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Problems related to determining the centroid, moment of inertia (ix and iy), and maximum shear stress (fv) for various beams made of sawn timber and steel. The document also includes calculations for the radius of gyration (rx and ry). Students can check their answers with partial solutions provided and use the negative area method to find section properties.
Typology: Exercises
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the top flange of the W18x50 and a 3 ½ x 3 x 3/8 angle is attached with the long leg up at the lower left as shown. Determine the location of the centroid, and the Ix and Iy about the major centroidal axes using the cross-sectional properties given in the steel tables for standard rolled shapes (see Appendix).
Problems: from Onouye, Chapters 7 & 9 Notes: Problems marked with a * have been altered with respect to the problem stated in the text. Multiframe4D or other methods may be used for V & M diagrams and maximums.
Partial answers to check with: xˆ = -0.0805 in, yˆ= 11.99 in and must be calculated using the table , Ix = 1578.8 in.^4 , Iy = 393.1 in.^4 ,,rx = 7.40 in, ry = 3.69 in
(flexural and shear stress)
sawn timber
2.4 k/ft
A992 steel (Fb = 33 ksi).
steel
*The load is changed to 2.4 k/ft and the depth is not restricted. Also find the maximum shear stress, fv****. Assume A992 steel (FY = 50 ksi, Fb = 33 ksi).
*The load is changed to 180 lb/ft. Assume Douglas fir- larch No. 2 ( Fb = 1450 psi). Also find the maximum shear stress, f v.
(flexural and shear stress)
180 lb/ft
L3 ½ x 3 x 3/
*Also calculate the radius of gyration, rx and ry.
(centroid and moment of inertia)
Partial answers to check with: y ˆ = 3.07 in from bottom, Ix = 112.6 in.^4 , fb = 27.6 ksi, fv-max = 1.37 ksi, (Qna = 17.6 in^3 ), fv-joint =1.20 ksi (Q = 15.44 in^3 ).
Partial answers to check with: y ˆ = 6.71 in, Ix = 496.2 in.^4 , fb = 1168 psi, fv = 195 psi (Q = 53.8 in^3 ), p =5.3 in. (Q = 31.3 in^3 ) Note: The negative area method is quicker for finding Ix. There are beam diagram and formula equations for V and M in a text example in Chapter 8.
Use the negative area to find the section properties. Also determine the required pitch spacing for the bottom 2x with 1 nail each side (2) with a shear capacity of 300 lb.
(section properties, flexural and shear stress)
(section properties, flexural and shear stress)