐๐ ๐๐ = ๐๐๐๐๐๐๐๐๐๐๐น๐น๐๐ ๐๐ ๐๐
Object has volume ๐๐
Buoyancy > Weight if ๐๐๐๐๐๐๐๐๐๐๐น๐น๐๐ < ๐๐๐๐๐๐๐๐๐๐๐๐
๐ฃ๐ฃ 1 ๐ฃ๐ฃ 2
Area ๐ด๐ด 1
Area ๐ด๐ด 2
๐ฃ๐ฃ 1 ๐ด๐ด 1 = ๐ฃ๐ฃ 2 ๐ด๐ด 2
Weight of fluid displaced = weight of boat Same weight is displaced before and after [A]
Continuity equation ๐ฃ๐ฃ ๐ด๐ด = ๐๐๐๐๐๐๐๐๐๐๐๐๐๐๐๐ : velocity increases / constant flow rate Bernoulliโs equation ๐๐ + 12 ๐๐๐ฃ๐ฃ^2 = ๐๐๐๐๐๐๐๐๐๐๐๐๐๐๐๐ : pressure decreases [D]
Hydrostatic equilibrium only depends on depth : A
Lake is in hydrostatic equilibrium : pressure increases with depth
Buoyancy force = weight of water displaced = constant : D
2 = 1.77 ร 10โ6^ ๐๐ 2
Gauge pressure is the additional pressure above the atmospheric pressure
Hydrostatic equilibrium: ๐๐ = ๐๐ 0 + ๐๐๐๐๐
Gauge pressure = ๐๐๐๐๐๐๐๐ ๐๐ ๐๐๐๐๐๐๐ + ๐๐๐ค๐ค๐๐๐๐๐๐๐น๐น ๐๐ ๐๐ค๐ค๐๐๐๐๐๐๐น๐น = 820 ร 9.8 ร 0.05 + 1000 ร 9.8 ร 0.05 = 890 ๐๐๐๐
Volume flow rate = ๐ฃ๐ฃ ๐ด๐ด = 5 ร 10โ3^ ๐๐ 3 ๐๐โ
Bernoulliโs equation : ๐๐ + 12 ๐๐๐ฃ๐ฃ 2 = ๐๐๐๐๐๐๐๐๐๐๐๐๐๐๐๐ ๐๐๐ด๐ด + 12 ๐๐๐ฃ๐ฃ๐ด๐ด^2 = ๐๐๐ต๐ต + 12 ๐๐๐ฃ๐ฃ๐ต๐ต^2 ๐๐๐ด๐ด = 1.6 ร 10^5 ๐๐๐๐, ๐๐๐ต๐ต = 1.2 ร 10^5 ๐๐๐๐, ๐ฃ๐ฃ๐ด๐ด = 2.5 ๐๐๐๐โ1, ๐๐ = 1000 ๐๐๐๐ ๐๐ โ
โ ๐ฃ๐ฃ๐ต๐ต = 9.3 ๐๐ ๐๐โ
Continuity equation : ๐ฃ๐ฃ ๐ด๐ด = ๐๐๐๐๐๐๐๐๐๐๐๐๐๐๐๐ ๐ฃ๐ฃ๐ด๐ด ๐ด๐ด๐ด๐ด = ๐ฃ๐ฃ๐ต๐ต ๐ด๐ด๐ต๐ต
๐ด๐ด๐ต๐ต =
๐ฃ๐ฃ๐ด๐ด ๐ด๐ด๐ด๐ด ๐ฃ๐ฃ๐ต๐ต^ =^
2.5 ร 2 ร 10โ
โ4 (^) ๐๐ 2