Understanding Reaction Rates & Half-Lives in Second Order Kinetics, Study notes of Law

The concept of second order kinetics, focusing on the time-dependence of a second order reaction, the integrated rate law, and the relationship between initial concentrations and half-life. It also covers specific examples of SN2 reactions and their rate laws, as well as the significance of the NO-O2 reaction.

Typology: Study notes

2021/2022

Uploaded on 09/27/2022

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Second order kinetics
A second order reaction in component A has a
time-dependence given by
d[A]/dt = -k[A]2
The integrated rate law is given by
d[Α]
[Α]2
[Α]0
[Α]
= k dt
0
t
or 1
]1
]0= kt
This can be expressed as [A] = [A]0/(1 + [A]0kt)
pf3
pf4
pf5
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Second order kinetics

A second order reaction in component A has a time-dependence given by d[A]/dt = -k[A] 2 The integrated rate law is given by

d[Α]

[Α]

2 [Α] 0 [Α]

= k dt

0 t

or

[Α]

[Α]

0

= kt

This can be expressed as [A] = [A] 0 /(1 + [A] 0 kt)

Second order kinetics:

the half life

The half life, τ 1/ occurs when [A]= [A] 0 /

[Α]

0

[Α]

0

= kτ

1 / 2

1 / 2

k[Α]

0 For a second order process, the half life depends on the initial concentration [A] 0 .

Integrated rate law for second

order reaction A + B → P

The time course for the appearance of product is given the integrated rate law: Note that the half-life for a second order process depends on the initial concentration of A and B.

[ P ] =

[ A ]

0

[ B ]

0 1 – exp{([ B ] 0

– [ A ]

0 ) kt } [ A ] 0

– [ B ]

0 exp{([ B ] 0

– [ A ]

0 ) kt }

S

N

2 reactions

The net effect of a S N 2 reaction is that a leaving group is displaced by an attacking group (nucleophile). The process is inherently second order since the nucleophile must collide with the substrate in the rate-limiting step (labeled as slow above).

S

N

1 reactions

Bimolecular reaction example

The reaction of NO with O 2

  • (superoxide anion) is an example of a second order reaction with a great biological significance. The reaction is: The bimolecular rate constant has been determined to be k = 6.7 x 10 9 L mol

s

. The reaction is important since the ratio of is a crucial indicator of health. If this ratio is > 4 an individual is healthy. As this ratio falls to < 1 it indicates poor health.