Signal Plot-Advanced Unified Engineering-Assignment Solution, Exercises of Aeronautical Engineering

This is solution to assignment of Basic Unified Engineering course. It was submitted to Prof. Yasaar Verma at Jiwaji University. It includes: Signal, Plot, Gaussian, Duration, Bandwidth, Product, Integral, Evaluated, Limit, Shape

Typology: Exercises

2011/2012

Uploaded on 07/22/2012

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Unified Engineering II Spring 2004
Problem S21 (Signals and Systems)
Solution:
1. The signal is plotted below:
-10 -8 -6 -4 -2 0 2 4 6 8 10
0
0.2
0.4
0.6
0.8
1
1.2
Time, t
g(t)
The signal is very smooth, almost like a Gaussian. Therefore, I expect that the
duration bandwidth product will be close to the theoretical lower bound.
2. 2
Δtt2g2(t)dt
2 g2(t)dt
The two integrals are easily evaluated for the given g(t). The result is
7
2 2
t g (t)dt = 2
5
2
g (t)dt = 2
Therefore,
7
Δt = 2 5
3. The time domain formula for the bandwidth is
2
Δωg˙2(t)dt
2 g2(t)dt
The numerator integral is 1
g˙2(t)dt = 2
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Unified Engineering II Spring 2004

Problem S21 (Signals and Systems)

Solution:

  1. The signal is plotted below:

-10 -8 -6 -4 -2 0 2 4 6 8 10 0

1

Time, t

g(t)

The signal is very smooth, almost like a Gaussian. Therefore, I expect that the duration bandwidth product will be close to the theoretical lower bound.

Δt t^2 g^2 (t) dt

2 g^2 (t) dt

The two integrals are easily evaluated for the given g(t). The result is

t g (t) dt = 2

g (t) dt = 2

Therefore, (^) � 7 Δt = 2 5

  1. The time domain formula for the bandwidth is � � 2 � Δω g˙ (^2) (t) dt

2 g^2 (t) dt

The numerator integral is 1 g˙ 2 (t) dt = 2

Therefore, 2 Δω = √ 5

  1. The durationbandwidth product is

Δt Δω = ≈ 2. 1166 5

which is very close to the theoretical lower limit of 2. This is not surprising, since the shape of g(t) is close to a gaussian.