Solution to Lemmon's Problem on Hallden-Incompleteness of RMLC, Summaries of Logic

A solution to a problem left open by lemmon regarding the hallden-completeness of the rmlc logical system. The author, dolph ulrich, proves that rmlc is hallden-incomplete by showing that it cannot prove certain formulas that are provable in both rm and lc, two related but distinct logical systems. The document also discusses the relationship between rmlc and other logical systems, such as dummett's lc and the intuitionistic sentential calculus, ic.

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187
Notre Dame Journal
of
Formal Logic
Volume
22,
Number
2,
April
1981
RMLC:
Solution
to a
Problem
Left Open
by
Lemmon
DOLPH ULRICH
A system
S is
Hallden-incomplete
if
and
only
if
there
are
wffs
A
and
B
with
no
variables
in
common such that
\^A v B
but
neither
\$A
nor
\^B,
and
strongly Hallden-incomplete
if, in
addition,
A
and
B
have
but
one
variable
apiece.* Evidently,
all
strongly Hallden-incomplete systems
are
Hallden-
incomplete; Lemmon
[5]
poses
the
converse
as an
open problem.
Consider
the
system RMLC, with detachment
and
adjunction
as
rules
and, using standard conventions concerning relative binding strengths
of
connectives
and
omission
of
parentheses,
the
following axiom schemes:
RO
A-+(A-+A)
Rl A^A
R2
(A
->
B) -* ((£ ->
C)
->
(A
~>
C))
R3 A-+((A->
B)-»
B)
R4
(A
-+(A-+B))-»
(A
-+B)
R5
A&B-+A
R6 A&B-+B
R7 (A-+B)&(A-+C)'+(A-+(B&
C))
R8
A
->
A v B
R9
B-^AMB
RIO
04
-> C) &
(5
-* C) ->
(U v B)
->
C)
DUMMETT
U
-*
5) v (5
->
A)
Rll
i&(5vC)->U&5)vC
R12
(A-»B)-*(B-+A) _
PRE TRANS
U
->
(5
-> ^1))
-> (A
- (I
->
5))
RMLC
W->>l)v (B^(C-+B)).
*The author wishes
to
thank
N.
D.
Belnap,
Jr.,
J.
M.
Dunn,
and the
anonymous referee
for
several suggestions
for
improving
the
presentation
of
this paper.
Received December 27, 1978; revised November
3, 1980
pf3

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Notre Dame Journal of Formal Logic Volume 22, Number 2, April 1981

RMLC: Solution to a Problem

Left Open by Lemmon

DOLPH ULRICH

A system S is Hallden-incomplete if and only if there are wffs A and B with no variables in common such that ^A v B but neither $A nor ^B, and strongly Hallden-incomplete if, in addition, A and B have but one variable apiece.* Evidently, all strongly Hallden-incomplete systems are Hallden- incomplete; Lemmon [5] poses the converse as an open problem. Consider the system RMLC, with detachment and adjunction as rules and, using standard conventions concerning relative binding strengths of connectives and omission of parentheses, the following axiom schemes: RO A-+(A-+A) Rl A^A R2 (A -> B) -* ((£ -> C) -> (A ~> C)) R3 A-+((A-> B)-» B) R4 (A -+(A-+B))-» (A -+B) R5 A&B-+A R6 A&B-+B R7 (A-+B)&(A-+C)'+(A-+(B& C)) R8 A -> A v B R9 B-^AMB RIO 04 -> C) & (5 -* C) -> ( U v B) -> C) DUMMETT U -* 5 ) v (5 -> A ) R l l i & ( 5 v C ) - > U & 5 ) v C R12 (A-»B)-*(B-+A) _ PRE TRANS U -> (5 -> ^1)) -> (A -• ( I -> 5)) RMLC W->>l)v (B^(C-+B)).

*The author wishes to thank N. D. Belnap, Jr., J. M. Dunn, and the anonymous referee for several suggestions for improving the presentation of this paper.

Received December 27, 1978; revised November 3, 1980

188 DOLPHULRICH

RMLC is clearly a subsystem of Dummett's LC [3], most of the above schemes being among those listed for ZC-duty in [6] (pp. 316-317) and the rest easily derived, e.g., PRE TRANS from the intuitionistiol -> (A -> B) by way of B -* (C->5), and RMLC from the latter by R9. RMLC is also contained in the system /tM(ingle) of [1], for R0-R12 are ^M-axioms (p. 341), DUMMETT is RM64 (p. 397), and PRE TRANS and RMLC are readily established. Indeed, RM and LC may be axiomatized by adding to RMLC (sche- matically) the left disjunct of RMLC for the former and the right for the latter: R0-R12 plus A -> A suffice for RM according to [1] (p. 341), while R2, R4-R10, DUMMETT, R12, PRE TRANS, and B -> (C-»fi) give a set equivalent, with minor adjustments, to one given in [6] (p. 317) for LC. A familiar, Hallden-style argument consequently completes a proof that the theorems of RMLC are precisely the wffs provable in both RM and LC. For assume ^fiC and \jx;C. Then there must be substitution i n s t a n c e s ^ ,.. .,Am ofA-*A and 2?!,.. .,Bn of B -+ (C~+B) such that Ax &... &Am fejxcC and Bt &... & Bn \RMLC C. It follows, by a proof similar to one in [1] (p. 302), that 04! &... & Am) v {Bx &... & Bn) ^MLCC^ whence eventually, after repeated distribution moves licensed by R5-R11 (and the transitivity of \RMLC)> (Ax v Bx) & 04! v B 2 ) &... & {Am v Bn) ^MICC- B^ Y RMLC, however, each A{ v Bj is available in RMLC, so that \RMLCC a s we^» finishing the argument.^1 For a solution to Lemmon's problem, now, let A and B have no variables in common, and just one each, and assume \RMLC^ V^ &- Then \j^A v B also. It is shown in [4] that the extensions (closed under substitution) of LC are linearly ordered, so it follows from Theorem 1 of [5] that LC is Hallden- complete. Thus, \j^A or \j^B. Arbitrarily, say \j^A. Then^l is a tautology of the classical, two-valued truth tables and, since these characterize the one- variable fragment of RM ([ 1 ], p. 413, Corollary 3.1), ^jA as well, whereupon \RMLCA anc* the latter system is thus not strongly Hallden-incomplete. Because A -> A is scarcely in LC, however, and B -> (C -> B) notoriously not in RM, neither disjunct of RMLC can be obtained in RMLC, so that RMLC is Hallden-incomplete..

NOTE

  1. The problem ([1], p. 99) of axiomatizing a "constructive mingle" whose implicational fragment will be given by the implicational axiom schemes R0-R4 remains open; for BULL {{A -*5) -> C) -»(((5 -»A) -> C) -> C) is known from [2] to hold in LC, and a quick check of Parks's matrix in [1] (p. 148) shows it in RM as well. So BULL is provable in RMLC. But R0-R4 are intuitionistically acceptable, as BULL is not. The author suggests looking, instead, at the system RMIC which results when DUMMETT is deleted from RMLC's axiom set and whose theorems are easily shown to be precisely those wffs provable in both RM and the intuitionistic sentential calculus, IC.

REFERENCES

[1] Anderson, A. R. and N. D. Belnap, Jr., Entailment, Princeton University Press, Prince- ton, New Jersey, 1975.