Revision : Fluid mechanics, Study notes of Fluid Mechanics

If your answer to a later part of a question is wrong because of a numerical slip-up in an earlier part, will you lose marks?

Typology: Study notes

2021/2022

Uploaded on 08/05/2022

jacqueline_nel
jacqueline_nel ๐Ÿ‡ง๐Ÿ‡ช

4.4

(242)

3.2K documents

1 / 23

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Revision :
Fluid mechanics
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe
pff
pf12
pf13
pf14
pf15
pf16
pf17

Partial preview of the text

Download Revision : Fluid mechanics and more Study notes Fluid Mechanics in PDF only on Docsity!

Revision :

Fluid mechanics

FAQ 1

  • Can we take other calculators into the exam?
  • No, sorry that you have to use the โ€œgreen oneโ€

(TI-30XB)

FAQ 3

  • Will you lose marks for not quoting correct

numbers of significant figures?

  • Only in extreme cases. If you quote something

similar to the data given in the question, you will

not lose marks.

Formula sheet

Formula sheet

Fluid Mechanics key facts (1/5)

  • Basic definitions:
  • Density ๐œŒ๐œŒ =

๐‘€๐‘€๐‘€๐‘€๐‘€๐‘€๐‘€๐‘€ ๐‘‰๐‘‰๐‘‰๐‘‰๐‘‰๐‘‰๐‘‰๐‘‰๐‘‰๐‘‰๐‘‰๐‘‰ [units:^ ๐‘˜๐‘˜๐‘˜๐‘˜ ๐‘š๐‘š^

โˆ’3]

  • Pressure ๐‘ƒ๐‘ƒ =

๐น๐น๐‘‰๐‘‰๐น๐น๐น๐น๐‘‰๐‘‰ ๐ด๐ด๐น๐น๐‘‰๐‘‰๐‘€๐‘€ [units:^ ๐‘๐‘ ๐‘š๐‘š^

โˆ’2 (^) or ๐‘ƒ๐‘ƒ๐‘ƒ๐‘ƒ]

  • Pressure can also be measured in atmospheres: 1 ๐‘ƒ๐‘ƒ๐‘Ž๐‘Ž๐‘š๐‘š = 1.013 ร— 10^5 ๐‘ƒ๐‘ƒ๐‘ƒ๐‘ƒ [on formula sheet]
  • Gauge pressure means the extra pressure above the atmospheric pressure

Fluid Mechanics key facts (3/5)

  • An object immersed in a fluid will feel a buoyancy

force equal to the weight of the fluid displaced

Buoyancy force = ๐‘š๐‘š๐‘“๐‘“๐‘‰๐‘‰๐‘‰๐‘‰๐‘“๐‘“๐‘“๐‘“ ๐‘˜๐‘˜ = ๐œŒ๐œŒ๐‘“๐‘“๐‘‰๐‘‰๐‘‰๐‘‰๐‘“๐‘“๐‘“๐‘“ ๐‘‰๐‘‰ ๐‘˜๐‘˜

Weight force = ๐‘š๐‘š๐‘‰๐‘‰๐‘œ๐‘œ๐‘œ๐‘œ๐‘‰๐‘‰๐น๐น๐‘œ๐‘œ ๐‘˜๐‘˜ = ๐œŒ๐œŒ๐‘‰๐‘‰๐‘œ๐‘œ๐‘œ๐‘œ๐‘‰๐‘‰๐น๐น๐‘œ๐‘œ ๐‘‰๐‘‰ ๐‘˜๐‘˜

Object has volume ๐‘‰๐‘‰

Buoyancy > Weight if ๐œŒ๐œŒ๐‘‰๐‘‰๐‘œ๐‘œ๐‘œ๐‘œ๐‘‰๐‘‰๐น๐น๐‘œ๐‘œ < ๐œŒ๐œŒ๐‘“๐‘“๐‘‰๐‘‰๐‘‰๐‘‰๐‘“๐‘“๐‘“๐‘“

Fluid Mechanics key facts (4/5)

  • Flow of an incompressible fluid obeys the

continuity equation : ๐‘ฃ๐‘ฃ ๐ด๐ด = ๐‘๐‘๐‘๐‘๐‘๐‘๐‘๐‘๐‘Ž๐‘Ž๐‘ƒ๐‘ƒ๐‘๐‘๐‘Ž๐‘Ž where

๐‘ฃ๐‘ฃ = fluid velocity and ๐ด๐ด = pipe area

  • This equation results from conservation of mass. Itโ€™s the same as saying ๐‘ฃ๐‘ฃ๐‘๐‘๐‘ฃ๐‘ฃ๐‘ฃ๐‘ฃ๐‘š๐‘š๐‘ฃ๐‘ฃ ๐‘“๐‘“๐‘ฃ๐‘ฃ๐‘๐‘๐‘“๐‘“ ๐‘Ÿ๐‘Ÿ๐‘ƒ๐‘ƒ๐‘Ž๐‘Ž๐‘ฃ๐‘ฃ = ๐‘๐‘๐‘๐‘๐‘๐‘๐‘๐‘๐‘Ž๐‘Ž๐‘ƒ๐‘ƒ๐‘๐‘๐‘Ž๐‘Ž

๐‘ฃ๐‘ฃ 1 ๐‘ฃ๐‘ฃ 2

Area ๐ด๐ด 1

Area ๐ด๐ด 2

๐‘ฃ๐‘ฃ 1 ๐ด๐ด 1 = ๐‘ฃ๐‘ฃ 2 ๐ด๐ด 2

Practice exam questions: Section A

Weight of fluid displaced = weight of boat Same weight is displaced before and after [A]

