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This is the Quiz Solution of Linear Algebra. Mainly this Course includes Zero Vector, Linearly Dependent, Statement, Vector, Linear Combination, Expressed, Trivial Solution, Inspection, Dependent, Theorem etc. Key important points of his quiz are: Section, Row Operations, Invertible, Column Vectors, Information, Condition, Entries, Problem, Augmented Matrix, Corresponding
Typology: Exercises
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QUIZ 5
NAME: Section:(Circle one) A(1 : 10) B(2 : 40)
Show ALL your work CAREFULLY.
(a) Suppose det
a b c d e f g h i
(^) = 3. Find det
a d g 2 b 2 e 2 h c f i
det
a d g 2 b 2 e 2 h c f i
(^) = 2 · det
a d g b e h c f i
(^) = 2 · det
a d g b e h c f i
T = 2 · det
a b c d e f g h i
(b) Use row operations to find det A where
A =
1 a b + c 1 b a + c 1 c a + b
Is A invertible? First note that if a = b or a = c then A will have two identical rows and thus is row equivalent to a matrix that has a row of zeros. In such cases, det A = 0 and A is not invertible. Now, assume that a 6 = b and a 6 = c. Then we have
A ∼
1 a b + c 0 b − a a − b 1 c a + b
1 a b + c 0 b − a a − b 0 c − a a − c
1 a b + c 0 1 − 1 0 c − a a − c
1 a b + c 0 1 − 1 0 1 − 1
1 a b + c 0 1 − 1 0 0 0
It follows that det A = 0 and hence A is not invertible.
Date: February 13, 2013. 1