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In order to integrate with respect to x , we can't have x's in the limits. So, to reverse the order, it is best to first sketch the region. Notice first that ...
Typology: Exercises
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Section 5.4 - Changing the Order of Integration
Problem 1. Evaluate the integral by first reversing the order of integration,
∫^ x=
x=
∫^ y=
y=x^2
x
3 e
y^3 dy dx.
Solution. Even if we tried to integrate with respect to y first, we cannot do it. We can’t just
switch either. In order to integrate with respect to x , we can’t have x’s in the limits. So,
to reverse the order, it is best to first sketch the region. Notice first that our region has two
properties:
0 ≤ x ≤ 3 x
2 ≤ y ≤ 9.
We then can draw the region:
Since we want to integrate with respect to x first, we will need limits for x as functions of y
and we need constant bounds for y. Looking at the picture, we get
0 ≤ y ≤ 9 0 ≤ x ≤
y.
With this information, we can now set up our new integral and hopefully be able to solve it!
∫^ x=
x=
∫^ y=
y=x^2
x
3 e
y^3 dy dx =
∫^ y=
y=
x=
√ y ∫
x=
x
3 e
y^3 dx dy
∫^ y=
y=
x
4 e
y^3
x=
√ y
x=
dy
∫^ y=
y=
y
2 e
y^3 dy
e
y^3
y=
y=
e
729 − 1
Problem 2. Evaluate the integral by first reversing the order of integration,
∫^ y=
y=
∫^ x=
x= 3
√ y
x^4 + 1 dx dy.
Solution. The region is described by the following two inequalities:
0 ≤ y ≤ 8 3
y ≤ x ≤ 2.
We sketch the region and get the picture
Now we can find our new inequalities and we get that
0 ≤ x ≤ 2 0 ≤ y ≤ x
3 .
With this information, we can now set up our new integral and evaluate:
∫^ y=
y=
x∫=
x= 3
√ y
x^4 + 1 dx dy =
∫^ x=
x=
y ∫=x^3
y=
(x
4
1 (^2) dy dx
∫^ x=
x=
y(x
4
y=x^3
y=
dx
∫^ x=
x=
x
3 (x
4
1 (^2) dx
3 (^2) − 1