Sample Final Exam Solution - Computer Components and Operations | ECSE 2610, Exams of Electrical and Electronics Engineering

Material Type: Exam; Class: CPTR COMPONENTS & OPER; Subject: Electrical & Comp. Sys. Engr.; University: Rensselaer Polytechnic Institute; Term: Fall 2008;

Typology: Exams

2011/2012

Uploaded on 02/17/2012

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_______________________ _____________________ ______________
name RIN# section #
COCO Final Exam Fall 2008 Solution 1 / 10
SOLUTION
Computer Components and Operations (COCO)
ECSE-2610
SAMPLE Final
Please show your work.
Question
# Possible
Points Actual
Points Grader
1 10
2 10
3 10
4 20
5 10
6 20
7 10
8 10
Total 100
pf3
pf4
pf5
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Download Sample Final Exam Solution - Computer Components and Operations | ECSE 2610 and more Exams Electrical and Electronics Engineering in PDF only on Docsity!

name RIN# section #

SOLUTION

Computer Components and Operations (COCO)

ECSE-

SAMPLE Final

Please show your work.

Question

Possible

Points

Actual

Points

Grader

Total 100

name RIN# section #

  1. (10 points) Analyze the circuit below. Do NOT simplify. Just write out step by step the output of each gate and the final function output without simplifying.

F = ((W' + X) ⋅ Y) ⋅ (W' + X + Y') ⋅ (W + Z)

name RIN# section #

  1. (10 points) The 74x139 is a 3x8 decoder. The input signals to the circuit below are: EN1 = HIGH, EN2_L = LOW, EN3_L is LOW, EN4 = HIGH; N0 = LOW, N1 = LOW, N2 =HIGH, N3 = HIGH, N4 = LOW. = 01100 = 12dec

What are

DEC0_L DEC1_L DEC2_L DEC3_L DEC4_L DEC5_L DEC6_L DEC7_L EN8X15_L

_____ _____ _____ _____ _____ _____ _____ _____ _____

DEC8_L DEC9_L DEC10_L DEC11_L DEC12_L DEC13_L DEC14_L DEC15_L?

_____ _____ _____ _____ _____ _____ _____ _____

The two high order input bits (01) select, through the left hand decoder, the second right hand decoder from the top using its Enable input. The three low order inputs (100) select the fifth output of all the right-hand decoders.

name RIN# section #

  1. (20 points) Moore sequential machine. Design a sequential machine that gives a “1” output when the total number of 0s received is ODD and the total number of 1s received is an EVEN number greater than 0.

4.a. (5) Circle the inputs that should reach state S5, the “success state”

0 0 0 1 1 0 0 0 1 1 0 1 0

4.b (10) Such a machine can be implemented with six states. Complete the state diagram below. Be sure to include the outputs in each state.

S

[0]

S1 S

[0] [0]

S3 S

[0] [0]

S

[1]

4.c (5) Describe briefly in words the strings that reach each state:

SO: Start (and even number of zeros with no 1’s)

S1: Odd number of 0s, no 1’s

S2: Even number of 0s (or none), odd number of 1s

S3: Odd number of 0s, odd number of 1s

S4: Even number of 0s, even number of 1s

S5: Odd number of 0s, and an even number, greater than zero, of 1s

name RIN# section #

  1. (20 points) A 2-bit Gray code goes 00 → 01 → 11 → 10 → 00 → ... Build a simple counter circuit using D flip-flops (in four parts below) that continuously cycles through this code.

6.a. Sketch the state diagram for this counter.

6.b. Denote the bit on the left as B, and the bit on the right as A. Using this notation, construct the next-state and excitation tables for this counter using the template below.

Current State Next State Flip-Flop Inputs

B A B* A* D^ B DA

6.c. From your table, write down simple formulas for D (^) A and DB.

DB = A DA = B'

6.d. Sketch and label the circuit diagram for the 2-bit Gray code counter using the D flip-flop template below.

D (^) A CLK

\Reset

Q Q

S

R

QA D (^) B CLK

Q Q

S

R

QB

+5V

D (^) A CLK

\Reset

Q Q

S

R

QA D (^) B CLK

Q Q

S

R

QB

+5V

B' A

name RIN# section #

  1. (10 points) Minimization with don’t cares.

F= ∑ (^) w,x,y,z (0, 2, 13, 15) + d(5, 7, 8, 10)

Find the minimal SOP and POS expressions for F using the K-maps below.

FSOP = _________ xz + x'z' _____________

FPOS = _______ ( x +z') ⋅ (x '+z) _____________

name RIN# section #