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The solutions to exam 3 for math 361, section d13 and d14, held on november 12, 2007. The exam covers topics such as continuous uniform distributions, normal distributions, and moments. Students are expected to compute probabilities, cumulative distribution functions, densities, and expected values.
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fX (t) =
1 if 0 < t < 1
0 else
Define Y
def = X 3 .
(a) 10 points Compute P
1 5
(b) 15 points Compute the cumulative distribution FY of Y
(c) 15 points Compute the density fY of Y , if it exists. If the density does not exist, explain why.
(d) 10 points Compute E[Y ].
(a) 10 points What percentage of 25-year old men weigh more than 165 pounds?
(b) 10 points What percentage of 25-year old men over 165 pounds are less than 180 pounds?
fX (t) =
a + bx^3 if 0 < x < 1
0 else
If E[X] = 3 5 , compute^ a^ and^ b.
Answers
1 5
3 ≤ 1 5
1 5
t=−∞
fY (t)dt = (1/5) 1 / 3 .
(b)
FY (t) = P {Y ≤ t} = P
3 ≤ t
X ≤ t 1 / 3
∫ (^) t 1 / 3
s=−∞
fY (s)ds
0 if t 1 / 3 < 0
t^1 /^3 if 0 ≤ t^1 /^3 < 1
1 if t^1 /^3 ≥ 1
0 if t < 0
t^1 /^3 if 0 ≤ t < 1
1 if t ≥ 1
(c)
fY (t) = F ′ Y (t) =
1 3 t
− 2 / 3 if 0 < t < 1
0 else
(d)
3 ] =
t=−∞
t
3 fX (t)dt =
t=
t
3 dt =
or equivalently
t=−∞
tfY (t)dt =
t=
t
t − 2 / 3
dt =
t=
t 1 / 3 dt =
(a)
P{X ≥ 165 } = P{ 5 ξ + 170 ≥ 165 } = P{ξ ≥ − 1 } = P{−ξ ≥ − 1 }
= P{ξ ≤ 1 } = 0. 8413
(b)
We calculate that
We then compute that
P{X ≤ 180 } = P{ 5 ξ + 170 ≤ 180 } = P{ξ ≤ 2 } = 0. 9772.