Continuity equation ๐‘ฃ๐‘ฃ ๐ด๐ด = ๐‘๐‘๐‘๐‘๐‘๐‘๐‘๐‘๐‘Ž๐‘Ž๐‘ƒ๐‘ƒ๐‘๐‘๐‘Ž๐‘Ž : velocity increases / constant flow rate Bernoulliโ€™s equation ๐‘ƒ๐‘ƒ + 12 ๐œŒ๐œŒ๐‘ฃ๐‘ฃ^2 = ๐‘๐‘๐‘๐‘๐‘๐‘๐‘๐‘๐‘Ž๐‘Ž๐‘ƒ๐‘ƒ๐‘๐‘๐‘Ž๐‘Ž : pressure decreases [D]

Practice exam questions: Section A

Hydrostatic equilibrium only depends on depth : A

Lake is in hydrostatic equilibrium : pressure increases with depth

Buoyancy force = weight of water displaced = constant : D

Practice exam questions: Section B

1.5 ร— 10โˆ’

2 = 1.77 ร— 10โˆ’6^ ๐‘š๐‘š 2

๐น๐น๐‘๐‘๐‘Ÿ๐‘Ÿ๐‘๐‘๐‘ฃ๐‘ฃ = ๐‘ƒ๐‘ƒ๐‘Ÿ๐‘Ÿ๐‘ฃ๐‘ฃ๐‘๐‘๐‘๐‘๐‘ฃ๐‘ฃ๐‘Ÿ๐‘Ÿ๐‘ฃ๐‘ฃ ร— ๐ด๐ด๐‘Ÿ๐‘Ÿ๐‘ฃ๐‘ฃ๐‘ƒ๐‘ƒ = 12 ร— 10^6 ร— 1.77 ร— 10โˆ’6^ = 21 ๐‘๐‘

Practice exam questions: Section B

Gauge pressure is the additional pressure above the atmospheric pressure

Hydrostatic equilibrium: ๐‘ƒ๐‘ƒ = ๐‘ƒ๐‘ƒ 0 + ๐œŒ๐œŒ๐‘˜๐‘˜๐œŒ

Gauge pressure = ๐œŒ๐œŒ๐‘‰๐‘‰๐‘“๐‘“๐‘‰๐‘‰ ๐‘˜๐‘˜ ๐œŒ๐‘‰๐‘‰๐‘“๐‘“๐‘‰๐‘‰ + ๐œŒ๐œŒ๐‘ค๐‘ค๐‘€๐‘€๐‘œ๐‘œ๐‘‰๐‘‰๐น๐น ๐‘˜๐‘˜ ๐œŒ๐‘ค๐‘ค๐‘€๐‘€๐‘œ๐‘œ๐‘‰๐‘‰๐น๐น = 820 ร— 9.8 ร— 0.05 + 1000 ร— 9.8 ร— 0.05 = 890 ๐‘ƒ๐‘ƒ๐‘ƒ๐‘ƒ

Practice exam questions: Section C

Volume flow rate = ๐‘ฃ๐‘ฃ ๐ด๐ด = 5 ร— 10โˆ’3^ ๐‘š๐‘š 3 ๐‘๐‘โˆ’

5 ร— 10โˆ’

2 ร— 10โˆ’^

Practice exam questions: Section C

Bernoulliโ€™s equation : ๐‘ƒ๐‘ƒ + 12 ๐œŒ๐œŒ๐‘ฃ๐‘ฃ 2 = ๐‘๐‘๐‘๐‘๐‘๐‘๐‘๐‘๐‘Ž๐‘Ž๐‘ƒ๐‘ƒ๐‘๐‘๐‘Ž๐‘Ž ๐‘ƒ๐‘ƒ๐ด๐ด + 12 ๐œŒ๐œŒ๐‘ฃ๐‘ฃ๐ด๐ด^2 = ๐‘ƒ๐‘ƒ๐ต๐ต + 12 ๐œŒ๐œŒ๐‘ฃ๐‘ฃ๐ต๐ต^2 ๐‘ƒ๐‘ƒ๐ด๐ด = 1.6 ร— 10^5 ๐‘ƒ๐‘ƒ๐‘ƒ๐‘ƒ, ๐‘ƒ๐‘ƒ๐ต๐ต = 1.2 ร— 10^5 ๐‘ƒ๐‘ƒ๐‘ƒ๐‘ƒ, ๐‘ฃ๐‘ฃ๐ด๐ด = 2.5 ๐‘š๐‘š๐‘๐‘โˆ’1, ๐œŒ๐œŒ = 1000 ๐‘˜๐‘˜๐‘˜๐‘˜ ๐‘š๐‘š โˆ’

โ†’ ๐‘ฃ๐‘ฃ๐ต๐ต = 9.3 ๐‘š๐‘š ๐‘๐‘โˆ’

Continuity equation : ๐‘ฃ๐‘ฃ ๐ด๐ด = ๐‘๐‘๐‘๐‘๐‘๐‘๐‘๐‘๐‘Ž๐‘Ž๐‘ƒ๐‘ƒ๐‘๐‘๐‘Ž๐‘Ž ๐‘ฃ๐‘ฃ๐ด๐ด ๐ด๐ด๐ด๐ด = ๐‘ฃ๐‘ฃ๐ต๐ต ๐ด๐ด๐ต๐ต

๐ด๐ด๐ต๐ต =

๐‘ฃ๐‘ฃ๐ด๐ด ๐ด๐ด๐ด๐ด ๐‘ฃ๐‘ฃ๐ต๐ต^ =^

2.5 ร— 2 ร— 10โˆ’

  1. 3 =^5.^4 ร—^10

โˆ’4 (^) ๐‘š๐‘š 2